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A bass guitar string is 89 cm long with a fundamental frequency of \(30 \mathrm{Hz}\). What is the wave speed on this string?

Short Answer

Expert verified
The wave speed on this string is 53.4 m/s.

Step by step solution

01

Identify the given values

The length of the string \(L\) is given as 89 cm and the fundamental frequency \(f\) is given as 30 Hz.
02

Find the wavelength

For a string that is fixed at both ends, the wavelength \(\lambda\) of the fundamental frequency (also known as the first harmonic) is twice the length of the string. Therefore, we calculate \(\lambda = 2L = 2 \times 89 \, cm = 178 \, cm = 1.78 \, m\). We convert the length into meters because the standard unit of wavelength is meters.
03

Calculate the speed of the wave

Now we have the frequency and the wavelength, we substitute those into the formula for the speed of a wave: \(v = f \cdot \lambda = 30 \, Hz \times 1.78 \, m = 53.4 \, m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fundamental Frequency
Imagine gently plucking a bass guitar string and hearing the lowest pitch that the string can produce; this is what we call the fundamental frequency . It's the musical tone produced by the string when it vibrates at its simplest possible form, essentially at its most basic state. It's significant because the fundamental frequency sets the precedent for all other harmonics , which are higher pitched tones that resonate at multiples of the fundamental.

When you're working with a string instrument like a bass guitar, this fundamental frequency is determined by various factors, including string length, tension, and density. In the case of our exercise, the given fundamental frequency is 30 Hz, which means the string vibrates 30 times every second when playing this most basic tone. Understanding this concept is crucial when you start diving into the world of acoustics and string instruments.
Wavelength Calculation
When it comes to wave speed on a string, knowing how to calculate the wavelength is crucial. The wavelength is the distance between consecutive points of the wave in one cycle, or simply put, it's the length of one complete wave. Interestingly, for a string fixed at both ends—like a guitar or bass string—the wavelength of the fundamental frequency is twice the length of the string itself, because the two fixed points serve as nodes where the wave doesn't move.

In our example, where the string measures 89 cm, the wavelength for the fundamental is calculated as 178 cm, or 1.78 meters when we need it in standard units. Being familiar with this calculation is useful not just for solving textbook exercises, but also for understanding the physical properties of musical instruments and sound waves.
Harmonics
Now let's explore the concept of harmonics . While the fundamental frequency gives the basic note, harmonics, or overtones , are the additional frequencies that the string can generate and are integral to the rich sound we associate with stringed instruments. These harmonics are actually whole number multiples of the fundamental frequency. If the fundamental frequency is like the first 'layer' of a sound, harmonics are the subsequent layers that add complexity and richness.

For example, if a string's fundamental frequency is 30 Hz, the second harmonic would be 60 Hz, the third would be 90 Hz, and so on. Each harmonic frequency has its own wavelength and mode of vibration on the string, and understanding these can lead to a deeper appreciation and technical grasp of how musical instruments work. In the context of our problem-solving, grasping the relationship between the fundamental frequency and the harmonics aids in a comprehensive understanding of wave behavior on strings.

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Most popular questions from this chapter

Although the vocal tract is quite complicated, we can make a simple model of it as an open-closed tube extending from the opening of the mouth to the diaphragm, the large muscle separating the abdomen and the chest cavity. What is the length of this tube if its fundamental frequency equals a typical speech frequency of \(200 \mathrm{Hz}\) ? Assume a sound speed of \(350 \mathrm{m} / \mathrm{s}\). Does this result for the tube length seem reasonable, based on observations on your own body?

Musicians can use beats to tune their instruments. One flute is properly tuned and plays the musical note A at exactly \(440 \mathrm{Hz}\). A second player sounds the same note and hears that her instrument is slightly "flat" (that is, at too low a frequency). Playing at the same time as the first flute, she hears two loud-soft-loud beats per second. What is the frequency of her instrument?

Two loudspeakers, \(4.0 \mathrm{m}\) apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved \(0.25 \mathrm{m}\). a. What is the frequency of the sound? b. If the frequency is then increased while you remain \(0.25 \mathrm{m}\) from the center, what is the first frequency for which that location will be a maximum of sound intensity?

A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of \(39.1 \mathrm{cm} .\) The room is slightly warm, so the speed of sound is \(344 \mathrm{m} / \mathrm{s}\). If the string's linear density is \(0.600 \mathrm{g} / \mathrm{m}\) and the tension is \(150 \mathrm{N},\) how long is the vibrating section of the violin string?

A drainage pipe running under a freeway is \(30.0 \mathrm{m}\) long. Both ends of the pipe are open, and wind blowing across one end causes the air inside to vibrate. a. If the speed of sound on a particular day is \(340 \mathrm{m} / \mathrm{s},\) what will be the fundamental frequency of air vibration in this pipe? b. What is the frequency of the lowest harmonic that would be audible to the human ear? c. What will happen to the frequency in the later afternoon as the air begins to cool?

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