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A speaker at an open-air concert emits 600 W of sound power, radiated equally in all directions. a. What is the intensity of the sound 5.0 m from the speaker? b. What sound intensity level would you experience there if you did not have any protection for your ears? c. Earplugs you can buy in the drugstore have a noise reduction rating of 23 decibels. If you are wearing those earplugs but your friend Phil is not, how far from the speaker should Phil stand to experience the same loudness as you?

Short Answer

Expert verified
a. The sound intensity 5.0 m from the speaker is 0.955 W/m虏. b. The sound intensity level at that distance is 120 dB. c. Phil needs to stand 18.7 m away from the speaker to experience the same loudness as if wearing the earplugs.

Step by step solution

01

Calculate the sound intensity 5.0 m from the speaker

Use the formula for sound intensity I = P / (4蟺r虏), where P = 600 W and r = 5.0 m. This gives I = 600 W / (4蟺(5 m)虏) = 0.955 W / m虏.
02

Calculate the sound intensity level

The sound intensity level in decibels can be found using the formula dB = 10 log(I / I鈧). For the given intensity I = 0.955 W/m虏 and I鈧 = 10鈦宦孤 W/m虏, this gives dB = 10 log(0.955 W/m虏 / 10鈦宦孤 W/m虏) = 120 dB
03

Calculate the distance for the same loudness with earplugs

If earplugs reduce the sound level by 23 dB, the sound intensity level with earplugs will be 120 dB - 23 dB = 97 dB. We can find the intensity I corresponding to this level using the formula I = I鈧 * 10^(dB/10), which gives I = 10鈦宦孤 W/m虏 * 10^(97/10) = 0.0224 W/m虏. Then we can find distance r from the speaker using the formula for sound intensity I = P / (4蟺r虏). Solving for r gives r = sqrt(P / (4蟺I)), which gives r = sqrt(600 W / (4蟺 * 0.0224 W / m虏)) = 18.7 m. Phil needs to stand 18.7 m away from the speaker to experience the same loudness as if wearing the earplugs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Power
Sound power is the total energy that a sound source emits as sound waves per unit of time. It is measured in watts (W). In the context of the open-air concert, the speaker is emitting 600 watts of sound power. This means the speaker is transferring 600 joules of energy per second into the surrounding air as sound waves. It's an intrinsic property of the source itself, unlike sound intensity, which depends on your distance from the source. Whether you are 5 meters away or 50 meters, the power remains 600 W because it radiates uniformly in all directions. This uniform radiation is often why you see the "4蟺r虏" in the intensity formula 鈥 a mathematical expression for the surface area of a sphere, illustrating how sound spreads out.
Decibel Scale
The decibel scale is a logarithmic scale used to quantify sound intensity levels, making it easier to manage large ranges of sound levels. Our ears can detect both very faint and very loud sounds, and the decibel scale helps us measure them with more human-friendly numbers. The formula used is \( dB = 10 \log_{10} ( \frac{I}{I_0} ) \), where \( I \) is the sound intensity and \( I_0 \) is the reference intensity level, usually \( 10^{-12} \text{W/m}^2 \), the faintest sound a typical human ear can detect. At the 5-meter point in the concert, the sound intensity level is calculated to be 120 dB. This number shows that it's very loud and potentially damaging to our hearing over prolonged exposure.
Noise Reduction
Noise reduction refers to decreasing unwanted sound using barriers, distance, or devices like earplugs. In the exercise, earplugs are used which have a noise reduction rating (NRR) of 23 dB. This means they can reduce the loudness of a sound that reaches your ear by 23 dB. If you are standing at a point where the sound intensity level is 120 dB without protection, wearing earplugs will reduce it to 97 dB, making it much safer for your ears. However, this reduction doesn't change the actual sound power emitted by the source; it only affects your perception by reducing what enters your ears.
Open-Air Concert
An open-air concert presents unique challenges for sound management because sound radiates in all directions without any walls or ceilings to contain it. In such settings, understanding sound power, intensity, and how sound diminishes over distance is crucial for everyone involved, from the sound engineers to the audience. The open-air environment facilitates a natural decrease in sound intensity as distance increases, following the inverse square law. This means as you move further from the source, the sound intensity decreases rapidly, resulting in a quieter experience. This is why, without earplugs, Phil should stand 18.7 meters away to perceive the loudness equivalent to what you experience wearing earplugs at 5 meters.

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