/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 104 Homes are often insulated with f... [FREE SOLUTION] | 91Ó°ÊÓ

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Homes are often insulated with fiberglass insulation in their walls and ceiling. The thermal conductivity of fiberglass is \(0.040 \mathrm{W} / \mathrm{m} \cdot \mathrm{K} .\) Suppose that the total surface area of the walls and roof of a windowless house is \(370 \mathrm{m}^{2}\) and that the thickness of the insulation is \(10 \mathrm{cm}\). At what rate does heat leave the house on a day when the outside temperature is \(30^{\circ} \mathrm{C}\) colder than the inside temperature?

Short Answer

Expert verified
The rate at which heat leaves the house is 44400 W, or equivalently 44.4 kW.

Step by step solution

01

Identify the right formula for heat transfer

The formula used for calculating the rate at which heat energy is transferred through a material is given by \( q = k \cdot A \cdot \Delta T / d \), where:- \( q \) is the heat transfer rate,- \( k \) is the thermal conductivity,- \( A \) is the surface area,- \( \Delta T \) is the temperature difference,- \( d \) is the thickness of the material.
02

Substitute the given values into the formula

We can fill in the values given in the problem into the formula:- \( k = 0.040 \, \mathrm{W/m \cdot K} \),- \( A = 370 \, \mathrm{m}^{2} \),- \( \Delta T = 30 \, \mathrm{K} \) (Note: The difference in temperature in Kelvin and Celsius is the same),- \( d = 10 \, \mathrm{cm} = 0.10 \, \mathrm{m} (We need to convert this from cm to m because the other parameters are in the SI system which uses meters).So the formula with the given values substituted in looks like this: \( q = 0.040 \, \mathrm{W/m \cdot K} \cdot 370 \, \mathrm{m}^{2} \cdot 30 \, \mathrm{K} / 0.10 \, \mathrm{m} \).
03

Calculate the heat transfer rate

Performing the multiplication and division in the formula gives the heat transfer rate: \( q = 44400 \, \mathrm{W} \), or equivalently, \( 44.4 \, \mathrm{kW} (since 1 \, \mathrm{kW} = 1000 \, \mathrm{W} \)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer Rate
Heat transfer rate is a fundamental concept in thermodynamics. It tells us how fast heat is flowing through a material. This is particularly important for understanding how well insulation works in buildings, such as houses. Heat transfer rate is measured in watts (W), symbolized as \( q \), and it helps us calculate the efficiency of thermal insulation.

The formula for heat transfer rate in a material is:
  • \( q = k \cdot A \cdot \Delta T / d \)
Here:
  • \( k \): Thermal conductivity of the material (in \( \mathrm{W/m \cdot K} \))
  • \( A \): Surface area through which heat is being transferred (in \( \mathrm{m}^{2} \))
  • \( \Delta T \): Temperature difference between the two sides of the material (in K)
  • \( d \): Thickness of the material (in meters)
Understanding the rate of heat transfer helps in determining energy costs and optimizing insulation for maintaining desired indoor temperatures without excessive heating or cooling.
Fiberglass Insulation
Fiberglass insulation is a common material used to reduce heat transfer in buildings. It serves as a barrier that slows the flow of heat between the inside and the outside of a house. This is key to keeping homes warm during winter and cool during summer.

One important property of fiberglass insulation is its thermal conductivity, \( k \). For fiberglass, this is typically around \( 0.040 \mathrm{W/m \cdot K} \). A low thermal conductivity means that the material is effective at insulating, allowing for less heat to pass through.
Fiberglass is chosen for its:
  • Effectiveness in reducing heat flow due to low thermal conductivity
  • Relatively low cost compared to other insulation types
  • Ease of installation and availability in various forms, such as batts or rolls
Using fiberglass improves energy efficiency, reduces utility bills, and enhances overall comfort in a home.
Temperature Difference Formula
The temperature difference, \( \Delta T \), is a crucial part of calculating heat transfer. It is simply the difference in temperature between one side of a barrier and the other. For our scenario, if the outside day temperature is \( 30^{\circ} \mathrm{C} \) colder than the inside, then \( \Delta T = 30 \mathrm{K} \).

Remember, the units of Kelvin (K) and Celsius (°C) can be interchangeably used when determining a temperature difference. This is because a change of one °C equals a change of one K.
The temperature difference affects how much heat can flow through a material:
  • Bigger differences mean more heat flows, increasing energy transfer rates.
  • Smaller differences lead to reduced heat flow, making insulation more effective.
Understanding \( \Delta T \) is vital for designing efficient heating or cooling systems and selecting appropriate insulation materials.

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