/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Driving on asphalt roads entails... [FREE SOLUTION] | 91Ó°ÊÓ

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Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resistance. But driving slowly in dry sand is another story. If a \(1500 \mathrm{kg}\) car is driven in sand at \(5.0 \mathrm{m} / \mathrm{s},\) the coefficient of rolling friction is \(0.06 .\) In this case, nearly all of the energy that the car uses to move goes to overcoming rolling friction, so you can ignore air drag in this problem. a. What propulsion force is needed to keep the car moving forward at a constant speed? b. What power is required for propulsion at \(5.0 \mathrm{m} / \mathrm{s} ?\) c. If the car gets 15 mpg when driving on sand, what is the car's efficiency? One gallon of gasoline contains \(1.4 \times 10^{8} \mathrm{J}\) of chemical energy.

Short Answer

Expert verified
a. The propulsion force needed to keep the car moving forward at a constant speed is 882N. b. The power required for propulsion at 5.0 m/s is 4410 W. c. The car's efficiency, with 15 mpg when driving on sand, where one gallon of gasoline contains \(1.4 \times 10^{8} J\) can be calculated using the aforementioned formula and will be a unitless ratio.

Step by step solution

01

Calculate the force of rolling friction

According to Newton's second law, the force of rolling friction can be calculated using the equation \(f = \mu * m * g\) where \(f\) is the frictional force, \(\mu\) is the coefficient of rolling friction, \(m\) is the mass of the car, and \(g\) is the acceleration due to gravity(9.8 m/s^2). In our case, \(\mu = 0.06, m = 1500 kg, g = 9.8 m/s^2\). Plugging these values into the equation gives the frictional force \(f = 0.06 * 1500 * 9.8 = 882 N\)
02

Calculate the work done against friction

The work done to overcome the friction and keep the car moving at a constant speed is equal to the frictional force. Thus, the propulsion force needed is 882 N.
03

Calculate the power required for propulsion

The power (P) needed can be calculated using the equation \(P = f * v\) where \(v\) is the velocity of the car. Since \(f = 882 N\) and the car's velocity \(v = 5.0 m/s\), plugging these values into the equation gives the power required as \(P = 5.0 m/s * 882 N = 4410 Watts\)
04

Calculate the energy used per gallon of gas

If a 1500 kg car gets 15 miles per gallon, that means it will travel 15 miles or 24159 meters for every gallon of gasoline which contains \(1.4 * 10^{8} J\)
05

Calculate the car's efficiency

The energy efficiency of the car can be calculated as the ratio of useful work output to total energy input. The work output (W_out) can be calculated by multiplying the frictional force (882N) by the distance traveled (24159 meters per gallon). The total energy input (E_in) is given as \(1.4 * 10^{8} J\). The car's efficiency can be calculated as \( Efficiency = \frac{W_out}{E_in} = \frac{882N * 24159 m}{1.4 *10^8 J}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficients of Rolling Friction
When a vehicle moves over a surface, it encounters a resistance known as rolling friction. This is essential in vehicles, from bicycles to cars, as it directly affects their motion and energy consumption. The coefficient of rolling friction, represented by the symbol \(\mu_r\), measures the resistance a wheel faces when rolling over a surface. Think of it as a numerical value that describes how 'sticky' or 'slippery' the interface between the tire and the road is.

The value of \(\mu_r\) varies with materials, surface texture and deformability, tire composition, and even the temperature. For example, tires rolling on dry asphalt will have a lower \(\mu_r\) compared to those on sand, indicating less resistance and hence, a smoother and more energy-efficient ride. The coefficient of rolling friction plays a pivotal role when calculating the force necessary for propulsion and hence impacts the energy calculations associated with vehicular motion.
Calculating Work Done
In physics, work is defined as the force applied to an object multiplied by the distance the object moves while being subject to that force. Specifically, when we talk about the work done against rolling friction, we are considering the effort needed to maintain a car's motion against the resistance provided by the rolling friction. To calculate this work, we use the equation \( W = f \times d \), where \( W \) is the work done, \( f \) is the force of rolling friction, and \( d \) is the distance traveled.

The force of rolling friction itself is determined by multiplying the coefficient of rolling friction by the mass of the vehicle and the gravitational acceleration (\( f = \mu_r \times m \times g \) ). In automotive terms, this work translates to the energy used in maintaining the constant speed of the car, overcoming the resistance provided by the terrain—a critical figure in energy consumption and vehicle performance analyses.
Power Required for Propulsion
Power, in the context of vehicles, refers to the rate at which work is done or energy is converted or used. When discussing the power required for propulsion, we are referring to how quickly a car can convert fuel into motion, overcoming resistive forces like rolling friction. The equation to calculate the power required for propulsion is \( P = f \times v \), where \( P \) stands for power, \( f \) is the force necessary to overcome rolling friction, and \( v \) is the velocity of the vehicle.

Moreover, understanding the power requirements helps engineers design engines and energy systems that are efficient for different driving conditions. It is a guiding factor for the necessary output and helps predict fuel consumption under varying operational conditions. As we've seen in the example, even at a modest speed, a significant amount of power can be needed to propel a vehicle through resistant terrain like sand.
Energy Efficiency
Energy efficiency in vehicles is a measure of how well they convert the energy stored in fuel into mechanical work—specifically, forward motion. It’s a ratio of the useful work performed to the total energy expended, which tells us how much of the input energy is wasted and how much is effectively used for propulsion.

High efficiency means most of the fuel's energy goes towards moving the car, whereas low efficiency indicates significant energy loss. Energy losses occur due to a variety of factors, including aerodynamic drag, mechanical losses in the drivetrain, and rolling friction. The latter can be especially prominent when driving on resistive surfaces like sand. Understanding and improving a vehicle’s energy efficiency is critical as we move toward a more energy-conscious society, making it essential to optimize fuel use and reduce greenhouse gas emissions.

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Most popular questions from this chapter

An individual white LED (light-emitting diode) has an efficiency of \(20 \%\) and uses \(1.0 \mathrm{W}\) of electric power. How many LEDs must be combined into one light source to give a total of \(1.6 \mathrm{W}\) of visible-light output (comparable to the light output of a \(40 \mathrm{W}\) incandescent bulb)? What total power is necessary to run this LED light source?

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