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91Ó°ÊÓ

How much energy can be stored in a spring with a spring constant of \(500 \mathrm{N} / \mathrm{m}\) if its maximum possible stretch is \(20 \mathrm{cm} ?\)

Short Answer

Expert verified
The energy stored in the spring is 10 Joules.

Step by step solution

01

Identify given values

From the problem, \n\nSpring constant, \(k = 500 N/m\) \n\nMaximum stretch, \(x = 20 cm = 0.2 m\) (should be converted to millimeters to match the units of the spring constant)
02

Substitute the values into the energy formula

The energy stored in the spring can be calculated by substituting the given values into the formula. \[U = \frac{1}{2} kx^2\] \[U = \frac{1}{2} * 500 N/m * (0.2 m)^2\]
03

Solve for U

Multiplying out these values, the energy \(U\) stored in the spring is \(U = 10 Joules\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Spring Constant
The spring constant, also known as the force constant, is a crucial part of understanding how springs work. It is denoted by the symbol \(k\). This constant gives us an idea of how stiff or flexible a spring is. The higher the value of \(k\), the stiffer the spring. Conversely, a lower value of \(k\) indicates a more flexible spring. In our example, the spring's constant is \(500 \mathrm{N/m}\), showing that it requires 500 newtons of force to stretch the spring by a meter. This value remains constant regardless of the force applied, until the spring deforms or breaks. It's vital to always check the units of the spring constant to ensure calculations are consistent. Common units are \(\mathrm{N/m}\), ensuring all measurements match when you compute other spring-related values.
The Energy Formula for Springs
The energy stored in a spring is determined using a specific energy formula. This formula is given by \(U = \frac{1}{2}kx^2\), where \(U\) represents the potential energy stored in the spring, \(k\) is the spring constant, and \(x\) is the displacement or stretch of the spring from its equilibrium position. Understanding each component of the formula is essential:
  • \(\frac{1}{2}\): This fraction accounts for the nature of transferring kinetic energy into potential energy in the spring.
  • \(k\): Spring constant, indicating spring stiffness, discussed in detail above.
  • \(x^2\): The stretch squared signifies that energy increases significantly with more stretch.
Applying these values correctly, as in the original step-by-step solution shows how energy is stored in a spring. In the given problem, by substituting \(k = 500 \mathrm{N/m}\) and \(x = 0.2 \mathrm{m}\) into the formula, we find \(U = 10 \mathrm{Joules}\). This calculation illustrates how the spring stores energy as it stretches.
Maximum Stretch of a Spring
Maximum stretch refers to the greatest extent a spring can be elongated under force while still returning to its original shape. Beyond this, the spring won't obey Hooke's Law and might become damaged. In our exercise, the spring's maximum stretch is given as \(20 \mathrm{cm}\), which is \(0.2 \mathrm{m}\). This is the distance the spring can stretch when subjected to maximum force before potentially getting deformed. Understanding maximum stretch is vital for calculating the potential energy stored. It ensures that our calculations remain physically accurate and within the safe operating limits of the spring. This concept helps determine not only physical limitations of the spring but also its design and application in practical scenarios.

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Most popular questions from this chapter

The elastic energy stored in your tendons can contribute up to \(35 \%\) of your energy needs when running. Sports scientists have studied the change in length of the knee extensor tendon in sprinters and nonathletes. They find (on average) that the sprinters' tendons stretch \(41 \mathrm{mm},\) while nonathletes' stretch only 33 mm. The spring constant for the tendon is the same for both groups, \(33 \mathrm{N} / \mathrm{mm} .\) What is the difference in maximum stored energy between the sprinters and the nonathletes?

When a tennis ball bounces from a racket, the ball loses approximately \(30 \%\) of its kinetic energy to thermal energy. A ball that hits a racket at a speed of \(10 \mathrm{m} / \mathrm{s}\) will rebound with approximately what speed? A. \(8.5 \mathrm{m} / \mathrm{s}\) B. \(7.0 \mathrm{m} / \mathrm{s}\) C. \(4.5 \mathrm{m} / \mathrm{s}\) D. \(3.0 \mathrm{m} / \mathrm{s}\)

A boy reaches out of a window and tosses a ball straight up with a speed of \(10 \mathrm{m} / \mathrm{s}\). The ball is \(20 \mathrm{m}\) above the ground as he releases it. Use conservation of energy to find a. The ball's maximum height above the ground. b. The ball's speed as it passes the window on its way down. c. The speed of impact on the ground.

A school has installed a modestly-sized wind turbine. The three blades are \(4.6 \mathrm{m}\) long; each blade has a mass of \(45 \mathrm{kg}\). You can assume that the blades are uniform along their lengths. When the blades spin at 240 rpm, what is the kinetic energy of the blade assembly?

An elevator weighing \(2500 \mathrm{N}\) ascends at a constant speed of \(8.0 \mathrm{m} / \mathrm{s} .\) How much power must the motor supply to do this?

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