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A fielder tosses a 0.15 kg baseball at \(32 \mathrm{m} / \mathrm{s}\) at a \(30^{\circ}\) angle to the horizontal. What is the ball's kinetic energy at the start of its motion? What is the kinetic energy at the highest point of its arc?

Short Answer

Expert verified
The kinetic energy of the baseball at the start of its motion and at its highest point is \(76.8 \, \mathrm {J}\).

Step by step solution

01

Calculate the initial kinetic energy

Using the kinetic energy formula \( KE = \frac {1}{2} m v^2 \), we plug in the given values: mass \( m = 0.15 \, \mathrm {kg} \) and velocity \( v = 32 \, \mathrm {m/s} \). So, \( KE = \frac {1}{2} \times 0.15 \, \mathrm {kg} \times (32 \, \mathrm {m/s})^2 \).
02

Calculation

Calculating \( KE = \frac {1}{2} \times 0.15 \, \mathrm {kg} \times (32 \, \mathrm {m/s})^2 \) gives us \( KE = 76.8 \, \mathrm {J} \).
03

Kinetic energy at highest point

As per the conservation of mechanical energy concept, if we neglect air resistance, the total energy (here, kinetic energy as there is no change in elevation hence no potential energy) of the baseball remains the same throughout its journey. Thus, the kinetic energy at the highest point of the arc is also \(76.8 \, \mathrm {J}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
The concept of conservation of energy is pivotal in understanding physical phenomena such as the motion of objects, including projectiles. In essence, it states that the total energy of an isolated system remains constant if there are no external forces, like friction, acting on it. In most cases concerning simple mechanical systems, energy transformations occur primarily between kinetic energy and potential energy.

When considering a projectile, like a baseball being tossed into the air, we often look at how kinetic and potential energy exchange as the projectile ascends and then descends. Initially, the baseball's energy is purely kinetic, as it moves with an initial velocity. As it rises, some of this kinetic energy converts into gravitational potential energy (though this aspect isn't observed in the given exercise due to no change in potential energy).

  • Kinetic Energy: Related to motion, calculated as \( KE = \frac{1}{2} mv^2 \).
  • Potential Energy: Related to position, calculated as \( PE = mgh \) (not applicable here since height isn't considered).
Thus, despite the changes in kinetic and potential energy during its journey, the total mechanical energy remains constant, reinforcing the conservation of energy principle.
Motion in Physics
Motion in physics broadly involves changes in the position of an object over time, covering aspects such as speed, velocity, acceleration, and forces acting upon an object. Understanding motion is crucial for analyzing and predicting the behavior of moving objects, whether they are on a microscopic scale or in considerable everyday motions like a baseball toss.

When we say an object is in motion, we describe not just the change in its position but also how fast it's moving (speed) and in what direction (velocity).

  • Speed: The magnitude of velocity, often measured in meters per second (m/s).
  • Velocity: A vector quantity, meaning it has both magnitude and direction.
  • Acceleration: The rate of change of velocity over time.
In the problem at hand, the baseball's trajectory is an example of motion, where understanding its velocity and acceleration due to gravity helps us calculate its behavior over time as it travels through the air under the influence of Earth's gravitational pull.
Projectile Motion
Projectile motion refers to the curved path an object follows when it is thrown or propelled near the surface of the Earth, under the influence of gravity, and without any propulsion of its own. This motion can be analyzed separately in terms of its horizontal and vertical components.

In the case of a baseball being thrown at an angle, like in the given problem, the motion can be decomposed into two components:

  • Horizontal Motion: Constant velocity because there's typically no acceleration acting horizontally (assuming no air resistance).
  • Vertical Motion: Influenced by acceleration due to gravity, causing the object to slow down, stop momentarily at the peak, and accelerate downwards thereafter.
Understanding projectile motion requires analyzing these two components independently to predict the object's path. Importantly, at the highest point in the arc of a projectile's trajectory, the vertical component of its velocity is zero, reducing the kinetic energy to solely depend on the horizontal component.

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Most popular questions from this chapter

A 60 kg runner in a sprint moves at 11 m/s. A 60 kg cheetah in a sprint moves at \(33 \mathrm{m} / \mathrm{s} .\) By what factor does the kinetic energy of the cheetah exceed that of the human runner?

A typical meteor that hits the earth's upper atmosphere has a mass of only 2.5 g, about the same as a penny, but it is moving at an impressive 40 \(\mathrm{km} / \mathrm{s} .\) As the meteor slows, the resulting thermal energy makes a glowing streak across the sky, a shooting star. The small mass packs a surprising punch. At what speed would a \(900 \mathrm{kg}\) compact car need to move to have the same kinetic energy?

A \(20 \mathrm{kg}\) child slides down a \(3.0-\mathrm{m}\) -high playground slide. She starts from rest, and her speed at the bottom is \(2.0 \mathrm{m} / \mathrm{s}\). a. What energy transfers and transformations occur during the slide? b. What is the total change in the thermal energy of the slide and the seat of her pants?

A cyclist is coasting at \(12 \mathrm{m} / \mathrm{s}\) when she starts down a \(450-\mathrm{m}-\mathrm{long}\) slope that is \(30 \mathrm{m}\) high. The cyclist and her bicycle have a combined mass of \(70 \mathrm{kg}\). A steady \(12 \mathrm{N}\) drag force due to air resistance acts on her as she coasts all the way to the bottom. What is her speed at the bottom of the slope?

The elastic energy stored in your tendons can contribute up to \(35 \%\) of your energy needs when running. Sports scientists have studied the change in length of the knee extensor tendon in sprinters and nonathletes. They find (on average) that the sprinters' tendons stretch \(41 \mathrm{mm},\) while nonathletes' stretch only 33 mm. The spring constant for the tendon is the same for both groups, \(33 \mathrm{N} / \mathrm{mm} .\) What is the difference in maximum stored energy between the sprinters and the nonathletes?

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