Chapter 8: Problem 25
. A \(\mathrm{A} 5.00\) g bullet is fired horizontally into a 1.20 \(\mathrm{kg}\) wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is \(0.20 .\) The bullet remains embedded in the block, which is observed to slide 0.230 \(\mathrm{m}\) along the surface before stopping. What was the initial speed of the bullet?
Short Answer
Step by step solution
Understand the Problem
Determine the System's Final Velocity
Use Work-Energy Principle for Sliding
Calculate Frictional Work
Set Initial Kinetic Energy Equal to Work Done by Friction
Calculate Initial Velocity of Bullet-Block System
Use Conservation of Momentum for Bullet and Block System
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kinetic Energy
- Its mass (\[m\]) - the more massive the object, the more kinetic energy it possesses.
- Its velocity (\[v\]) - the faster the object moves, the more kinetic energy it has.
Work-Energy Principle
- The bullet embeds itself into the block, giving the system a certain amount of kinetic energy as it starts sliding across the surface.
- As the bullet-block system slides, the kinetic friction force does work on it, gradually reducing its kinetic energy until it comes to a rest.
Friction
- Static friction, which prevents objects from starting to move.
- Kinetic friction, which acts on objects that are already moving.
- The coefficient of friction \((\mu)\), which is a measure of how "grippy" the surfaces are with respect to each other.
- The normal force, which is the perpendicular contact force exerted by a surface, often slightly affected by the mass of the object.