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\(\bullet\) \(\bullet\) A loaded 375 kg toboggan is traveling on smooth hori- zontal snow at 4.5 \(\mathrm{m} / \mathrm{s}\) when it suddenly comes to a rough region. The region is 7.0 \(\mathrm{m}\) long and reduces the tobogan's speed by 1.5 \(\mathrm{m} / \mathrm{s}\) . (a) What average friction force did the rough region exert on the toboggan? (b) By what percent did the rough region reduce the toboggan's (i) kinetic energy and (ii) speed?

Short Answer

Expert verified
(a) Average friction force: \(-362.946\, \text{N}\); (b) Kinetic energy reduced by 60.0\%, speed reduced by 33.3\%.

Step by step solution

01

Identify the Known Values

The initial velocity of the toboggan is given as \( v_i = 4.5 \, \text{m/s} \) and the final velocity is \( v_f = 4.5 \, \text{m/s} - 1.5 \, \text{m/s} = 3.0 \, \text{m/s} \). The mass of the toboggan is \( m = 375 \) kg, and the distance over the rough region is \( d = 7.0 \, \text{m} \).
02

Set Up the Equation for Work Done by Friction

The work done by friction is equal to the change in kinetic energy, which can be expressed as:\[W = \Delta KE = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2\]We are solving for the work done by friction \( W \).
03

Calculate the Change in Kinetic Energy

Substitute the known values into the kinetic energy equation:\[\Delta KE = \frac{1}{2} \cdot 375 \cdot (3.0)^2 - \frac{1}{2} \cdot 375 \cdot (4.5)^2\]Calculate this to find \( \Delta KE = \frac{1}{2} \cdot 375 \cdot 9 - \frac{1}{2} \cdot 375 \cdot 20.25 = 1687.5 - 4228.125 = -2540.625 \, \text{J} \).
04

Relate Work to Friction Force

The work done by friction can also be expressed as \( W = f_{avg} \cdot d \), where \( f_{avg} \) is the average friction force. Rearrange to solve for \( f_{avg} \):\[f_{avg} = \frac{W}{d} \]Substitute \( W = -2540.625 \, \text{J} \) and \( d = 7.0 \, \text{m} \) into the equation:\[f_{avg} = \frac{-2540.625}{7} = -362.946 \, \text{N}\]
05

Find Percentage Change in Kinetic Energy

To find the percentage change in kinetic energy:\[\text{Percentage change in KE} = \frac{\Delta KE}{\text{Initial KE}} \times 100\%\]The initial kinetic energy \( KE_i = \frac{1}{2} \cdot 375 \cdot 4.5^2 = 4228.125 \, \text{J} \), so:\[\text{Percentage change in KE} = \frac{-2540.625}{4228.125} \times 100\% \approx -60.0\%\]
06

Find Percentage Change in Speed

To find the percentage change in speed:\[\text{Percentage change in speed} = \frac{\text{change in speed}}{\text{initial speed}} \times 100\% = \frac{4.5 - 3.0}{4.5} \times 100\% = \frac{1.5}{4.5} \times 100\%\]Calculate this to find the percentage change in speed is approximately \( 33.3\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a type of energy that an object possesses due to its motion. The formula for kinetic energy (KE ) is given as \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass of the object and \( v \) is its velocity. This means that any object that is moving has kinetic energy, and how much it has depends on its mass and speed.

In our toboggan example, we initially observe it traveling with a speed of 4.5 m/s, indicating that it possesses kinetic energy. As the speed changes, so does the kinetic energy. When the toboggan hits a rough patch, its speed decreases, resulting in a reduction in kinetic energy.
  • An object's kinetic energy is dependent on both its mass and velocity.
  • A change in speed significantly impacts kinetic energy as it is proportional to the square of the velocity.
  • The greater the reduction in velocity, the more the kinetic energy will decrease.
This relationship shows us how motion and energy are interconnected, helping us predict changes in energy when speed changes.
Speed Reduction
Speed reduction occurs when an object slows down due to forces acting on it, such as friction. In our example, the toboggan's speed reduces from 4.5 m/s to 3.0 m/s when it hits a rough surface. The extent to which the speed decreases can be calculated in terms of percentages for better understanding.

This decrease in speed doesn't just affect its motion; it also affects its kinetic energy, as we've calculated before. The percentage change in speed is calculated using the difference in initial and final speeds relative to the initial speed, expressed in percentage terms.
  • Changes in speed directly impact motion and kinetic energy.
  • Speed reduction is often due to external forces such as friction or drag.
  • Calculating the percentage change provides insights into how much an object's motion is altered.
Understanding speed reduction helps explain how objects slow down and the effects it has on their energy.
Work-Energy Principle
The work-energy principle is a key concept in physics that relates the work done on an object to its change in kinetic energy. According to this principle, the work done by all external forces acting on an object equals the change in its kinetic energy.

In the toboggan scenario, the work done by friction is the force exerted over the distance of the rough patch. We calculated this by finding the difference in kinetic energy before and after passing the rough surface. The work-energy principle shows us why the toboggan slowed down: friction performed negative work, reducing its energy.
  • Work is done when a force is applied over a distance, and it can either add to or take away energy from an object.
  • Negative work is done when the force opposes the direction of motion, such as friction slowing down the toboggan.
  • The principle helps us understand energy transfer between objects and their environments.
This principle is essential in analyzing and predicting how forces affect an object's motion and energy changes.
Physics Problem Solving
Solving physics problems involves understanding underlying physical principles and applying them systematically. In our toboggan exercise, solving the problem required a series of logical steps starting with known quantities and expressions.

The process involved identifying initial conditions, using the kinetic energy formula, and applying the work-energy principle to deduce the average friction force. By carefully plugging in values and performing calculations, we determined numerical answers that explain how the forces and motion interactions play out.
  • The first step is to gather and understand all given data and quantities.
  • Apply relevant physical laws, like the conservation of energy, to form equations.
  • Solve these equations step-by-step, ensuring accuracy in calculations.
  • Check results for reasonableness based on physical intuition.
A systematic approach not only solves specific problems but also builds a deeper understanding of physical concepts.

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Most popular questions from this chapter

\(\bullet\) \(\bullet\) \(\bullet\) Automotive power. A truck engine transmits 28.0 \(\mathrm{kW}\) \((37.5 \mathrm{hp})\) to the driving wheels when the truck is traveling at a constant velocity of magnitude 60.0 \(\mathrm{km} / \mathrm{h}(37.7 \mathrm{mi} / \mathrm{h})\) on a level road. (a) What is the resisting force acting on the on a level road. (a) What is the resisting force acting on the truck? (b) Assume that 65\(\%\) of the resisting force is due to rolling friction and the remainder is due to air resistance. If the force of rolling friction is independent of speed, and the force of air resistance is proportional to the square of the speed, what power will drive the truck at 30.0 \(\mathrm{km} / \mathrm{h} ?\) At 120.0 \(\mathrm{km} / \mathrm{h} ?\) Give your answers in kilowatts and in horse- power.

\(\bullet\) \(\bullet\) At 7.35 cents per kilowatt-hour, (a) what does it cost to operate a 10.0 hp motor for 8.00 hr? (b) What does it cost to leave a 75 W light burning 24 hours a day?

\(\bullet\) \(\bullet\) \(\bullet\) A ball is thrown upward with an initial velocity of 15 \(\mathrm{m} / \mathrm{s}\) at an angle of \(60.0^{\circ}\) above the horizontal. Use energy conservation to find the ball's greatest height above the ground.

\(\bullet\) \(\bullet\) Ski jump ramp. You are designing a ski jump ramp for the next Winter Olympics. You need to calculate the vertical height \(h\) from the starting gate to the bottom of the ramp. The skiers push off hard with their ski poles at the start, just above the starting gate, so they typically have a speed of 2.0 \(\mathrm{m} / \mathrm{s}\) as they reach the gate. For safety, the skiers should have a speed of no more than 30.0 \(\mathrm{m} / \mathrm{s}\) when they reach the bottom of the ramp. You determine that for a 85.0 -kg skier with good form, friction and air resistance will do total work of magnitude 4000 J on him during his run down the slope. What is the max- imum height \(h\) for which the maximum safe speed will not be exceeded?

\(\bullet\) (a) How many joules of energy does a 100 watt lightbulb use every hour? (b) How fast would a 70 kg person have to run to have that amount of kinetic energy? Is it possible for a per- son to run that fast? (c) How high a tree would a 70 kg person have to climb to increase his gravitational potential energy rela- tive to the ground by that amount? Are there any trees that tall?

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