/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 What is the acceleration of a ra... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the acceleration of a raindrop that has reached half of its terminal velocity? Give your answer in terms of \(g .\)

Short Answer

Expert verified
The acceleration is \( \frac{1}{2}g \).

Step by step solution

01

Understanding Terminal Velocity

Terminal velocity is the constant speed that a freely falling object eventually reaches when the resistance of the medium prevents further acceleration. At terminal velocity, the force of gravity is balanced by the drag force.
02

Set Up the Forces Equations

When the raindrop is not at terminal velocity, the forces are: gravitational force \[ F_g = mg \] and drag force \( F_d \). At half terminal velocity, drag force is \( F_d = rac{1}{2} imes \text{drag force at terminal velocity} \).
03

Apply Newton's Second Law

Newton's second law tells us the net force is equal to mass times acceleration: \[ F_{net} = ma \]. The net force with half terminal velocity is given by: \[ F_{net} = mg - F_d \] where \( F_d = rac{1}{2} imes mg \).
04

Calculate the Acceleration

Substitute the forces into the net force equation: \[ ma = mg - rac{1}{2}mg \]. Simplifying: \[ ma = rac{1}{2}mg \]. Thus, \[ a = rac{1}{2}g \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Terminal Velocity
Terminal velocity is a key concept in understanding the motion of objects through a fluid, like air or water. When an object falls through a fluid, it accelerates due to gravity. However, as its speed increases, so does the drag force opposing its motion. Eventually, these two forces balance each other out.

This balance between gravitational force and drag force means the object stops accelerating and moves at a constant speed—this is its terminal velocity. Terminal velocity depends on a variety of factors, including:
  • Object's mass.
  • Surface area.
  • Shape of the object.
  • Density of the fluid through which it falls.
Understanding terminal velocity helps us comprehend why raindrops don't continue to increase in speed indefinitely as they fall from the sky.
Drag Force
Drag force is the resistance force caused by the movement through a fluid. In the context of a falling object, it's the air pushing against the object as it moves downward. Drag force increases with velocity, meaning the faster something moves through a fluid, the greater the drag force it experiences.

Drag force is influenced by several factors:
  • Velocity of the object: The faster the object, the greater the drag.
  • Cross-sectional area: Larger areas experience more drag.
  • Shape: Streamlined shapes reduce drag.
  • Density of the fluid: Thicker fluids cause more drag.
It can be represented mathematically by the equation:\[ F_d = \frac{1}{2} \times \rho \times v^2 \times C_d \times A \]where \( \rho \) is the fluid density, \( v \) is the velocity, \( C_d \) is the drag coefficient and \( A \) is the cross-sectional area. Understanding drag force is crucial for calculating the forces at play when not at terminal velocity.
Gravitational Force
Gravitational force is a fundamental force that attracts any two objects with mass. It is the force that causes objects to fall towards Earth when dropped. For objects on or near the Earth's surface, gravitational force can be calculated as:\[ F_g = mg \]where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity, approximately \( 9.8 \, \text{m/s}^2 \) on Earth.

Gravitational force plays a major role when an object is in free fall and when it reaches terminal velocity.
  • At the beginning of a fall, it is the dominant force causing acceleration.
  • As speed increases, drag force starts to counteract gravitational force.
Understanding this force is essential for analyzing motion and interactions between objects in physics.
Acceleration
Acceleration is the rate at which an object changes its velocity. In physics, it is a vector quantity, having both magnitude and direction. When a raindrop or any object falls, it initially accelerates due to gravitational force. However, as drag force builds and ultimately balances with gravitational force, acceleration can decrease and may stop entirely at terminal velocity.

Acceleration can be calculated using Newton's second law of motion:\[ F_{net} = ma \]Where \( a \) is the acceleration, \( m \) is the mass, and \( F_{net} \) is the net force acting on the object. In this scenario, for an object falling at half of its terminal velocity, the net force (and hence acceleration) is not zero, resulting in continued, but reduced, downward acceleration. Acceleration provides insights into how forces interact with motion, especially in changing conditions.
Freely Falling Object
A freely falling object is a body moving solely under the influence of gravitational force, without any additional forces like air resistance initially. In this idealized scenario, the only force acting on the object is gravity, giving it a constant acceleration equal to \( g \) (approximately \( 9.8 \, \text{m/s}^2 \) on Earth) as it falls.

However, in the real world, air resistance soon becomes a factor, transforming a freely falling object into one undergoing forces other than just gravity. The object will experience a decreasing downward acceleration until it stops accelerating and reaches terminal velocity.
  • Initial behavior is a direct result of gravitational pull.
  • Eventually reaches a point where drag force equals gravitational force.
This concept is commonly illustrated using objects like raindrops, falling leaves, or skydivers—demonstrating how various forces interact in real-world physics scenarios.

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Most popular questions from this chapter

\(\bullet$$\bullet \mathrm{A} 75,600 \mathrm{N}\) spaceship comes in for a vertical landing. From an initial speed of \(1.00 \mathrm{km} / \mathrm{s},\) it comes to rest in 2.00 \(\mathrm{min}\) . with uniform acceleration. (a) Make a free-body diagram of this ship as it is coming in. (b) What braking force must its rockets provide? Ignore air resistance.

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\(\bullet$$\bullet\) A man pushes on a piano of mass 180 \(\mathrm{kg}\) so that it slides at a constant velocity of 12.0 \(\mathrm{cm} / \mathrm{s}\) down a ramp that is inclined at \(11.0^{\circ}\) above the horizontal. No appreciable friction is acting on the piano. Calculate the magnitude and direction of this push (a) if the man pushes parallel to the incline, (b) if the man pushes the piano up the plane instead, also at 12.0 \(\mathrm{cm} / \mathrm{s}\) paral- lel to the incline, and (c) if the man pushes horizontally, but still with a speed of 12.0 \(\mathrm{cm} / \mathrm{s}\) .

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