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\(\bullet\) A canoe has a velocity of 0.40 \(\mathrm{m} / \mathrm{s}\) southeast relative to the earth. The canoe is on a river that is flowing 0.50 \(\mathrm{m} / \mathrm{s}\) east rela- tive to the earth. Find the velocity (magnitude and direction) of the canoe relative to the river.

Short Answer

Expert verified
The canoe's velocity relative to the river is 0.357 m/s at a direction of 52° southwest.

Step by step solution

01

Define the velocity vectors

Identify the given velocities: \( \vec{v}_{ce} = 0.40 \, \mathrm{m/s} \) southeast for the canoe relative to Earth and \( \vec{v}_{re} = 0.50 \, \mathrm{m/s} \) east for the river relative to Earth. Note that southeast implies a 45-degree angle from the east.
02

Convert canoe velocity into components

To determine the southeast velocity in terms of its components, break it into east and south components: \[\vec{v}_{ce_{east}} = 0.40 \cos(45°) \, \mathrm{m/s}, \, \vec{v}_{ce_{south}} = 0.40 \sin(45°) \, \mathrm{m/s}.\]Calculate these values: \( \vec{v}_{ce_{east}} = 0.40 \times 0.707 = 0.283 \mathrm{m/s} \) and \( \vec{v}_{ce_{south}} = 0.40 \times 0.707 = 0.283 \mathrm{m/s} \).
03

Compute canoe velocity relative to the river

Use the relative velocity formula: \[\vec{v}_{cr} = \vec{v}_{ce} - \vec{v}_{re}.\]In component form:\[\vec{v}_{cr_{east}} = \vec{v}_{ce_{east}} - \vec{v}_{re} = 0.283 - 0.50 = -0.217 \, \mathrm{m/s},\]\[\vec{v}_{cr_{south}} = \vec{v}_{ce_{south}} = 0.283 \, \mathrm{m/s}.\]
04

Calculate magnitude of the relative velocity

The magnitude of the velocity is given by: \[\|\vec{v}_{cr}\| = \sqrt{(\vec{v}_{cr_{east}})^2 + (\vec{v}_{cr_{south}})^2}\]Substitute the values: \[\|\vec{v}_{cr}\| = \sqrt{(-0.217)^2 + (0.283)^2} = \sqrt{0.0471 + 0.0801} = \sqrt{0.1272} = 0.357 \, \mathrm{m/s}.\]
05

Determine the direction of the relative velocity

The direction \( \theta \) is given by \[\theta = \tan^{-1}\left(\frac{\vec{v}_{cr_{south}}}{|\vec{v}_{cr_{east}}|}\right)= \tan^{-1} \left(\frac{0.283}{0.217}\right)\]This results in \[\theta = 52°.\] The direction is towards the southwest (since the east component is negative, indicating a net motion westward from the river's perspective).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Vectors
In physics, a velocity vector represents the speed and direction of an object's motion. It helps us understand movement through space. Velocity vectors are crucial because they combine both magnitude (how fast an object is moving) and direction (where the object is going).

For example, a canoe moving at a certain speed southeast relative to the Earth is described by its velocity vector. The vector gives us a clear picture of the canoe's path and allows us to make calculations about its motion relative to other objects, like the river in the exercise.

By setting up velocity vectors for each component of the scenario—such as the canoe's speed relative to Earth and the river's flow—students can piece together an overall picture of relative motion. Understanding these velocity vectors is the first step to tackling any relative velocity problem.
Vector Components
Breaking a velocity vector into components allows us to analyze motion in different directions, typically along the north-south and east-west coordinate axes. This is like peeling back layers to examine each directional movement separately.

For instance, when a vector describes a canoe heading southeast, it combines movement in both the south and east directions. Using trigonometry, particularly sine and cosine, we can separate this vector into its components:
  • The east component, calculated using the cosine function.
  • The south component, calculated with the sine function.
These components are essential because they allow us to perform calculations, like determining the effect of the river's current on the canoe.
Magnitude and Direction
Once we have the components, calculating the magnitude and direction of the resultant vector gives a complete picture of the object's motion.

The magnitude, often called the length of a vector, can be found using the Pythagorean theorem. This gives us a scalar value, representing the total speed relative to another object, which in this exercise is the river.

Determining the direction involves calculating the angle of the resultant vector. This often uses the arctangent function, illustrating the direction of motion relative to a reference axis. Understanding both magnitude and direction allows us to know how fast and in what specific direction the canoe is moving relative to the river.
Relative Motion
Relative motion is about understanding how an object's movement appears differently depending on the observer's point of reference.

In the exercise, we assessed how the canoe's movement relative to the Earth contrasts with its movement relative to the river. This illustrates that even if an object seems to be at rest or moving differently from another viewpoint, it's all about where you're observing from.

Using the formula for relative velocity, you subtract the observer's velocity (river) from the object's velocity (canoe) to find how it moves from the observer's frame. This kind of analysis is pivotal in everyday physics, helping us understand everything from how a car overtakes another on the highway, to how the currents affect a swimmer crossing a river.

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