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Use the electron configurations of Si and O to explain why these atoms combine chemically in a one-to-two ratio to form sand.

Short Answer

Expert verified
Si and O form SiO2 because Si shares its 4 electrons with 2 O atoms, each receiving 2 electrons to complete their octets.

Step by step solution

01

Identify Electron Configurations of Si and O

Silicon (Si) has an atomic number of 14. Its electron configuration is \([\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^2 \text{3p}^2]\). Oxygen (O) has an atomic number of 8, and its electron configuration is \([\text{1s}^2 \text{2s}^2 \text{2p}^4]\). These configurations show how electrons are arranged in atomic orbitals for these elements.
02

Determine Valence Electrons

The valence electrons are found in the outermost shell. For Si, the valence electrons are in the 3rd shell, with a configuration of \(3s^2 3p^2\), totaling 4 valence electrons. For O, the valence electrons are in the 2nd shell, with a configuration of \(2s^2 2p^4\), totaling 6 valence electrons.
03

Explain the Formation of Bonds

Atoms combine to complete their octets for a stable configuration. Oxygen needs 2 electrons to fill its outer shell and reach a stable \(2p^6\) configuration. Silicon can share its 4 valence electrons, allowing each oxygen atom to "take" 2 electrons per bond.
04

Explain the SiO2 Ratio

To satisfy the octet rule for both elements, two oxygen atoms chemically combine with one silicon atom. Each oxygen atom uses two electrons from silicon. This results in the compound \(\text{SiO}_2\), commonly known as sand.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration is like a map that shows where electrons live around an atom's nucleus. It tells us in which energy level or shell certain electrons can be found.
For example, if we look at silicon (Si), it has an atomic number of 14. This means it has 14 electrons, and its electron configuration is \[\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^2 \text{3p}^2\].

What does this mean? Let's break it down:
  • The first energy level, with shells "1s," is filled with 2 electrons.
  • The second energy level, containing "2s" and "2p" shells, holds 8 electrons.
  • The third level starts filling up with the "3s" and "3p" shells holding 4 electrons in total.
Oxygen (O), with an atomic number of 8, has an electron configuration of \[\text{1s}^2 \text{2s}^2 \text{2p}^4\]. This shows:
  • The first shell "1s" holds 2 electrons.
  • The second shell "2s" and "2p" holds 6 electrons total, almost filling it entirely.
This arrangement is crucial because it affects how atoms like Si and O interact with each other.
Valence Electrons
Valence electrons are the magic electrons that live in the outermost shell of an atom. They decide how atoms will bond with each other.
In silicon (Si), these valence electrons are the 4 electrons in the "3s" and "3p" orbitals.
These 4 valence electrons mean Si can form several bonds to achieve a stable structure.

For oxygen (O), with valence electrons located in the "2s" and "2p" orbitals, there are a total of 6:
  • 2 in the "2s" orbital
  • 4 in the "2p" orbital
These sets of electrons play a huge role when oxygen wants to bond because it needs 2 more electrons to fill its outer shell.

Understanding where these electrons reside helps explain why atoms join together, like pieces of a puzzle, to form compounds such as SiOâ‚‚.
Octet Rule
The octet rule is like a goal that atoms try to achieve to be happy and stable.
They aim to have 8 electrons in their outer shell, just like the noble gases, which are the happiest and most stable elements around.

Oxygen, for instance, has 6 valence electrons and thus needs 2 more to reach the perfect 8.
Silicon has 4 valence electrons. By sharing these, each oxygen atom can "borrow" 2 electrons from silicon, fulfilling their octet quest.

When these exchanges happen:
  • Each oxygen achieves its octet by getting 2 electrons.
  • Silicon satisfies the needs of 2 oxygens by sharing its 4 valence electrons.
This explains why they form a compound in a 1:2 ratio, resulting in SiOâ‚‚, where silicon "coordinates" with two oxygen atoms, completing their electronic destinies according to the octet rule.

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Most popular questions from this chapter

(a) Write out the ground-state electron configuration \(\left( 1 s ^ { 2 } 2 s ^ { 2 } ,\) etc. \right\()\) for the beryllium atom. (b) What element of next- larger \(Z\) has chemical properties similar to those of beryllium? (See Example \(29.3 .\) ) Give the ground-state electron con- figuration of this element. (c) Use the procedure of part (b) to predict what element of next-larger \(Z\) than in (b) will have chemical properties similar to those of the element you found in part (b), and give its ground-state electron configuration.

Consider an electron in hydrogen having total energy \(- 0.5440 \mathrm { eV } .\) (a) What are the possible values of its orbital angular momentum (in terms of \(\hbar\) ? (b) What wavelength of light would it take to excite this electron to the next higher shell? Is this photon visible to humans?

(a) Write out the electron configuration \(\left( 1 s ^ { 2 } 2 s ^ { 2 } ,\) etc. \right\()\) for Li and \(\mathrm { Na }\) . (b) How many electrons does each of these atoms have in its outer shell?

The maximum wavelength of light that a certain silicon photocell can detect is 1.11\(\mu \mathrm { m }\) . (a) What is the energy gap (in electron volts) between the valence and conduction bands for this photocell? (b) Explain why pure silicon is opaque. (Hint: Will visible light that strikes silicon be transmitted or absorbed?

(a) How many different 3\(d\) states does hydrogen have? Make a list showing all of them. (b) How many different 3f states does it have?

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