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Chapter 27: Problem 5

\(\bullet\) You take a trip to Pluto and back (round trip 11.5 billion km), traveling at a constant speed (except for the turnaround at Pluto) of \(45,000 \mathrm{km} / \mathrm{h}\) . (a) How long does the trip take, in hours, from the point of view of a friend on earth? About how many years is this? (b) When you return, what will be the difference between the time on your atomic wristwatch and the time on your friend's? (Hint: Assume the distance and speed are highly precise, and carry a lot of significant digits in your calculation!)

Short Answer

Expert verified
The trip takes about 29.17 years as seen from Earth. Time dilation effects are negligible.

Step by step solution

01

Calculate Total Distance

The total distance for the round trip to Pluto and back is given as 11.5 billion kilometers. This is equal to \(11.5 \times 10^9\) kilometers.
02

Determine Travel Speed

The speed of travel is given as \(45,000 \text{ km/h}\). This will be used to calculate the time taken for the trip.
03

Calculate Time Taken for Trip in Hours

Use the formula \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \) to find the time taken for the trip. Substitute the given values: \[ \text{Time} = \frac{11.5 \times 10^9 \text{ km}}{45,000 \text{ km/h}} \approx 2.55556 \times 10^5 \text{ hours}. \]
04

Convert Hours to Years

To convert the time from hours to years, divide the number of hours by the number of hours in a year (\(8760\) hours). So, \( \frac{2.55556 \times 10^5}{8760} \approx 29.17\) years.
05

Calculate Time Dilation Effect

The time dilation can be calculated using the formula \( \Delta t = t \sqrt{1 - \frac{v^2}{c^2}} \) for special relativity, where \(t\) is the time observed on Earth, \(v\) is velocity, and \(c\) is the speed of light (~\(3 \times 10^8 \text{ m/s}\)). Since \(v\ll c\), \( \Delta t \approx \frac{t v^2}{2 c^2} \). Plug in the values to find \( \Delta t \). However, because \(v\) is very small compared to \(c\), \( \Delta t \) is negligibly small here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a theory developed by Albert Einstein which revolutionizes our understanding of how space and time are intertwined.
  • At the heart of this theory is the premise that the laws of physics are the same for all observers, regardless of their velocities, as long as they are not accelerating.
  • Time dilation, a key aspect of special relativity, addresses how the time experienced by an observer in motion compared to one at rest differs.
  • This means that time can stretch or compress based on the relative speed of an observer.
In the context of the Pluto round trip, special relativity predicts that a clock on the spaceship would measure time differently than one on Earth. It highlights the fascinating consequences of traveling close to the speed of light. Even though the velocities in everyday space travel, like this trip, are much smaller than the speed of light, the concept underscores how space and time are interconnected.
Distance Calculation
Calculating distance is an essential step in understanding journeys like the trip to Pluto. At its core, distance calculation ensures you have an accurate figure for the total length of the journey.To find our total distance:
  • Take the round-trip distance to Pluto and back, given as 11.5 billion kilometers.
  • This can be expressed in scientific notation as \(11.5 \times 10^9\) kilometers.
This large number highlights the vastness of space and the challenges involved in interplanetary travel.Whether you're calculating for a flight on Earth or a trip to Pluto, understanding the distance helps in planning the time and fuel needed for the trip.
Speed of Light
The speed of light in a vacuum is a critical constant in physics, valued approximately at \(3 \times 10^8\) meters per second.
  • This speed is pivotal in special relativity and serves as a universal speed limit.
  • For any object, no matter the technology involved, exceeding this speed is impossible according to our current understanding of physics.
When considering space travel, as in the example of a trip to Pluto:- The speed of light sets a benchmark against which our spacecraft speeds are compared.- Even at top conventional speeds (like 45,000 kilometers per hour), we are moving much slower than light.This vast difference in speeds helps us understand why relativistic effects like time dilation are negligible for most space travel.
Velocity Comparison
In the context of traveling to Pluto, comparing velocities is essential for understanding motion and its implications.
  • The trip involves a constant travel speed of 45,000 km/h.
  • When compared to the speed of light, this velocity, though fast in earthly terms, is minuscule.
This comparison becomes critical in calculating time dilation effects:- The formula for time dilation uses the ratio \( \frac{v^2}{c^2} \).- Given our much smaller speed, the ratio becomes negligibly small.Therefore, although special relativity predicts time differences due to motion, the effects are extremely small for such speeds.Velocity comparison not only provides a scale but also offers insights into the limits and possibilities of human travel beyond our planet.

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Most popular questions from this chapter

\(\bullet\) By what minimum amount does the mass of 4.00 \(\mathrm{kg}\) of ice increase when the ice melts at \(0.0^{\circ} \mathrm{C}\) to form water at that same temperature? (The heat of fusion of water is \(3.34 \times 10^{5} \mathrm{J} / \mathrm{kg.} )\)

\(\cdot\) An enemy spaceship is moving toward your starfighter with a speed of \(0.400 c,\) as measured in your reference frame. The enemy ship fires a missile toward you at a speed of 0.700\(c\) relative to the enemy ship. (See Figure \(27.24 . )\) (a) What is the speed of the missile relative to you? Express your answer in terms of the speed of light. (b) If you measure the enemy ship to be \(8.00 \times 10^{6} \mathrm{km}\) away from you when the missile is fired, how much time, measured in your frame, will it take the missile to reach you?

A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an observer on Tatooine, the cruiser is traveling away from the planet with a speed of 0.600\(c .\) The pursuit ship is traveling at a speed of 0.800\(c\) relative to Tatooine, in the same direction as the cruiser. What is the speed of the cruiser relative to the pur- suit ship?

\(\bullet\) Particle annihilation. In proton-antiproton annihilation, a proton and an antiproton (a negatively charged particle with the mass of a proton) collide and disappear, producing electromagnetic radiation. If each particle has a mass of \(1.67 \times 10^{-27} \mathrm{kg}\) and they are at rest just before the annihilation, find the total energy of the radiation. Give your answers in joules and in electron volts.

\(\bullet\) The negative pion \(\left(\pi^{-}\right)\) is an unstable particle with an average lifetime of \(2.60 \times 10^{-8} \mathrm{s}\) (measured in the rest frame of the pion).(a) If the pion is made to travel at very high speed relative to a laboratory, its average lifetime is measured in the laboratory to be \(4.20 \times 10^{-7}\) s. Calculate the speed of the pion expressed as a fraction of \(c .\) (b) What distance, as measured in the laboratory, does the pion travel during its average lifetime?
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