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\(\bullet\) If a diffraction grating produces a third-order bright spot for red light (of wavelength 700 \(\mathrm{nm}\) ) at \(65.0^{\circ}\) from the central maximum, at what angle will the second-order bright spot be for violet light (of wavelength 400 \(\mathrm{nm} ) ?\)

Short Answer

Expert verified
The second-order bright spot for violet light is at approximately \(20.17^{\circ}\).

Step by step solution

01

Understand the Diffraction Grating Formula

The diffraction grating formula is given by \( d\sin(\theta) = m\lambda \), where \( d \) is the distance between adjacent slits of the grating, \( \theta \) is the angle at which the light is diffracted, \( m \) is the order of the bright spot, and \( \lambda \) is the wavelength of the light. We will use this formula to calculate the required angle.
02

Calculate the Grating Constant using Red Light

Given: the third-order bright spot (\( m = 3 \)) for red light (\( \lambda = 700\,\mathrm{nm} \)) is at \( \theta = 65.0^{\circ} \). We rearrange the diffraction equation to find \( d \): \[d = \frac{3 \times 700\,\mathrm{nm}}{\sin(65.0^{\circ})}\]
03

Calculate the Grating Constant

Plug in the values: \[d \approx \frac{2100}{0.906}\,\mathrm{nm} = 2317.22\,\mathrm{nm}\] This is the grating constant \( d \) between the slits for the diffraction grating.
04

Calculate the Angle for Violet Light

Now, use the grating constant \( d = 2317.22\,\mathrm{nm} \) for violet light (\( \lambda = 400\,\mathrm{nm} \)) for the second-order bright spot (\( m = 2 \)):\[2317.22\,\mathrm{nm} \sin(\theta) = 2 \times 400\,\mathrm{nm}\]Solving for \( \sin(\theta) \): \[\sin(\theta) = \frac{800}{2317.22}\]
05

Solve for the Angle \( \theta \)

Calculate \( \theta \):\[\sin(\theta) \approx 0.345\]Thus, \[\theta = \arcsin(0.345) \approx 20.17^{\circ}\]This is the angle for the second-order bright spot of violet light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Calculation
To understand how light behaves when passing through a diffraction grating, it's essential to know about wavelength calculation. Wavelength, denoted as \( \lambda \), is the distance between consecutive crests of a wave. In optics, it plays a crucial role in determining how light interacts with objects, such as diffraction gratings. When you know the wavelength of light, you can predict the pattern of light on the screen after it passes through the diffraction grating. In this exercise, we are given two different wavelengths. Red light with a wavelength of 700 nm and violet light with a wavelength of 400 nm. These two wavelengths will behave differently as they pass through the grating, creating specific bright spots at different angles. Understanding the relationship between wavelength and diffraction helps in the calculation of these angles.
Order of Bright Spots
In the context of diffraction, the term 'order of bright spots' refers to the sequence or number of the light pattern fringes observed on a screen. This is an important concept as it helps categorize the diffractions based on the angles at which they appear.- The "order", denoted as \( m \), is an integer value that signifies the position of the bright spot, starting from zero.- A "first-order" bright spot means the first visible diffraction pattern from the center. "Second-order" is the next one, and so on.In our specific problem, we are looking at the third-order spot for red light at an angle of \( 65.0^\circ \) and need to find the angle for the second-order spot for violet light. Understanding this order helps in calculating angles using the diffraction grating formula.
Angle of Diffraction
The angle of diffraction is the angle at which light waves are dispersed after passing through a diffraction grating. It is denoted by \( \theta \) and is crucial for determining where the bright spots will appear on the screen.Understanding this concept requires knowing the relationship between the angle of incidence and the path difference of light waves. The angle is calculated using the sine function in conjunction with the order of the spot and wavelength in the diffraction grating formula. For example, in the exercise, the angle for a third-order bright spot of 700 nm red light was given, and we calculated the angle at which the second-order bright spot for 400 nm violet light would appear. Each order or 'm' corresponds to a different angle, showing the unique path of each wavelength.
Diffraction Formula
The diffraction formula is a mathematical expression used to calculate the angles at which bright and dark bands appear after light passes through a grating. The formula is given by:\[d \sin(\theta) = m \lambda\]- \( d \) is the distance between slits in the grating.- \( \theta \) is the angle of diffraction.- \( m \) is the order of the bright spot.- \( \lambda \) is the wavelength of the light.Using this formula, we can derive the relationship between these various parameters. In our case, we started by finding \( d \) using known values from red light and then applied it to find the angle for violet light. This formula is fundamental in optics, allowing us to predict how various wavelengths will distribute themselves after passing through a grating.

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Most popular questions from this chapter

\(\bullet\) A person with a radio-wave receiver starts out equidistant from two FM radio transmitters \(A\) and \(B\) that are 11.0 \(\mathrm{m}\) apart, each one emitting in-phase radio waves at 92.0 \(\mathrm{MH} z\) . She then walks so that she always remains 50.0 \(\mathrm{m}\) from transmitter \(B\) . See Fig- ure \(26.48 .\) ) For what values of \(x\) will she find the radio signal to be (a) maximally enhanced, (b) can- celled? Limit your solution to the cases where \(x \geq 50.0 \mathrm{m.}\)

\(\bullet$$\bullet\) CDs and DVDs as diffraction gratings. A laser beam of wavelength \(\lambda=632.8 \mathrm{nm}\) shines at normal incidence on the reflective side of a compact disc. (a) The tracks of tiny pits in which information is coded onto the \(\mathrm{CD}\) are 1.60\(\mu \mathrm{m}\) apart. For what angles of reflection (measured from the normal) will the intensity of light be maximum? (b) On a DVD, the tracks are only 0.740\(\mu\) mm apart. Repeat the calculation of part (a) for the DVD.

\(\bullet\) Monochromatic \(x\) rays are incident on a crystal for which the spacing of the atomic planes is 0.440 nm. The first-order maximum in the Bragg reflection occurs when the incident and reflected rays make an angle of \(39.4^{\circ}\) with the crystal planes. What is the wavelength of the rays?

\(\bullet$$\bullet\) An oil tanker spills a large amount of oil \((n=1.45)\) into the sea \((n=1.33)\) . (a) If you look down onto the oil spill from overhead, what predominant wavelength of light do you see at a point where the oil is 380 nm thick? (b) In the water under the slick, what visible wavelength (as measured in air) is predominant in the transmitted light at the same place in the slick as in part (a)?

\(\bullet\) The walls of a soap bubble have about the same index of refraction as that of plain water, \(n=1.33 .\) There is air both inside and outside the bubble. (a) What wavelength (in air) of visible light is most strongly reflected from a point on a soap bubble where its wall is 290 \(\mathrm{nm}\) thick? To what color does this correspond ( see Figure 23.3\() ?\) (b) Repeat part (a) for a wall thickness of 340 \(\mathrm{nm}\) .

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