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\bullet A microscope with an objective of focal length 8.00 \(\mathrm{mm}\) and an eyepiece of focal length 7.50 \(\mathrm{cm}\) is used to project an image on a screen 2.00 \(\mathrm{m}\) from the eyepiece. Let the image distance of the objective be 18.0 \(\mathrm{cm} .\) (a) What is the lateral magnification of the image? (b) What is the distance between the objective and the eyepiece?

Short Answer

Expert verified
(a) Calculate total magnification using lens equations. (b) Sum objective image distance and modified eyepiece screen distance to find distances.

Step by step solution

01

Understanding the Problem

We are given a microscope with an objective lens and an eyepiece lens. The focal lengths of the lenses, the image distance from the objective, and the final image distance from the eyepiece are given. We need to determine the lateral magnification and the distance between the objective and the eyepiece.
02

Convert All Units to Meters

Convert the given focal lengths from millimeters and centimeters to meters: For the objective: 8.00 mm = 0.008 m For the eyepiece: 7.50 cm = 0.075 m The image distance of the objective is given as 18.0 cm, so convert it to meters: 18.0 cm = 0.18 m.
03

Calculate Objective Lens Magnification

The lateral magnification ( \(M_o\) ) of the objective lens can be calculated using the formula: \[M_o = \frac{-d_i}{d_o}\]Where \(d_i\) is the image distance (0.18 m), and \(d_o\) is the object distance. Calculate \(d_o\) using the lens formula: \[\frac{1}{f_o} = \frac{1}{d_o} + \frac{1}{d_i}\]Rearrange to find \(d_o\):\[d_o = \frac{1}{\frac{1}{f_o} - \frac{1}{d_i}} = \frac{1}{\frac{1}{0.008} - \frac{1}{0.18}}\]Calculate \(d_o\) and then substitute to find \(M_o\).
04

Determine Total Magnification

The total magnification of the microscope system ( \(M_{total}\) ) is the product of the magnifications by the objective and the eyepiece. The magnification by the eyepiece ( \(M_e\) ) when projecting an image is given by: \[M_e = \frac{s}{f_e}\]Where \(s\) is the distance from the eyepiece to the screen (2.00 m) and \(f_e\) is the focal length of the eyepiece (0.075 m). Calculate \(M_e\) and multiply by \(M_o\) to get \(M_{total}\).
05

Calculate Distance Between Lenses

The distance ( \(L\) ) between the objective and the eyepiece is:\[L = d_o + (s - f_e)\]This accounts for the distance where each lens forms its part of the image. Substitute the values for \(d_o\) and (s - f_e) to find \(L\).
06

Final Answers

(a) Using the calculations from the previous steps, determine \(M_{total}\) as the lateral magnification of the image.(b) Substitute appropriate values into the equation for \(L\), providing the final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lateral Magnification
Lateral magnification is an important concept when using microscopes. It helps us understand how much larger the image is compared to the object. This is crucial for anyone working in fields involving microscopes, such as biology and material sciences. In simple terms, lateral magnification (\(M\) ) is calculated using the ratio of the image distance (\(d_i\) ) to the object distance (\(d_o\) ).
  • Formula: \(M_o = \frac{-d_i}{d_o}\)
  • The negative sign indicates image inversion, a common outcome in optical systems.
Before calculating, ensure you have values for both \(d_i\) (image distance) and \(d_o\) (object distance). The higher the magnification, the larger the image appears compared to the object.
Lens Formula
The lens formula is fundamental to understanding optics, especially when working with microscopes. It relates the focal length (\(f\) ), image distance (\(d_i\) ), and object distance (\(d_o\) ) in a straightforward equation:\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\]The lens formula allows you to calculate any one of these variables if the other two are known. This makes it a versatile tool for determining how lenses will behave in specific setups. To find \(d_o\) or \(d_i\) , rearrange the equation accordingly:
  • For \(d_o\): \[d_o = \frac{1}{\frac{1}{f} - \frac{1}{d_i}}\]
  • For \(d_i\): \[d_i = \frac{1}{\frac{1}{f} - \frac{1}{d_o}}\]
Calculating these values precisely is important for optimizing microscope setup and achieving the desired magnification and clarity.
Focal Length Conversion
Converting focal lengths into consistent units is key to solving optical equations accurately. In optics, the focal length represents how strongly a lens converges or diverges light. When beginning any calculations, ensure that all measurements are in the same unit, typically meters or centimeters.

Here’s how conversions work:
  • Millimeters to meters: divide by 1000.
  • Centimeters to meters: divide by 100.
For example, converting a focal length of 8.00 mm to meters involves:\[8.00\, \text{mm} = 0.008\, \text{m}\]Converting correctly avoids errors and makes equations like the lens formula usable without conversion-related mistakes.
Distance Between Lenses
The distance between lenses in a microscope affects how images are formed and magnified. This measurement is crucial as it involves both the objective lens and the eyepiece lens. Understanding this distance helps in setting up the microscope for best performance. To find the distance \(L\) between the objective and eyepiece, you consider both object distance (\(d_o\)) and the projection distance (\(s - f_e\)).

The formula to calculate the distance is:\[L = d_o + (s - f_e)\]Here,
  • \(d_o\) is the distance from the objective lens to the object.
  • \(s\) is the distance from the eyepiece to where the image is projected.
  • \(f_e\) is the focal length of the eyepiece.
Properly calculating \(L\) ensures the compounded magnification from both lenses functions as intended, providing clear and enlarged images. This knowledge is fundamental for both amateur and professional microscope users.

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Most popular questions from this chapter

\(\bullet\) Galileo's telescopes, I. While Galileo did not invent the telescope, he was the first known person to use it astronomically, beginning around \(1609 .\) Five of his original lenses have survived (although he did work with others). Two of these have focal lengths of 1710 \(\mathrm{mm}\) and 980 \(\mathrm{mm}\) . (a) For greatest magnification, which of these two lenses should be the eye- piece and which the objective? How long would this telescope be between the two lenses? (b) What is the greatest angular magnification that Galileo could have obtained with these lenses? (Note: Galileo actually obtained magnifications up to about \(30 \times\) but by using a diverging lens as the eye- piece.) (c) The Moon subtends an angle of \(\frac{10}{2}\) when viewed with the naked eye. What angle would it subtend when viewed through this telescope (assuming that all of it could be seen)?

. A certain microscope is provided with objectives that have focal lengths of \(16 \mathrm{mm}, 4 \mathrm{mm}\) , and 1.9 \(\mathrm{mm}\) and with eye pieces that have angular magnifications of \(5 \times\) and \(10 \times\) Each objective forms an image 120 \(\mathrm{mm}\) beyond its second focal point. Determine (a) the largest overall angular magnification obtainable and (b) the smallest overall angular magnification obtainable.

\(\bullet\) (a) A small refracting telescope designed for individual use has an objective lens with a diameter of 6.00 \(\mathrm{cm}\) and a focal length of 1.325 \(\mathrm{m}\) . What is the \(f\) -number of this instrument? (b) The 200 -inch-diameter objective mirror of the Mt. Palomar telescope has an \(f\) -number of \(3.3 .\) Calculate its focal length. (c) The distance between lens and retina for a normal human eye is about 2.50 \(\mathrm{cm}\) , and the pupil can vary in size from 2.0 \(\mathrm{mm}\) to 8.0 \(\mathrm{mm}\) . What is the range of \(f\) -numbers for the human eye?

A thin planoconvex lens has a radius of curvature of magnitude 22.5 \(\mathrm{cm}\) on the curved side. When a color chart is placed 48.0 \(\mathrm{cm}\) from the lens, green light of wavelength 550 \(\mathrm{nm}\) is focused 277 \(\mathrm{cm}\) from the lens and blue light of wavelength 450 \(\mathrm{nm}\) is focused 17 \(\mathrm{I} \mathrm{cm}\) from the lens. What are the indices of refraction for these two wavelengths of light?

An insect 1.2 \(\mathrm{mm}\) tall is placed 1.0 \(\mathrm{mm}\) beyond the focal point of the objective lens of a compound microscope. The objective lens has a focal length of \(12 \mathrm{mm},\) the eyepiece a focal length of 25 \(\mathrm{mm}\) . (a) Where is the image formed by the objective lens and how tall is it? (b) If you want to place the eye-piece so that the image it produces is at infinity, how far should this lens be from the image produced by the objective lens? (c) Under the conditions of part (b), find the overall magnification of the microscope.

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