/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 \(\bullet$$\bullet\) A plane sin... [FREE SOLUTION] | 91Ó°ÊÓ

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\(\bullet$$\bullet\) A plane sinusoidal electromagnetic wave in air has a wave- length of 3.84 \(\mathrm{cm}\) and an \(\vec{\boldsymbol{E}}\) field amplitude of 1.35 \(\mathrm{V} / \mathrm{m}\) . (a) What is the frequency of the wave? (b) What is the \(\vec{\boldsymbol{B}}\) field amplitude? (c) What is the intensity? (d) What average force does this radiation exert perpendicular to its direction of propagation on a totally absorbing surface with area 0.240 \(\mathrm{m}^{2}\) ?

Short Answer

Expert verified
(a) 7.81 GHz, (b) 4.50 nT, (c) 2.42 W/m², (d) 0.581 N.

Step by step solution

01

Calculate Frequency

The frequency \( f \) of a wave is related to the speed of light \( c \) and its wavelength \( \lambda \) by the formula: \( f = \frac{c}{\lambda} \). The speed of light \( c \) is approximately \( 3 \times 10^8 \) m/s, and the given wavelength \( \lambda = 3.84 \times 10^{-2} \) m. Substituting these values, we find:\[ f = \frac{3 \times 10^8}{3.84 \times 10^{-2}} = 7.81 \times 10^9 \text{ Hz} \].
02

Calculate Magnetic Field Amplitude

The relationship between the electric field amplitude \( E \) and the magnetic field amplitude \( B \) is given by: \( c = \frac{E}{B} \). Rearrange it to find \( B \):\[ B = \frac{E}{c} = \frac{1.35}{3 \times 10^8} = 4.50 \times 10^{-9} \text{ T} \].
03

Calculate Intensity

The intensity \( I \) of an electromagnetic wave can be found using the formula: \( I = \frac{1}{2} \varepsilon_0 c E^2 \), where \( \varepsilon_0 = 8.85 \times 10^{-12} \text{ C}^2/\text{N}\cdot\text{m}^2 \) is the permittivity of free space. Substitute \( E = 1.35 \text{ V/m} \):\[ I = \frac{1}{2} (8.85 \times 10^{-12}) (3 \times 10^8) (1.35)^2 = 2.42 \text{ W/m}^2 \].
04

Calculate Average Force on Surface

The average force \( F \) exerted by radiation on a totally absorbing surface is related to intensity \( I \) and area \( A \) by the equation: \( F = I \times A = 2.42 \times 0.240 \). Calculating this gives:\[ F = 0.581 \text{ N} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Calculation
Frequency is an essential characteristic of any wave, including electromagnetic waves such as light or radio waves. To calculate the frequency of a wave, you can use its wavelength and the speed of light. The frequency \( f \) is calculated using the formula:

\[ f = \frac{c}{\lambda}\]where:
  • \( c \) is the speed of light, approximately \( 3 \times 10^8 \, \text{m/s} \)
  • \( \lambda \) is the wavelength of the wave in meters.
For an electromagnetic wave with a wavelength of 3.84 cm, first convert the wavelength to meters: \( 3.84 \, \text{cm} = 3.84 \times 10^{-2} \, \text{m} \). Taking these values and substituting them into the formula:

\[ f = \frac{3 \times 10^8}{3.84 \times 10^{-2}} = 7.81 \times 10^9 \, \text{Hz}\]This calculation shows that the frequency is about 7.81 GHz. Frequency tells us how many wave cycles pass a point per second.
Magnetic Field Amplitude
The amplitude of the magnetic field \( \vec{B} \) in an electromagnetic wave is directly related to the electric field amplitude \( \vec{E} \). The speed of light also plays a crucial role in this relationship, dictated by the equation:

\[ c = \frac{E}{B}\]Rearranging it gives:

\[ B = \frac{E}{c}\]Given that \( E = 1.35 \, \text{V/m} \) and \( c = 3 \times 10^8 \, \text{m/s} \), you substitute these into the equation to find \( B \):

\[ B = \frac{1.35}{3 \times 10^8} = 4.50 \times 10^{-9} \, \text{T}\]This tells us that the magnetic field amplitude is approximately \( 4.50 \times 10^{-9} \, \text{tesla} \). The amplitude of the magnetic field is significantly weaker than the electric field but is just as important in defining the wave's properties.
Wave Intensity
Wave intensity describes how much energy an electromagnetic wave carries per unit area per unit time. It is a measure of the strength or power of the wave as it travels. The intensity \( I \) can be calculated using:

\[ I = \frac{1}{2} \varepsilon_0 c E^2\]where:
  • \( \varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N}\cdot\text{m}^2 \) is the permittivity of free space
  • \( c \) is the speed of light
  • \( E \) is the electric field amplitude in volts per meter.
Substituting the known values, \( E = 1.35 \, \text{V/m} \), we compute:

\[ I = \frac{1}{2} (8.85 \times 10^{-12}) (3 \times 10^8) (1.35)^2 = 2.42 \, \text{W/m}^2\]This tells us that the wave's intensity is 2.42 watts per square meter. Intensity gives us insight into how much power the wave can transfer in an area over time.
Radiation Force
Radiation force is the average force exerted by an electromagnetic wave as it impinges on a surface. For a surface that fully absorbs the wave, this can be found by multiplying the wave's intensity by the area of the surface:

\[ F = I \times A\]where:
  • \( I \) is the intensity of the wave, calculated previously
  • \( A \) is the area of the surface in meters squared.
In this example, the area \( A \) is given as \( 0.240 \, \text{m}^2 \). Substitute these numbers into the formula:

\[ F = 2.42 \times 0.240 = 0.581 \, \text{N}\]This indicates that the electromagnetic wave exerts a force of \( 0.581 \, \text{newtons} \) on the absorbing surface. The concept of radiation force is useful in understanding how electromagnetic waves can transfer momentum to objects they interact with.

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Most popular questions from this chapter

\(\bullet\) Consider each of the electric- and magnetic-field orientations given next. In each case, what is the direction of propagation of the wave? (a) \(\vec{E}\) in the \(+x\) direction, \(\vec{B}\) in the \(+y\) direction. (b) \(\vec{E}\) in the \(-y\) direction, \(\vec{B}\) in the \(+x\) direction. (c) \(\vec{\boldsymbol{E}}\) in the \(+z\) direction, \(\vec{\boldsymbol{B}}\) in the \(-x\) direction. (d) \(\vec{\boldsymbol{E}}\) in the \(+y\) direction, \(\vec{\boldsymbol{B}}\) in the \(-z\) direction.

\(\bullet$$\bullet\) A small helium-neon laser emits red visible light with a power of 3.20 \(\mathrm{mW}\) in a beam that has a diameter of 2.50 \(\mathrm{mm}\) . (a) What are the amplitudes of the electric and magnetic fields of the light? (b) What are the average energy densities associated with the electric field and with the magnetic field? (c) What is the total energy contained in a 1.00 \(\mathrm{m}\) length of the beam?

\(\bullet$$\bullet\) A parallel-sided plate of glass having a refractive index of 1.60 is in contact with the surface of water in a tank. A ray coming from above makes an angle of incidence of \(32.0^{\circ}\) with the top surface of the glass. What angle does this ray make with the normal in the water?

\(\bullet$$\bullet\) A beam of unpolarized light in air is incident at an angle of \(54.5^{\circ}\) (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?

\(\bullet$$\bullet\) In a physics lab, light with wavelength 490 nm travels in air from a laser to a photocell in 17.0 ns. When a slab of glass 0.840 m thick is placed in the light beam, with the beam incident along the normal to the parallel faces of the slab, it takes the light 21.2 ns to travel from the laser to the photocell. What is the wavelength of the light in the glass?

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