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\(\bullet\) When a certain paramagnetic material is placed in an external magnetic field of 1.5000 \(\mathrm{T}\) , the field inside the material is measured to be 1.5023 \(\mathrm{T}\) . Find (a) the relative permeability and (b) the magnetic permeability of this material.

Short Answer

Expert verified
(a) The relative permeability is 1.00153. (b) The magnetic permeability is approximately \( 4.007 \times 10^{-7} \text{ T} ext{ m/A} \).

Step by step solution

01

Understanding the Problem

We have a paramagnetic material placed in an external magnetic field. The external magnetic field strength, \( B_0 \), is given as 1.5000 \( \mathrm{T} \), and the field inside the material, \( B \), is 1.5023 \( \mathrm{T} \). We need to find the relative permeability, \( \mu_r \), and the magnetic permeability, \( \mu \), of this material.
02

Formula for Relative Permeability

Relative permeability, \( \mu_r \), is calculated using the formula: \[ \mu_r = \frac{B}{B_0} \] where \( B \) is the magnetic field inside the material, and \( B_0 \) is the external magnetic field.
03

Calculate Relative Permeability

Substitute the given values into the formula: \[ \mu_r = \frac{1.5023}{1.5000} = 1.00153 \] Thus, the relative permeability of the material is 1.00153.
04

Formula for Magnetic Permeability

The magnetic permeability, \( \mu \), can be calculated using the formula: \[ \mu = \mu_0 \times \mu_r \] where \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \text{ T} ext{ m/A} \).
05

Calculate Magnetic Permeability

Using the calculated \( \mu_r \), find \( \mu \): \[ \mu = (4\pi \times 10^{-7} \text{ T} ext{ m/A}) \times 1.00153 \approx 4.007 \times 10^{-7} \text{ T} ext{ m/A} \] Thus, the magnetic permeability of the material is approximately \( 4.007 \times 10^{-7} \text{ T} ext{ m/A} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paramagnetic Material
Paramagnetic materials are substances that are weakly attracted by an external magnetic field. Unlike ferromagnetic materials, which retain magnetization, paramagnetic materials only exhibit magnetism in the presence of an external field. This is because the atomic magnetic moments in paramagnetic materials tend to align with the applied magnetic field, but the alignment is not strong enough to result in permanent magnetism. Instead, the magnetism disappears when the external field is removed.

Key characteristics of paramagnetic materials include:
  • They have unpaired electrons contributing to the net magnetic moment.
  • The magnetic susceptibility is positive but very small, indicating weak attraction.
  • The effect of temperature is significant; as temperature increases, the thermal agitation makes it harder for the magnetic dipoles to align.
Understanding these features helps explain why paramagnetic materials behave as they do in magnetic fields, offering insight into their practical applications in medical imaging and certain cooling technologies.
Relative Permeability
Relative permeability is a measure of how easily a material can become magnetized when exposed to an external magnetic field, compared to vacuum. It essentially measures the ratio of the magnetic field strength inside the material to the external magnetic field strength. Mathematically, it's given by:

\[ \mu_r = \frac{B}{B_0} \] where \( B \) is the magnetic field inside the material, and \( B_0 \) is the external magnetic field.

For paramagnetic materials, the relative permeability slightly exceeds 1.0, which means they are marginally better than a vacuum in terms of allowing a magnetic field to pass through. In the exercise, the relative permeability was calculated as 1.00153, indicating the paramagnetic behavior of the material with a very subtle enhancement of the magnetic field inside. This tiny enhancement is characteristic of the weak interplay between the material's atomic structure and the field.
Magnetic Field Strength
Magnetic field strength refers to the ability of a magnetic field to induce magnetism in materials or to exert a force on magnetic particles. It's usually symbolized by \( H \) and typically measured in amperes per meter (A/m). Magnetic field intensity varies based on the type of material and how it interacts with an external field. For paramagnetic materials, while the alignment of atomic magnetic moments increases slightly in response to \( H \), it does not persist after the external field is removed. This is what was observed in the exercise, where the material slightly enhanced the external magnetic field strength from 1.5000 T to 1.5023 T.

This concept helps us understand:
  • How the field's presence induces a magnetic effect in materials.
  • Why certain materials, like paramagnetic ones, don’t retain magnetic properties without external influence.
  • The fundamental role of field strength in determining material behavior in magnetic applications.
Comprehending these principles allows students to grasp material interactions with magnetic fields effectively, enhancing their practical knowledge in subjects spanning physics to engineering.

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Most popular questions from this chapter

\(\bullet\) A beam of protons traveling at 1.20 \(\mathrm{km} / \mathrm{s}\) enters a uniform magnetic field, traveling perpendicular to the field. The beam exits the magnetic field in a direction perpendicular to its original direction (Fig. \(20.60 ) .\) The beam travels a distance of 1.18 cm while in the field. What is the magnitude of the magnetic field?

\bullet A circular coil of 50 loops and diameter 20.0 \(\mathrm{cm}\) is lying flat on a tabletop, and carries a clockwise current of 2.50 A. A magnetic field of 0.450 \(\mathrm{T}\) , directed to the north and at an angle of \(45.0^{\circ}\) from the vertical down through the coil and into the tabletop is turned on. (a) What is the torque on the coil, and (b) which side of the coil (north or south) will tend to rise from the tabletop?

\bullet A 150 g ball containing \(4.00 \times 10^{8}\) excess electrons is dropped into a 125 vertical shaft. At the bottom of the shaft, the ball suddenly enters a uniform horizontal 0.250 T magnetic field directed from east to west. If air resistance is negligibly small, find the magnitude and direction of the force that this magnetic field exerts on the ball just as it enters the field.

\(\bullet\) (a) How large a current would a very long, straight wire have to carry so that the magnetic field 2.00 \(\mathrm{cm}\) from the wire is equal to 1.00 \(\mathrm{G}\) (comparable to the earth's northward-pointing magnetic field)? (b) If the wire is horizontal with the current running from east to west, at what locations would the magnetic field of the wire point in the same direction as the horizontal component of the earth's magnetic field? (c) Repeat part (b) except with the wire vertical and the current going upward.

\bullet Bubble chamber, I. Certain types of bubble chambers are filled with liquid hydrogen. When a particle (such as an electron or a proton) passes through the liquid, it leaves a track of bubbles, which can be photographed to show the path of the particle. The apparatus is immersed in a known magnetic field, which causes the particle to curve. Figure 20.77 is a trace of a bubble chamber image showing the path of an electron. (a) How could you determine the sign of the charge of a particle from a photograph of its path? (b) How can physicists determine the momentum and the speed of this electron by using measurements made on the photograph, given that the magnetic field is known and is perpendicular to the plane of the figure? (c) The electron is obviously spiraling into smaller and smaller circles. What properties of the electron must be changing to cause this behavior? Why does this happen? (d) What would be the path of a neutron in a bubble chamber? Why?

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