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\(\bullet\) As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150 T magnetic field near its center. You have enough wire for 4000 circular turns, and the solenoid must be 1.40 m long and 2.00 \(\mathrm{cm}\) in diameter. What current will you need to produce the necessary field?

Short Answer

Expert verified
The current needed is approximately 41.8 A.

Step by step solution

01

Understand the Formula for Solenoid's Magnetic Field

The magnetic field inside a solenoid is given by the formula \(B = \mu_0 \cdot n \cdot I\), where \(B\) is the magnetic field, \(\mu_0\) is the permeability of free space (\(4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}\)), \(n\) is the number of turns per unit length, and \(I\) is the current.
02

Calculate Turns per Unit Length

The number of turns per unit length \(n\) is calculated as the total number of turns divided by the length of the solenoid. Here, \(n = \frac{4000}{1.40} \, \text{turns/m}\).
03

Rearrange the Formula to Solve for Current

Rearrange the formula to find the current: \(I = \frac{B}{\mu_0 \cdot n}\). This allows us to solve for \(I\) once \(n\) is known.
04

Substitute Values and Solve for Current

Substitute the known values into the rearranged formula: \(I = \frac{0.150 \, \text{T}}{4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A} \cdot \frac{4000}{1.40} \, \text{turns/m}}\). Calculate \(I\) to find the current required.
05

Calculate the Numerical Answer

Calculate \(I\) using the substituted values:\[I = \frac{0.150}{4\pi \times 10^{-7} \times \frac{4000}{1.40}}\]This results in \(I \approx 41.8 \, \text{A}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
A magnetic field is a fundamental concept in physics, relating to a region where a magnetic force can be detected. In the context of solenoids, a magnetic field is created when an electric current flows through the wire loops. This field is uniform in the center of a solenoid, which means it has a constant strength and direction at that point. The strength of the magnetic field inside a solenoid is given by the formula \( B = \mu_0 \cdot n \cdot I \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space, \( n \) is the number of turns per unit length, and \( I \) is the current flowing through the solenoid.
  • Uniform fields are ideal for applications like electromagnets and transformers, where consistent magnetic effects are required.
  • The strength of the magnetic field is directly proportional to current and the number of turns per unit length.
Current Calculation
Calculating the current needed to create a desired magnetic field inside a solenoid is crucial. The steps involve using the formula \( I = \frac{B}{\mu_0 \cdot n} \). This requires re-arranging the fundamental solenoid magnetic field equation.
First, understand that the current \( I \) is what powers the magnetic field. To find \( I \), you need to know the desired magnetic field \( B \), the permeability of free space \( \mu_0 \), and the number of turns per unit length \( n \). Substituting these values into the formula gives you the current required.
Consider this example: if you need \( 0.150 \) Tesla magnetic field from a solenoid, with permeability \( 4\pi \times 10^{-7} \) T\cdot m/A, and \( n = \frac{4000}{1.40} \) turns/m, you find the current needed is approximately \( 41.8 \) A.
Turns per Unit Length
The term "turns per unit length" refers to how many loops of wire are packed into each meter of the solenoid's length. It is symbolized by \( n \) in equations. This value significantly impacts the strength of the magnetic field produced by the solenoid. The calculation is straightforward: divide the total number of turns by the solenoid's length. In our example, the solenoid has 4000 turns and a length of 1.40 meters. Therefore, \( n = \frac{4000}{1.40} \) turns/m.
  • Higher number of turns per unit length increases the magnetic field strength.
  • Compact solenoids can save space while still producing a strong magnetic field.
This concept helps in designing solenoids with desired field strengths by adjusting the number of turns and their distribution along the solenoid's length.
Permeability of Free Space
The permeability of free space, symbolized by \( \mu_0 \), is a constant that appears in several magnetic equations. It quantifies how easily a magnetic field can be established in a vacuum. The value of \( \mu_0 \) is approximately \( 4\pi \times 10^{-7} \) T\cdot m/A. This constant is critical when calculating the magnetic field inside a solenoid. When combined with the current and turns per unit length, it determines the field’s strength.
  • Acts as a benchmark to compare with materials having different permeability.
  • The uniformity of this constant simplifies calculations in theoretical physics.
Understanding \( \mu_0 \) helps predict how materials will respond to magnetic fields, crucial in designing devices like transformers, inductors, and other electromagnetic applications.

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Most popular questions from this chapter

\bullet Bubble chamber, I. Certain types of bubble chambers are filled with liquid hydrogen. When a particle (such as an electron or a proton) passes through the liquid, it leaves a track of bubbles, which can be photographed to show the path of the particle. The apparatus is immersed in a known magnetic field, which causes the particle to curve. Figure 20.77 is a trace of a bubble chamber image showing the path of an electron. (a) How could you determine the sign of the charge of a particle from a photograph of its path? (b) How can physicists determine the momentum and the speed of this electron by using measurements made on the photograph, given that the magnetic field is known and is perpendicular to the plane of the figure? (c) The electron is obviously spiraling into smaller and smaller circles. What properties of the electron must be changing to cause this behavior? Why does this happen? (d) What would be the path of a neutron in a bubble chamber? Why?

(a) What is the speed of a beam of electrons when the simultaneous influence of an electric field of \(1.56 \times 10^{4} \mathrm{V} / \mathrm{m}\) and a magnetic field of \(4.62 \times 10^{-3} \mathrm{T}\) , with both fields normal to the beam and to each other, produces no deflection of the electrons? (b) In a diagram, show the relative orientation of the vectors \(\vec{\boldsymbol{v}}\) , \(\vec{\boldsymbol{E}}\) and \(\vec{\boldsymbol{B}}\) . (c) When the electric field is removed, what is the radius of the electron orbit? What is the period of the orbit?

A circular coil of wire 8.6 \(\mathrm{cm}\) in diameter has 15 turns and carries a current of 2.7 \(\mathrm{A}\) . The coil is in a region where the magnetic field is 0.56 \(\mathrm{T}\) (a) What orientation of the coil gives the maximum torque on the coil, and what is this maximum torque? (b) For what orientation of the coil is the magnitude of the torque 71\(\%\) of the maximum found in part (a)?

A closely wound, circular coil with radius 2.40 \(\mathrm{cm}\) has 800 turns. What must the current in the coil be if the magnetic field at the center of the coil is 0.0580 \(\mathrm{T}\) ?

\(\bullet\) If the magnetic field due to a long, straight current-carrying wire has a magnitude \(B\) at a distance \(R\) from the wire's center, how far away must you be (in terms of \(R\) ) for the magnetic field to decrease to \(B / 3 ?\)

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