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You want to produce a magnetic field of magnitude \(5.50 \times 10^{-4} \mathrm{T}\) at a distance of 0.040 \(\mathrm{m}\) from a long, straight wire's center. (a) What current is required to produce this field? (b) With the current found in part (a), how strong is the magnetic field 8.00 \(\mathrm{cm}\) from the wire's center?

Short Answer

Expert verified
(a) 11.0 A; (b) 2.75 × 10^-4 T.

Step by step solution

01

Understanding the formula

The magnetic field around a long, straight wire is given by the formula: \( B = \frac{\mu_0 I}{2\pi r} \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \ \mathrm{T\cdot m/A} \)), \( I \) is the current, and \( r \) is the distance from the wire. We will use this formula to find the current \( I \).
02

Rearranging the formula

To find the current \( I \), we rearrange the formula to solve for \( I \): \( I = \frac{B \, 2\pi r}{\mu_0} \).
03

Substituting the values for part (a)

Substitute the given values into the rearranged formula: \( B = 5.50 \times 10^{-4} \, \mathrm{T} \), \( r = 0.040 \, \mathrm{m} \), and \( \mu_0 = 4\pi \times 10^{-7} \, \mathrm{T\cdot m/A} \). This gives \( I = \frac{(5.50 \times 10^{-4} \, \mathrm{T}) \, 2\pi \, (0.040 \, \mathrm{m})}{4\pi \times 10^{-7} \, \mathrm{T\cdot m/A}} \).
04

Calculating the current

Perform the calculation: \( I = \frac{(5.50 \times 10^{-4} \, \mathrm{T}) \, 2\pi \, (0.040 \, \mathrm{m})}{4\pi \times 10^{-7} \, \mathrm{T\cdot m/A}} = 11.0 \, \mathrm{A} \). So, the current required is 11.0 A.
05

Calculating the magnetic field at 8.00 cm

Now for part (b), we use the same formula \( B = \frac{\mu_0 I}{2\pi r} \) to find the magnetic field at \( r = 0.080 \, \mathrm{m} \) with the current \( I = 11.0 \, \mathrm{A} \). Substitute the values: \( B = \frac{(4\pi \times 10^{-7} \, \mathrm{T\cdot m/A}) \, (11.0 \, \mathrm{A})}{2\pi \, (0.080 \, \mathrm{m})} \).
06

Solving for the magnetic field at 8.00 cm

Perform the calculation: \( B = \frac{(4\pi \times 10^{-7} \, \mathrm{T\cdot m/A}) \, (11.0 \, \mathrm{A})}{2\pi \, (0.080 \, \mathrm{m})} = 2.75 \times 10^{-4} \, \mathrm{T} \). Thus, the magnetic field at 8.00 cm is \( 2.75 \times 10^{-4} \, \mathrm{T} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampere's Law
Ampere's Law is a fundamental principle in electromagnetism that describes how magnetic fields are generated by electric currents. It states that the line integral of the magnetic field \( \mathbf{B} \) around a closed loop is proportional to the total current \( I \) passing through the loop. Mathematically, this is expressed as: \[ \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I \]Here, \( \mu_0 \) represents the permeability of free space, and \( d\mathbf{l} \) is a differential length element of the loop. Ampere's Law simplifies to show that for a long, straight wire, the magnetic field's strength depends on the current, and diminishes with distance from the wire. This law is essential for calculating the magnetic effects of currents in various scenarios. By applying this principle, the relation between a wire's current and the magnetic field it generates can be understood and utilized in electric circuits and devices.
Current Calculation
The current calculation is important when trying to determine the amount of current needed to generate a specific magnetic field at a certain distance from a wire. In this problem, we use the formula that comes from Ampere's Law specific to a long, straight wire:\[ I = \frac{B \cdot 2\pi r}{\mu_0} \]This equation is derived by rearranging the magnetic field equation to solve for the current \( I \).
  • \( B \) is the magnetic field's desired strength.
  • \( r \) is the distance from the wire center to the point where \( B \) is measured.
  • \( \mu_0 \) is the permeability of free space.
For example, if the magnetic field required is \( 5.50 \times 10^{-4} \ \mathrm{T} \) at \( 0.040 \ \mathrm{m} \) from the wire, you can substitute these values into the formula to find \( I \). This calculation is crucial for electronic design and experimentation, ensuring circuits function as intended.
Permeability of Free Space
The permeability of free space, often denoted as \( \mu_0 \), is a physical constant integral to electromagnetic theory. It characterizes how much magnetic field can be generated within a vacuum by a given amount of current. Mathematically, it is expressed as: \[ \mu_0 = 4\pi \times 10^{-7} \, \mathrm{T \cdot m/A} \]This constant indicates the extent to which a magnetic field can penetrate a vacuum and is a key component when calculating magnetic fields and forces. In our context, \( \mu_0 \) allows us to understand the interaction between magnetic fields and currents in wire calculations. It is particularly important in equations derived from Ampere's Law, as it provides the 'scaling factor' that relates the current to the magnetic field strength for any given geometry. Understanding \( \mu_0 \) is foundational to mastering how magnetic phenomena work in theoretical and applied physics.
Magnetic Field of a Straight Wire
The magnetic field produced by a long, straight wire is an intriguing phenomenon. When an electric current runs through a wire, it creates a circular magnetic field surrounding the wire. This field's strength decreases with distance from the wire. The relationship can be described with the formula: \[ B = \frac{\mu_0 I}{2\pi r} \]
  • \( B \) is the magnetic field strength.
  • \( \mu_0 \) is the permeability of free space.
  • \( I \) is the current flowing through the wire.
  • \( r \) is the radial distance from the wire's center.
For example, if we calculate \( B \) at 0.080 m from a wire with a current of 11.0 A, this formula shows how the magnetic field lessens with increasing distance. This principle has practical applications in designing electromagnetic devices and understanding how currents interact with their surroundings, serving as a basis for technologies in electronics and communications.

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Most popular questions from this chapter

. You have 25 \(\mathrm{m}\) of wire, which you want to use to construct a 44 \(\mathrm{cm}\) diameter coil whose magnetic field at its center will exactly cancel the earth's field of 0.55 gauss. What current will your coil require?

The effect of transmission lines. Two hikers are reading a compass under an overhead transmission line that is 5.50 \(\mathrm{m}\) above the ground and carries a current of 0.800 \(\mathrm{kA}\) in a horizontal direction from north to south. (a) Find the magnitude and direction of the magnetic field at a point on the ground directly under the transmission line. (b) One hiker suggests that they walk 50 \(\mathrm{m}\) away from the lines to avoid inaccurate compass readings due to the current. Considering that the earth's magnetic field is on the order of \(0.5 \times 10^{-4} \mathrm{T},\) is the current really a problem?

\(\bullet\) A proton traveling at 3.60 \(\mathrm{km} / \mathrm{s}\) suddenly enters a uniform magnetic field of 0.750 \(\mathrm{T}\) , traveling at an angle of \(55.0^{\circ}\) with the field lines (Figure 20.57\()\) . (a) Find the magnitude and direction of the force this magnetic field exerts on the proton. (b) If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve, and show how the velocity should be oriented to achieve these forces. (c) What would the answers to part (a) be if the proton were replaced by an electron traveling in the same way as the proton?

An ion having charge \(+6 e\) is traveling horizontally to the left at 8.50 \(\mathrm{km} / \mathrm{s}\) when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of \(6.94 \times 10^{-15} \mathrm{N} .\) What are the direction and magnitude of this field? Illustrate your method of solving this problem with a diagram.

\(\cdot\) The plane of a 5.0 \(\mathrm{cm}\) by 8.0 \(\mathrm{cm}\) rectangular loop of wire is parallel to a 0.19 T magnetic field, and the loop carries a cur- rent of 6.2 \(\mathrm{A}\) . (a) What torque acts on the loop? (b) What is the magnetic moment of the loop?

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