/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 A 0.525 kg ball starts from rest... [FREE SOLUTION] | 91Ó°ÊÓ

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A 0.525 kg ball starts from rest and rolls down a hill with uniform acceleration, traveling 150 m during the second 10.0 \(\mathrm{s}\) of its motion. How far did it roll during the first 5.0 s of motion?

Short Answer

Expert verified
The ball rolls 12.5 meters during the first 5 seconds.

Step by step solution

01

Understanding the Problem

We are given a ball that starts from rest and rolls down a hill with uniform acceleration. We know the distance it travels during the second 10 seconds (from 10s to 20s) is 150 m. We need to find how far it rolls during the first 5 seconds.
02

Determine the Acceleration

Since the ball starts from rest, we can use the equation for distance traveled using uniform acceleration,\[s = ut + \frac{1}{2}at^2,\]where \(u = 0\) (initial velocity), \(s\) is distance, \(t\) is time, and \(a\) is acceleration. We can express the distance for the first 20 seconds as \(s_{20} = \frac{1}{2}a(20)^2 = 200a\), and the distance for the first 10 seconds as \(s_{10} = \frac{1}{2}a(10)^2 = 50a\). The distance for the second 10 seconds \((s_{10 \to 20})\) is the difference of these: \(s_{10 \to 20} = s_{20} - s_{10} = 150m = 200a - 50a = 150a\). Solving for \(a\), we find \(a = 1\).
03

Calculate Distance for First 5 Seconds

Now that we know the acceleration \(a = 1\), we can calculate the distance traveled in the first 5 seconds using \[s = \frac{1}{2} a t^2.\] Substituting \(a = 1\) and \(t = 5\), we get \[s = \frac{1}{2} \times 1 \times (5)^2 = \frac{1}{2} \times 25 = 12.5 \text{ m}.\] Thus, the ball rolls 12.5 meters in the first 5 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
In physics, kinematics is a branch that studies motion without considering the forces that cause the motion. It's all about describing how objects move rather than why they move. Kinematics involves analyzing parameters such as velocity, speed, acceleration, and displacement. These parameters help in understanding how an object traverses through space over a period of time.

In the context of our exercise, kinematics is used to describe the ball's journey as it rolls down a hill. Since the ball starts from rest, its movement is characterized by its acceleration, which is constant in this case. Observing uniform acceleration helps simplify the equations we use as changes in motion can be predicted more easily.

Understanding kinematics allows you to break down complex motion problems into simpler ones by looking at different motion segments separately. Through kinematic equations, we can determine crucial information like the distance covered in particular time frames, making the study of motion practical for solving real-world problems.
Distance-Time Relations
Distance-time relations help us understand how the motion of an object progresses over time. By analyzing these relations, we can determine how far an object travels during specific time intervals. This is particularly useful in cases where the motion includes uniform acceleration.

In our given exercise, these relations allow us to calculate how far the ball travels during different segments of its motion down the hill. The ball covers a total of 150 meters during the second 10 seconds of its movement. This information, combined with the understanding that the ball starts from rest, helps us derive the ball's acceleration and other details necessary for further calculations.

The distance-time relationship is graphically represented as a parabola when acceleration is constant, as seen in this problem. It creates a visual representation of the ball speeding up as it continues to roll, emphasizing the increasing distance over equal time intervals due to acceleration.
Equations of Motion
Equations of motion are mathematical relationships that describe the behavior of moving objects. They allow us to calculate important quantities like position, velocity, and time for objects in uniform or non-uniform motion.

In this problem, we use one of the fundamental equations of motion: \[s = ut + \frac{1}{2}at^2,\]where:
  • \(u\) = initial velocity, which is 0 since the ball starts from rest,
  • \(a\) = acceleration, which we found to be 1 \( \text{m/s}^2 \),
  • \(t\) = time, the duration for which the motion is considered,
  • \(s\) = distance, the total path length covered by the object.
For the initial period (the first 5 seconds), the equation simplifies our calculation of the distance. Knowing the acceleration, we substitute it into the equation to find that the ball rolls 12.5 meters in this initial time frame.

These equations provide a systematic way to solve motion-related problems, offering quantitative insights into how objects move through space and time.

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Most popular questions from this chapter

Earthquake waves. Earthquakes produce several types of shock waves. The best known are the P-waves (P for primary or pressure) and the S-waves (S for secondary or shear). In the earth's crust, P-waves travel at around 6.5 \(\mathrm{km} / \mathrm{s}\) while S-waves move at about 3.5 \(\mathrm{km} / \mathrm{s}\) . (The actual speeds vary with the type of material the waves are going through.) The time delay between the arrival of these two types of waves at a seismic recording station tells geologists how far away the earthquake that produced the waves occurred. (a) If the time delay at a seismic station is 33 s, how far from that station did the earthquake that produced the waves occurred. (a) If the time delay at a seismic station is 33 s, how far from that station did the earthquake occur? (b) One form of earthquake warning system detects the faster (but less damaging) P-waves and sounds an alarm when they first arrive, giving people a short time to seek cover before the more dangerous S-waves arrive. If an earthquake occurs 375 \(\mathrm{km}\) away from such a warning device, how much time would people have to take cover between the alarm and the arrival of the S-waves?

Starting from rest, a boulder rolls down a hill with constant acceleration and travels 2.00 \(\mathrm{m}\) during the first second. (a) How far does it travel during the second second? (b) How fast is it moving at the end of the first second? at the end of the second second?

A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no appreciable air drag. (a) How tall, in meters, is the building? (b) How fast is the brick moving just before it reaches the ground? (c) Sketch graphs of this falling brick's acceleration, velocity, and vertical position as functions of time.

An airplane travels 280 \(\mathrm{m}\) down the runway before taking off. Assuming that it has constant acceleration, if it starts from rest and becomes airborne in 8.00 s, how fast \((\) in \(\mathrm{m} / \mathrm{s})\) is it moving at takeoff?

Raindrops. If the effects of the air acting on falling raindrops are ignored, then we can treat raindrops as freely falling objects. (a) Rain clouds are typically a few hundred meters above the ground. Estimate the speed with which raindrops would strike the ground if they were freely falling objects. Give your estimate in \(\mathrm{m} / \mathrm{s}, \mathrm{km} / \mathrm{h},\) and milh. (b) Estimate (from your own personal observations of rain the speed with which raindrops actually strike the ground. (c) Based on your answers to parts (a) and (b), is it a good approximation to neglect the effects of the air on falling raindrops? Explain.

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