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Charging and discharging a capacitor. An initially uncharged capacitor \(C\) charges through a resistor \(R\) for many time constants and then discharges through the same resistor. Call \(Q_{\max }\) the maximum charge on its plates and \(I_{\max }\) the maximum current in the circuit. (a) Sketch clear graphs of the charge on the plates and the current in the circuit as functions of time for the charging process. (b) During the discharging process, the charge on the capacitor and the current both decrease exponentially from their maximum values. Use this fact to sketch graphs of the current in the circuit and the charge on the capacitor as functions of time.

Short Answer

Expert verified
Charging: exponential increase in charge, exponential decay in current. Discharging: exponential decay in both charge and current.

Step by step solution

01

Understanding the Charging Process

During the charging of a capacitor, the charge on the plates increases from zero to a maximum value, \( Q_{\max} \). The rate of charging depends on the resistor \( R \) and the capacitance \( C \). The charge \( Q(t) \) on the capacitor as a function of time is given by the equation:\[Q(t) = Q_{\max} \left(1 - e^{-t/RC}\right)\]This equation shows that the charge approaches \( Q_{\max} \) asymptotically. Initially, the current is maximum \( I_{\max} \) and decreases over time according to \[I(t) = I_{\max} e^{-t/RC}\]This indicates an exponential decay of the current.
02

Sketching the Charging Graphs

To sketch the charge \( Q(t) \) against time, plot an exponential growth curve starting from zero and asymptotically approaching \( Q_{\max} \). The current \( I(t) \) should start at its maximum value \( I_{\max} \) and decay exponentially towards zero. Both graphs are defined by the time constant \( RC \), which determines the rate at which the charge builds and the current decays.
03

Understanding the Discharging Process

For discharging, the charge \( Q(t) \) on the capacitor and the current \( I(t) \) in the circuit decrease exponentially. The equations governing these quantities during discharge are:\[Q(t) = Q_{\max} e^{-t/RC}\] \[I(t) = I_{\max} e^{-t/RC}\] Both charge and current decrease to zero over time, following an exponential curve. The maximum values \( Q_{\max} \) and \( I_{\max} \) are reached immediately before discharge starts.
04

Sketching the Discharging Graphs

For the discharge process, plot \( Q(t) \) starting from \( Q_{\max} \) and exponentially decreasing to zero. Likewise, plot \( I(t) \) beginning at \( I_{\max} \) and decreasing exponentially to zero. Both graphs show an exponential decay characterized by the time constant \( RC \). The axes should reflect that the quantities rapidly decline initially, slowing down as they approach zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Decay
Exponential decay is a process where quantities decrease at a rate proportional to their current value. In the context of capacitor circuits, both the charging and discharging processes show exponential behavior. During charging, the current starts high and then exponentially decreases over time. Similarly, during discharging, both the charge and the current exponentially decay toward zero. This behavior is described by mathematical equations. For instance, during the discharge phase, the charge on a capacitor decreases according to the formula \[ Q(t) = Q_{\max} e^{-t/RC} \] where \( Q_{\max} \) is the initial maximum charge, \( t \) is time, and \( RC \) is the time constant. The formula visually represents an exponential curve that starts at its maximum and gradually declines to zero over time.
Time Constant
The time constant \( RC \) plays a critical role in capacitor circuits. It's a product of the resistance \( R \) and the capacitance \( C \) of the circuit. This constant gives an idea of how quickly the capacitor will charge or discharge. For both processes, charging and discharging, the time constant \( RC \) dictates the rate of change. After a time equal to one \( RC \), the charge and current have changed significantly. Specifically, during the charging process, the capacitor reaches about 63.2% of \( Q_{\max} \) in one time constant. During discharging, the charge and current reduce to about 36.8% of their initial values in the same interval.Understanding \( RC \) helps predict how long it would take for the capacitor to charge or discharge in real-world scenarios, making it an essential parameter in designing electrical circuits.
Capacitor Circuits
Capacitor circuits play an essential role in electronics by storing and releasing electrical energy. They consist of a capacitor connected to other electrical components, like resistors. A capacitor is essentially two conductive plates separated by an insulator, storing electrical energy when a voltage is applied. Resistors, on the other hand, control the rate of charging and discharging by offering resistance to the flow of current. The combination of capacitors and resistors forms a simple yet fundamental circuit used in various applications - from filtering to timing devices. It's crucial to understand that while a capacitor charges, it stores energy in an electric field. When discharging, it releases the stored energy back into the circuit. Grasping these fundamentals will allow you to understand more complex circuits that use capacitors.
Charging Process
The charging process of a capacitor can be visualized as a gradual build-up of charge on its plates. Initially, when a voltage source is connected, the current is at its maximum because there is no stored charge to counteract the voltage. As time progresses, the capacitor plates accumulate charge, creating an opposing voltage to the source. This results in a decrease in current over time. Mathematically, the charge \( Q(t) \) on a capacitor during charging is given by: \[ Q(t) = Q_{\max} \left(1 - e^{-t/RC}\right) \]This equation shows that as time approaches infinity, the charge approaches \( Q_{\max} \), indicating the capacitor is fully charged. Graphically, the charge increases rapidly initially and then slows down as it nears its maximum value, while the current decays exponentially toward zero, as the capacitor becomes fully charged.
Discharging Process
In the discharging process, a fully charged capacitor releases its stored energy back into the circuit. Initially, the current and charge are at their maximum values \( I_{\max} \) and \( Q_{\max} \), respectively. As the energy is released, both quantities decrease exponentially.The equations describing this are:- **Charge**: \( Q(t) = Q_{\max} e^{-t/RC} \)- **Current**: \( I(t) = I_{\max} e^{-t/RC} \)At the start, the current is high and decreases quickly, leveling off as it approaches zero. Graphically, this creates a distinctive exponential decay curve. This rapid initial drop and gradual slowing highlight the discharging process's key characteristics. Understanding these basics is integral for working with electronic timing and filtering circuits.

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Most popular questions from this chapter

Charging and discharging a capacitor. A 1.50\(\mu \mathrm{F}\) capacitor is charged through a 125\(\Omega\) resistor and then discharged through the same resistor by short-circuiting the battery. While the capacitor is being charged, find (a) the time for the charge on its plates to reach \(1-1 / e\) of its maximum value and (b) the current in the circuit at that time. (c) During the discharge of the capacitor, find the time for the charge on its plates to decrease to 1/e of its initial value. Also, find the time for the current in the circuit to decrease to 1\(/ e\) of its initial value.

Flashlight batteries. A typical small flashlight contains two batteries, each having an emf of 1.5 \(\mathrm{V}\) , connected in series with a bulb having resistance 17\(\Omega .\) (a) If the internal resistance of the batteries is negligible, what power is delivered to the bulb? (b) If the batteries last for 5.0 h, what is the total energy delivered to the bulb? (c) The resistance of real batteries increases as they run down. If the initial internal resistance is negligible, what is the combined internal resistance of both batteries when the power to the bulb has decreased to half its initial value? (Assume that the resistance of the bulb is constant. Actually, it will change somewhat when the current through the filament changes, because this changes the temperature of the filament and hence the resistivity of the filament wire.)

A wire 6.50 \(\mathrm{m}\) long with diameter of 2.05 \(\mathrm{mm}\) has a resistance of 0.0290\(\Omega .\) What material is the wire most likely made of?

Struck by lightning. Lightning strikes can involve currents as high as \(25,000\) A that last for about 40\(\mu\) s. If a person is struck by a bolt of lightning with these properties, the current will pass through his body. We shall assume that his mass is 75 kg, that he is wet (after all, he is in a rainstorm) and therefore has a resistance of \(1.0 \mathrm{k} \Omega,\) and that his body is all water (which is reasonable for a rough, but plausible, approximation).(a) By how many degrees Celsius would this lightning bolt increase the temperature of 75 kg of water? (b) Given that the internal body temperature is about \(37^{\circ} \mathrm{C}\) , would the person's temperature actually increase that much? Why not? What would happen first?

A 6.00 \(\mathrm{V}\) lantern battery is connected to a 10.5\(\Omega\) lightbulb, and the resulting current in the circuit is 0.350 A. What is the internal resistance of the battery?

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