Chapter 17: Problem 72
\(\bullet$$\bullet \mathrm{A}-5.00 \mathrm{nC}\) point charge is on the \(x\) axis at \(x=1.20 \mathrm{m} . \mathrm{A}\) second point charge \(Q\) is on the \(x\) axis at \(-0.600 \mathrm{m} .\) What must be the sign and magnitude of \(Q\) for the resultant electric field at the origin to be (a) 45.0 \(\mathrm{N} / \mathrm{C}\) in the \(+x\) direction, \((\mathrm{b}) 45.0 \mathrm{N} / \mathrm{C}\) in the \(-x\) direction?
Short Answer
Step by step solution
Understanding the Problem
Electric Field Due to a Point Charge
Calculate the Electric Field from Charge A
Set up the Equation for the Resultant Electric Field - Part (a)
Calculate Magnitude and Sign of Q for Part (a)
Set up the Equation for the Resultant Electric Field - Part (b)
Calculate Magnitude and Sign of Q for Part (b)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
- \( F \) is the force between the charges.
- \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \).
- \( q_1 \) and \( q_2 \) are the amounts of the charges.
- \( r \) is the distance between the centers of the two charges.
Point Charge
- Point charges can be positive or negative, affecting the direction of the resultant electric field.
- They are essential for building an understanding of electric fields and forces in both theoretical and applied electricity concepts.
Electric Field Direction
- The field direction from each charge must be considered to derive the net field at a point, such as the origin.
- Positive charges contribute fields that push away, whereas negative charges pull towards them.
- Understanding these directions assists in correctly determining if charges will add or subtract from the total electric field in any given direction.
Calculation of Electric Fields
- \( E \) is the electric field.
- \( k \) is Coulomb’s constant.
- \( q \) is the point charge.
- \( r \) is the distance from the charge to the point where the field is being calculated.
- We hone the skill of setting up and solving equations where multiple charges affect the field directionality and magnitude.
- We calculate the resultant field by summing the fields produced by each point charge, attending carefully to their vector nature (direction and magnitude).