/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 \(\bullet$$\bullet\) A cylinder ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(\bullet$$\bullet\) A cylinder 1.00 \(\mathrm{m}\) tall with inside diameter 0.120 \(\mathrm{m}\) is used to hold propane gas (molar mass 44.1 \(\mathrm{g} / \mathrm{mol} )\) for use in a barbecue. It is initially filled with gas until the gauge pressure is \(1.30 \times 10^{6} \mathrm{Pa}\) and the temperature is \(22.0^{\circ} \mathrm{C} .\) The temperature of the gas remains constant as it is partially emptied out of the tank, untill the gauge pressure is \(2.50 \times 10^{5}\) Pa. Calculate the mass of propane that has been used.

Short Answer

Expert verified
The mass of propane used is 0.224 kg.

Step by step solution

01

Identify the Ideal Gas Law

The problem can be approached using the ideal gas law equation: \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is moles, \( R \) is the gas constant (\(8.314 \text{ J/(mol K)} \)), and \( T \) is temperature in Kelvin.
02

Convert Temperature to Kelvin

Convert the given temperature from Celsius to Kelvin using the formula: \( T(K) = T(°C) + 273.15 \).\[ T = 22 + 273.15 = 295.15 \text{ K} \]
03

Calculate Volume of the Cylinder

The volume \( V \) of the cylinder can be calculated using \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height. Since the diameter is 0.120 m, the radius is 0.060 m.\[ V = \pi (0.060)^2 (1.00) = 0.0113048 \text{ m}^3 \]
04

Calculate Initial and Final Moles of Propane

First, find the moles using the initial conditions \( (P_1 = 1.30 \times 10^6 \text{ Pa}) \) and \( V \) from Step 3.\[ \frac{P_1 V}{RT} = n_1 = \frac{1.30 \times 10^6 \times 0.0113048}{8.314 \times 295.15} \approx 6.30 \text{ moles} \]\[ \text{Final moles }(P_2 = 2.50 \times 10^5 \text{ Pa}): \frac{P_2 V}{RT} = n_2 = \frac{2.50 \times 10^5 \times 0.0113048}{8.314 \times 295.15} \approx 1.21 \text{ moles} \]
05

Calculate Mass of Propane Used

Subtract the final moles from the initial moles to find the moles used: \( n_{used} = n_1 - n_2 = 6.30 - 1.21 = 5.09 \) moles. Convert moles to mass with molar mass \( (44.1 \text{ g/mol} = 0.0441 \text{ kg/mol}) \).\[ \text{Mass} = n_{used} \times \text{molar mass} = 5.09 \times 0.0441 = 0.224 \text{ kg} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure and Volume Relationships
The relationship between pressure and volume is a fundamental concept in understanding gases, especially in the context of the ideal gas law. According to the ideal gas law, the product of pressure and volume is directly proportional to the product of the number of moles and temperature, represented by the equation \(PV = nRT\). This means that at a constant temperature, if the volume of a gas increases, the pressure decreases and vice versa. This principle is a specific case of Boyle's Law when temperature is held constant.

In practical terms, this is relevant when dealing with gases stored in containers, like propane in a barbecue cylinder. Initially, the gas cylinder is filled to a high pressure. As gas is used, the pressure inside the cylinder decreases if the temperature remains constant, which is useful for calculating how much gas has been consumed.

Understanding these relationships helps us in predicting how gases will behave under different conditions of temperature, pressure, and volume. This knowledge can be critical in areas ranging from weather forecasting to engineering applications.
Cylinder Volume Calculation
Calculating the volume of a cylinder plays a critical role in several real-world applications, especially those involving the storage of gases. The volume \(V\) of a cylinder is computed using the formula \(V = \pi r^2 h\), where \(r\) is the radius of the cylinder's base and \(h\) is its height. This formula helps determine how much space is available inside the cylinder for containing a certain amount of gas.

For example, if the cylinder has an inside diameter of 0.120 meters, the radius can be determined by dividing the diameter by two, resulting in 0.060 meters. By substituting the radius and height values into the formula, the total volume is calculated. In our specific problem, using a height of 1.00 meter, we find a volume of approximately 0.0113 cubic meters (\(m^3\)).

This method is invaluable for engineers and scientists needing to measure how much gas a vessel can contain. Additionally, this knowledge helps in various fields, including chemical processing and environmental science, where precise measurements are crucial.
Molar Mass and Mole Calculations
Molar mass and mole calculations are essential when dealing with chemical substances. The concept of a mole is central to chemistry as it allows scientists to count atoms, molecules, or ions in a given sample, which is crucial for chemical reactions and processes. The molar mass, given in grams per mole (\(g/mol\)), connects the mass of a substance to the number of moles. For propane, the molar mass is 44.1 \(g/mol\).

Using the ideal gas law \(PV = nRT\), we can determine the number of moles \(n\) of gas in a container. In situations like our initial problem, this involves calculating the initial and final moles of gas based on pressure and temperature values. Knowing the number of moles lets us find out the mass change, as mass equals the number of moles multiplied by the molar mass. For instance, if 5.09 moles of propane are used, the mass used equates to approximately 0.224 kilograms when converted using the molar mass.

This calculation methodology is vital in both academic and industrial settings, especially for tasks requiring precise material usage estimates, such as manufacturing and resource management.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(\bullet\) Suppose you do 457 \(\mathrm{J}\) of work on 1.18 moles of ideal He gas in a perfectly insulated container. By how much does the internal energy of this gas change? Does it increase or decrease?

\(\bullet\) A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499 \(\mathrm{cm}^{3}\) of air at atmospheric pressure \(\left(1.01 \times 10^{5} \mathrm{Pa}\right)\) and a temperature of \(27.0^{\circ} \mathrm{C}\) At the end of the stroke, the air has been compressed to a volume of 46.2 \(\mathrm{cm}^{3}\) and the gauge pressure has increased to \(2.72 \times 10^{6} \mathrm{Pa} .\) Compute the final temperature.

\(\bullet$$\bullet\) How often do we need to breathe? A resting person requires 14.5 \(\mathrm{L}\) of \(\mathrm{O}_{2}\) per hour to maintain metabolic activities. Such a person breathes in 0.50 \(\mathrm{L}\) of air at approximately \(20^{\circ} \mathrm{C}\) with each breath. The inhaled air is \(20.9 \% \mathrm{O}_{2},\) while the exhaled air is 16.3\(\% \mathrm{O}_{2} .\) (a) How many breaths per minute does a resting person need to take to provide the necessary oxygen? (b) How many \(\mathrm{O}_{2}\) molecules does a resting person inhale per breath?

\(\bullet\) The gas inside a balloon will always have a pressure nearly equal to atmospheric pressure, since that is the pressure applied to the outside of the balloon. You fill a balloon with helium (a nearly ideal gas) to a volume of 0.600 L at a temperature of \(19.0^{\circ} \mathrm{C}\) . What is the volume of the balloon if you cool it to the boiling point of liquid nitrogen \((77.3 \mathrm{K})\) ?

As the temperature of a monatomic gas increases, we expect its specific heat to A. remain the same B. increase C. decrease

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.