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\(\cdot\) Heat loss during breathing. In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into the lungs with each breath. (a) On a cold winter day when the temperature is \(-20^{\circ} \mathrm{C},\) what is the amount of heat needed to warm to internal body temperature \(\left(37^{\circ} \mathrm{C}\right)\) the 0.50 \(\mathrm{L}\) of air exchanged with each breath? Assume that the specific heat capacity of 1.3 \(\mathrm{g}\) is 1020 \(\mathrm{J} /(\mathrm{kg} \cdot \mathrm{K})\) and that 1.0 \(\mathrm{L}\) of air has a mass of 1.3 \(\mathrm{g}\) . (b) How much heat is lost per hour if the respiration rate is 20 breaths per minute?

Short Answer

Expert verified
Heat needed for each breath: 37.959 J; Heat lost per hour: 45550.8 J.

Step by step solution

01

Identify the Temperature Difference

To solve this problem, first calculate the temperature difference between the external air temperature and the body temperature. The external temperature is \(-20^{\circ} \mathrm{C}\) and the internal body temperature is \(37^{\circ} \mathrm{C}\). Find the difference by subtracting: \(T_{\text{difference}} = 37 - (-20) = 57^{\circ} \mathrm{C}\).
02

Calculate Heat for One Breath

Use the formula for heat transfer, \(Q = mc\Delta T\), where \(m\) is the mass of air, \(c\) is the specific heat capacity, and \(\Delta T\) is the temperature change. The mass \(m = 0.50\, \text{L} \times 1.3\, \text{g/L} = 0.65\, \text{g} = 0.00065\, \text{kg}\). The specific heat capacity \(c = 1020\, \text{J/kg} \cdot \text{K}\). Thus, \(Q = 0.00065 \times 1020 \times 57 = 37.959\, \text{J}\).
03

Determine Breaths per Hour

Calculate the total number of breaths taken per hour. If the respiration rate is 20 breaths per minute, then over one hour \(60\, \text{minutes/hour} \times 20\, \text{breaths/minute} = 1200\, \text{breaths/hour}\).
04

Calculate Total Heat Loss per Hour

To find the total heat lost per hour, multiply the heat required for one breath by the total number of breaths per hour. Using \(Q = 37.959\, \text{J/breath}\) and \(1200\, \text{breaths/hour}\), the total heat loss is \(37.959 \times 1200 = 45550.8\, \text{J/hour}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
Specific heat capacity is a crucial factor in calculating how much energy is required to change the temperature of a substance. It represents the amount of heat needed to raise the temperature of 1 kilogram of a material by 1 degree Celsius (or 1 Kelvin).

This concept is vital when thinking about the warming of air during breathing, particularly in cold weather. Air has a specific heat capacity, and when you breathe in cold air, your body uses energy to warm it up to your body's internal temperature. The specific heat tells us how much energy is needed to make this temperature change happen. In our problem, we looked at an air mass with a specific heat capacity of 1020 J/(kg·K). This specific heat capacity indicates how resistant the air is to temperature change.

To apply this, we used the formula for heat transfer: \[ Q = mc\Delta T \]where:
  • \(Q\) is the heat energy (in joules)
  • \(m\) is the mass of the air (in kilograms)
  • \(c\) is the specific heat capacity
  • \(\Delta T\) is the temperature change (in degrees Celsius or Kelvin)
This equation helps us calculate how much energy will be needed to warm the air taken in each breath so that it can reach the body's internal temperature.
Thermal Energy
Thermal energy, often referred to as heat, is the form of energy that is generated and measured by heat transfer and temperature changes. It is crucial to everyday processes, such as breathing in cold weather.

When you breathe in cold air, your body needs to use thermal energy to warm that air from the outside temperature \(-20^\circ C\) to your body’s internal temperature of \(37^\circ C\). This involves moving the heat from your body to the air. The temperature difference \(\Delta T\) is quite large in this case, at \(57^\circ C\), which is why your body loses a significant amount of energy to heat the air.

In terms of calculations, the thermal energy transfer was calculated for a single breath, and then scaled up to consider multiple breaths over a given time. By finding the heat energy required for one breath and then multiplying it by the number of breaths per hour, you can see how much thermal energy is lost in the effort to keep the warmth consistent relative to your internal temperature. This step is crucial in understanding the magnitude of heat loss through breathing.
Respiration Rate
Respiration rate refers to the number of breaths a person takes per minute. This rate can affect the total thermal energy used by the body depending on external conditions.

In cold weather, when the body must heat each breath of air to maintain its internal temperature, a higher respiration rate can lead to greater overall heat loss. In the exercise, we calculated that with a respiration rate of 20 breaths per minute, there were 1200 breaths per hour.

By knowing the heat required to warm the air in a single breath, calculated in Joules, we then multiplied this amount by 1200 to find out the total heat loss per hour. Understanding how respiration rate impacts heat transfer helps illustrate why body heat can drop quickly in cold environments and why sometimes you might feel colder when breathing heavily in such conditions.

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Most popular questions from this chapter

How large is the sun? By measuring the spectrum of wave- lengths of light from our sun, we know that its surface temperature is 5800 \(\mathrm{K}\) . By measuring the rate at which we receive its energy on earth, we know that it is radiating a total of \(3.92 \times 10^{26} \mathrm{J} / \mathrm{s}\) and behaves nearly like an ideal blackbody. Use this information to calculate the diameter of our sun.

\(\bullet\) A piece of ice at \(0^{\circ} \mathrm{C}\) falls from rest into a lake whose tem- perature is \(0^{\circ} \mathrm{C},\) and 1.00\(\%\) of the ice melts. Compute the minimum height from which the ice has fallen.

\bullet A 15.0 g bullet traveling horizontally at 865 \(\mathrm{m} / \mathrm{s}\) passes through a tank containing 13.5 \(\mathrm{kg}\) of water and emerges with a speed of 534 \(\mathrm{m} / \mathrm{s}\) . What is the maximum temperature increase that the water could have as a result of this event?

". "The Ship of the Desert." Camels require very little water because they are able to tolerate relatively large changes in their body temperature. While humans keep their body temperatures constant to within one or two Celsius degrees, a dehydrated camel permits its body temperature to drop to \(34.0^{\circ} \mathrm{C}\) overnight and rise to \(40.0^{\circ} \mathrm{C}\) during the day. To see how effective this mechanism is for saving water, calculate how many liters of water a 400 -kg camel would have to drink if it attempted to keep its body temperature at a constant \(34.0^{\circ} \mathrm{C}\) by evaporation of sweat during the day \((12\) hours) instead of letting it rise to \(40.0^{\circ} \mathrm{C}\) . (Note: The specific heat of a camel or other mammal is about the same as that of a typical human, 3480 \(\mathrm{J} /(\mathrm{kg} \cdot \mathrm{K}) .\) The heat of vaporization of water at \(34^{\circ} \mathrm{C}\) is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} . )\)

You are asked to design a cylindrical steel rod 50.0 \(\mathrm{cm}\) long, with a circular cross section, that will conduct 150.0 \(\mathrm{J} / \mathrm{s}\) from a furnace at \(400.0^{\circ} \mathrm{C}\) to a container of boiling water under 1 atmosphere of pressure. What must the rod's diameter be?

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