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\(\cdot\) Find the intensity \(\left(\) in \(W / m^{2}\right)\) of (a) a 55.0 dB sound, (b) a 92.0 dB sound, (c) a \(-2.0\) dB sound.

Short Answer

Expert verified
The intensities are \( 3.1623 \times 10^{-7} \, W/m^2 \), \( 1.5849 \times 10^{-3} \, W/m^2 \), and \( 6.3096 \times 10^{-13} \, W/m^2 \) for 55.0 dB, 92.0 dB, and -2.0 dB respectively.

Step by step solution

01

Understanding Decibels

Decibels (dB) are a unit of measure for sound intensity, where the intensity level in decibels is calculated using the formula: \[ L = 10 imes ext{log}_{10} \left( \frac{I}{I_0} \right) \] Here, \( L \) is the sound level in decibels, \( I \) is the intensity of the sound in \( W/m^2 \), and \( I_0 = 10^{-12} \, W/m^2 \) is the reference intensity level, typically considered the threshold of hearing.
02

Rearranging the Formula

To find the intensity \( I \) from a given decibel (dB) level, we rearrange the initial formula to solve for \( I \): \[ I = I_0 \times 10^{(L/10)} \] This equation allows us to calculate the intensity using the known decibel value.
03

Calculating Intensity for 55.0 dB

Substitute \( L = 55.0 \, dB \) into the formula: \[ I = 10^{-12} \times 10^{(55/10)} \] Simplify the exponent: \[ I = 10^{-12} \times 10^{5.5} \] Calculate \( 10^{5.5} \) and multiply by \( 10^{-12} \). Using a calculator, \( 10^{5.5} \approx 316227.77 \), thus: \[ I \approx 3.1623 \times 10^{-7} \, W/m^2 \]
04

Calculating Intensity for 92.0 dB

Substitute \( L = 92.0 \, dB \) into the formula: \[ I = 10^{-12} \times 10^{(92/10)} \] Simplify the exponent: \[ I = 10^{-12} \times 10^{9.2} \] Calculate \( 10^{9.2} \) and multiply by \( 10^{-12} \). Using a calculator, \( 10^{9.2} \approx 15848931.9 \), thus: \[ I \approx 1.5849 \times 10^{-3} \, W/m^2 \]
05

Calculating Intensity for -2.0 dB

Substitute \( L = -2.0 \, dB \) into the formula: \[ I = 10^{-12} \times 10^{(-2/10)} \] Simplify the exponent: \[ I = 10^{-12} \times 10^{-0.2} \] Calculate \( 10^{-0.2} \) and multiply by \( 10^{-12} \). Using a calculator, \( 10^{-0.2} \approx 0.630957 \), thus: \[ I \approx 6.3096 \times 10^{-13} \, W/m^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Scale
The decibel (dB) is a logarithmic unit used to measure sound intensity. It's not linear like other measurement units, such as centimeters or meters. Instead, each 10 dB increase represents a tenfold increase in intensity because decibels use a logarithmic scale. Understanding this concept is important because it explains why sounds that aren't linearly spaced in dB have dramatically different intensity levels. Decibels are calculated using a specific formula that relates the sound's actual intensity to a reference intensity level. This reference intensity, denoted as \( I_0 \), is typically \( 10^{-12} \, W/m^2 \), which is considered the threshold of hearing. By using this scale, very large or small sound intensities can be expressed in manageable numbers.
Intensity Formula
To find the intensity of a sound from its decibel level, we use a rearranged form of the decibel formula. The original formula for decibels is: \[ L = 10 \times \log_{10} \left( \frac{I}{I_0} \right) \] Where \( L \) represents the decibels, \( I \) is the intensity of the sound in watts per square meter (W/m²), and \( I_0 \) is the reference intensity. When we want to solve for \( I \), we manipulate the formula to isolate \( I \):\[ I = I_0 \times 10^{(L/10)} \] This formula allows us to convert dB values to intensity directly, making tasks like those in the original exercise straightforward once you understand the relationship. In practical terms, you substitute the decibel value (\( L \)) into the formula and compute to find the actual intensity in \( W/m^2 \). This method is crucial for solving various physics problems involving sound.
Physics Problem-Solving
When dealing with physics problems, such as calculating sound intensity from decibels, a structured approach makes problem-solving much easier. Here are some helpful tips:- **Understand the Basics**: Start by familiarizing yourself with core concepts, like the decibel scale and intensity formula.- **Use Appropriate Formulas**: Identify which formula is applicable, and ensure you know how to rearrange it if needed. For intensity problems, that would be: \[ I = I_0 \times 10^{(L/10)} \]- **Substitute Carefully**: Plug the given values into the formula carefully to avoid mistakes. Check each step as you go.- **Calculate Accurately**: Use a calculator for the exponents if necessary, as these can often involve non-integer values.- **Cross-Check Units**: Make sure your final answer is in the correct units, often \( W/m^2 \) for intensity.By understanding these steps, you can approach physics problems with confidence, ensuring you have both the comprehension and skills to find the correct solutions. Remember that practice is key to mastering these types of questions.

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Most popular questions from this chapter

\(\bullet\) One end of a horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates at 120 \(\mathrm{Hz}\) . The other end passes over a pulley and supports a 1.50 \(\mathrm{kg}\) mass. The linear mass density of the rope is 0.0550 \(\mathrm{kg} / \mathrm{m}\) . (a) What is the speed of a transverse wave on the rope? (b) What is the wavelength? (c) How would your answers to parts (a) and (b) change if the mass were increased to 3.00 \(\mathrm{kg}\) ?

A bat flies toward a wall, emitting a steady sound of frequency 2000 \(\mathrm{Hz}\) . The bat hears its own sound, plus the sound reflected by the wall. How fast should the bat fly in order to hear a beat frequency of 10.0 \(\mathrm{Hz}\) ? (Hint: Break this problem into two parts, first with the bat as the source and the wall as the listener and then with the wall as the source and the bat as the listener.)

A piano tuner stretches a steel piano wire with a tension of 800 N. The wire is 0.400 m long and has a mass of 3.00 g. (a) What is the frequency of its fundamental mode of vibration? (b) What is the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 10,000 Hz?

A turntable 1.50 \(\mathrm{m}\) in diameter rotates at 75 \(\mathrm{rpm}\) . Two speakers, each giving off sound of wavelength \(31.3 \mathrm{cm},\) are attached to the rim of the table at opposite ends of a diameter. A listener stands in front of the turntable. (a) What is the greatest beat frequency the listener will receive from this system? (b) Will the listener be able to distinguish individual beats?

\(\cdot\) The role of the mouth in sound. The production of sound during speech or singing is a complicated process. Let's concentrate on the mouth. A typical depth for the human mouth is about \(8.0 \mathrm{cm},\) although this number can vary. (Check it against your own mouth.) We can model the mouth as an organ pipe that is open at the back of the throat. What are the wavelengths and frequencies of the first four harmonics you can produce if your mouth is (a) open, (b) closed? Use \(v=354 \mathrm{m} / \mathrm{s}\) .

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