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\(\bullet\) A 2.50 kg rock is attached at the end of a thin, very light rope 1.45 \(\mathrm{m}\) long and is started swinging by releasing it when the rope makes an \(11^{\circ}\) angle with the vertical. You record the observation that it rises only to an angle of \(4.5^{\circ}\) with the vertical after 10\(\frac{1}{2}\) swings. (a) How much energy has this system lost during that time? (b) What happened to the "lost" energy? Explain how it could have been "lost."

Short Answer

Expert verified
The system lost energy to air resistance and friction, converting it into thermal energy.

Step by step solution

01

Calculate Initial Potential Energy

The initial potential energy when the rock is at an angle of \(11^\circ\) can be calculated using \(PE = mgh\), where \(h = L - L \cos(\theta)\). First, find \(h\):\[h = 1.45\, \mathrm{m} - 1.45\, \mathrm{m} \cos(11^\circ)\]. Then compute the potential energy: \[PE_{\text{initial}} = 2.5\, \mathrm{kg} \times 9.8\, \mathrm{m/s^2} \times h\].
02

Calculate Final Potential Energy

The final potential energy when the rock is at an angle of \(4.5^\circ\) is calculated similarly: \[h' = 1.45\, \mathrm{m} - 1.45\, \mathrm{m} \cos(4.5^\circ)\]. Then compute the potential energy: \[PE_{\text{final}} = 2.5\, \mathrm{kg} \times 9.8\, \mathrm{m/s^2} \times h'\].
03

Calculate Energy Lost

Calculate the energy lost by subtracting the final potential energy from the initial potential energy: \[\text{Energy Lost} = PE_{\text{initial}} - PE_{\text{final}}\].
04

Explain Energy Loss

The lost energy is mainly due to air resistance and friction at the pivot point. These non-conservative forces convert some of the mechanical energy into thermal energy, which dissipates into the surroundings.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is a type of energy that is stored within an object due to its position relative to a reference point, often the ground. Imagine a rock attached to the end of a rope, like in the exercise we discussed. When the rock is pulled back to an angle and released, it has potential energy because of its elevated position. This energy depends on a few factors:
  • Mass of the rock (m): Heavier objects have more potential energy.
  • Gravity (g): On Earth, this is approximately 9.8 m/s².
  • Height (h): The vertical distance the rock is initially elevated, calculated from the angle and rope length.
The formula to calculate potential energy is given by: \[PE = m imes g imes h\]In our problem, the rock is released from 11 degrees, so we first need to find the height it reaches from this angle. The formula used is: \[h = L - L \cos(\theta)\]where \(L\) is the length of the rope and \(\theta\) is the angle. By plugging these values into our potential energy formula, we can determine how much potential energy the rock initially has.
Energy Loss
Energy loss occurs when the energy in a system decreases as it is transformed from one form to another. In our exercise, the rock on the rope swings back and forth like a pendulum. Initially, it has a certain potential energy. Over time, this energy seems to "disappear" as the rock does not rise to the same angle it started from. There are many different causes for energy loss:
  • Friction: When the rope rubs against the pivot point, it converts kinetic energy (movement energy) into thermal energy (heat), which dissipates into the surrounding air.
  • Air Resistance: As the rock swings, it cuts through the air, causing drag. This force works against the rock's motion, gradually slowing it down and converting mechanical energy into heat.
All these factors contribute to the energy "lost" from the swing system. By calculating the potential energy at different points (initial and final), we can understand how much energy the system has lost.
Non-conservative Forces
Non-conservative forces are forces where the work done is not recoverable as elastic potential energy. Unlike conservative forces, such as gravity and spring force, which are path-independent and store energy internally, non-conservative forces depend on the path taken and often transform kinetic into thermal energy, among others. In our pendulum exercise, the two primary non-conservative forces at play are friction and air resistance.
  • Friction at the pivot: As the rope swings back and forth, it may rub against its pivot point or even stretch slightly. This interaction converts mechanical energy into heat.
  • Air resistance: As the rock moves through the air, it faces resistance. This force not only slows down the swing but also dissipates mechanical energy as heat.
These non-conservative forces explain why mechanical energy in many systems, like our swinging rock, is not entirely conserved during motion. The energy is not lost in the universe, but rather transformed into forms that are no longer useful for doing work in this system.

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Most popular questions from this chapter

\(\bullet\) \(\bullet\) Four passengers with a combined mass of 250 \(\mathrm{kg}\) compress the springs of a car with wom-out shock absorbers by 4.00 \(\mathrm{cm}\) when they enter it. Model the car and passengers as a single body on a single ideal spring. If the loaded car has a period of vibration of \(1.08 \mathrm{s},\) what is the period of vibration of the empty car?

\(\bullet\) A steel wire 2.00 \(\mathrm{m}\) long with circular cross section must stretch no more than 0.25 \(\mathrm{cm}\) when a 400.0 \(\mathrm{N}\) weight is hung from one of its ends. What minimum diameter must this wire have?

\(\bullet\) You've made a simple pendulum with a length of 1.55 \(\mathrm{m}\) , and you also have a (very light) spring with force constant 2.45 \(\mathrm{N} / \mathrm{m} .\) What mass should you add to the spring so that its period will be the same as that of your pendulum?

\(\bullet\) \(\bullet\) Rapunzel, Rapunzel, let down your golden hair. In the Grimms' fairy tale Rapunzel, she lets down her golden hair to a length of 20 yards (we'll use \(20 \mathrm{m},\) which is not much different) so that the prince can climb up to her room. Human hair has a Young's modulus of about 490 MPa, and we can assume that Rapunzel's hair can be squeezed into a rope about 2.0 \(\mathrm{cm}\) in cross-sectional diameter. The prince is described as young and handsome, so we can estimate a mass of 60 \(\mathrm{kg}\) for him. (a) Just after the prince has started to climb at constant speed, while he is still near the bottom of the hair, by how many centimeters does he stretch Rapunzel's hair? (b) What is the mass of the heaviest prince that could climb up, given that the maximum tensile stress hair can support is 196 MPa? (Assume that Hooke's law holds up to the breaking point of the hair, even though that would not actually be the case.)

\(\bullet\) \(\bullet\) One end of a stretched ideal spring is attached to an airtrack and the other is attached to a glider with a mass of 0.355 \(\mathrm{kg}\) . The glider is released and allowed to oscillate in SHM. If the distance of the glider from the fixed end of the spring varies between 1.80 \(\mathrm{m}\) and \(1.06 \mathrm{m},\) and the period of the oscillation is \(2.15 \mathrm{s},\) find (a) the force constant of the spring, (b) the maximum speed of the glider, and (c) the magnitude of the maximum acceleration of the glider.

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