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. A uniform 4.5 \(\mathrm{kg}\) square solid wooden gate 1.5 \(\mathrm{m}\) on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.1 \(\mathrm{kg}\) raven flying horizontally at 5.0 \(\mathrm{m} / \mathrm{s}\) flies into this gate at its center and bounces back at 2.0 \(\mathrm{m} / \mathrm{s}\) in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved, but not the linear momentum?

Short Answer

Expert verified
(a) The angular speed of the gate is 1.71 rad/s. (b) Angular momentum is conserved as no external torques act on the system, while linear momentum isn't conserved due to external forces.

Step by step solution

01

Determine Initial and Final Linear Momentum of Raven

First, calculate the initial linear momentum of the raven. The initial momentum \( p_{i} \) is given by its mass \( m \) and velocity \( v \): \[ p_{i} = m v = 1.1 \, \text{kg} \times 5.0 \, \text{m/s} = 5.5 \, \text{kg} \cdot \text{m/s}. \]Now calculate the final linear momentum of the raven (as it bounces back): \[ p_{f} = 1.1 \, \text{kg} \times (-2.0 \, \text{m/s}) = -2.2 \, \text{kg} \cdot \text{m/s}. \]
02

Change in Linear Momentum of the Raven

Calculate the change in linear momentum of the raven. This is simply the difference between the initial and final momentum:\[ \Delta p = p_{f} - p_{i} = -2.2 \, \text{kg} \cdot \text{m/s} - 5.5 \, \text{kg} \cdot \text{m/s} = -7.7 \, \text{kg} \cdot \text{m/s}. \]
03

Initial Angular Momentum of the Raven

Because the raven hits the gate at its center, the distance from the pivot to the point of contact \( r \) is 0.75 m, half of the gate's width. The initial angular momentum about the pivot point is:\[ L_{i} = r \times p_{i} = 0.75 \, \text{m} \times 5.5 \, \text{kg} \cdot \text{m/s} = 4.125 \, \text{kg} \cdot \text{m}^2/\text{s}. \]
04

Final Angular Momentum of the Raven

Similarly, calculate the angular momentum after the collision:\[ L_{f} = r \times p_{f} = 0.75 \, \text{m} \times (-2.2) \, \text{kg} \cdot \text{m/s} = -1.65 \, \text{kg} \cdot \text{m}^2/\text{s}. \]
05

Angular Momentum Conservation

The total initial angular momentum must equal the total final angular momentum. So, \( L_{i} - L_{f} \) contributes to the gate's angular momentum:\[ L_{\text{gate, final}} = L_{i} - L_{f} = 4.125 \, \text{kg} \cdot \text{m}^2/\text{s} - (-1.65 \, \text{kg} \cdot \text{m}^2/\text{s}) = 5.775 \, \text{kg} \cdot \text{m}^2/\text{s}. \]
06

Moment of Inertia of the Gate

The moment of inertia \( I \) of a square gate pivoted at an edge can be calculated using \( I = \frac{1}{3} m L^2 \),where \( m = 4.5 \, \text{kg} \) and \( L = 1.5 \, \text{m} \):\[ I = \frac{1}{3} \times 4.5 \, \text{kg} \times (1.5 \, \text{m})^2 = 3.375 \, \text{kg} \cdot \text{m}^2. \]
07

Find the Angular Velocity of the Gate

Using the relationship \( L = I \omega \), solve for the angular velocity \( \omega \):\[ \omega = \frac{L_{\text{gate, final}}}{I} = \frac{5.775 \, \text{kg} \cdot \text{m}^2/\text{s}}{3.375 \, \text{kg} \cdot \text{m}^2} = 1.71 \, \text{rad/s}. \]
08

Explain Conservation of Angular Momentum

In this system, external forces might not affect rotational motion about the pivot (which is frictionless), conserving angular momentum. Linear momentum isn't conserved due to external forces, like gravity and the pivot force, acting on the gate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

conservation of momentum
The principle of conservation of momentum is a cornerstone in physics. It states that within a closed system, the total momentum before an event is equal to the total momentum after the event, provided no external forces are acting on it. In our problem, when the raven collides with the gate, we see two types of momentum at play: linear and angular momentum.

During the collision, the linear momentum isn't conserved because of external forces. Factors like gravity and friction can influence the system. Yet, the angular momentum is conserved. This happens because the pivot point is frictionless, allowing the system to be isolated internally concerning rotational motion.

Here's what happens:
  • The raven's impact imparts an initial angular momentum on the gate.
  • The gate then continues to move with this angular momentum because no external torque acts on it.
Consequently, angular momentum conservation ensures that the gate swings with a new angular velocity after the impact.
angular velocity
Angular velocity is a measure of how fast an object rotates about an axis. In this scenario, the collision causes the gate to start rotating. Angular velocity is denoted by the symbol \( \omega \) and has the units of radians per second.

When the raven hits the gate, its angular velocity can be determined by considering the transferred angular momentum. The angular velocity of the gate post-impact can be calculated using the formula:
  • \( \omega = \frac{L}{I} \)
Here, \( L \) is the angular momentum and \( I \) is the moment of inertia.

Understanding angular velocity is crucial:
  • It tells us how quickly the gate rotates after being struck.
  • It helps us see the relationship between torque, moment of inertia, and angular motion.
This example illustrates the transformation from linear motion of the raven to rotational motion of the gate, giving the gate a discernible angular velocity.
moment of inertia
The moment of inertia \( I \) is a measure of an object's resistance to rotation. It is analogous to mass in linear motion. For the gate in our problem, this determines how easily it can begin or stop spinning when external forces are applied.

For a square gate pivoting at an edge, the moment of inertia is determined by the formula:
  • \( I = \frac{1}{3} m L^2 \)
where \( m \) is the mass and \( L \) is the length of a side of the square.

The moment of inertia is vital because:
  • It depends on the mass and the distribution of that mass relative to the pivot point.
  • It affects how much angular momentum the object can attain for a given angular velocity.
In this exercise, knowing the gate's moment of inertia allows us to calculate how its angular velocity changes due to the collision, providing deeper insights into how rotational dynamics operate in real-world scenarios.

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Most popular questions from this chapter

A A large turntable rotates about a fixed vertical axis, making one revolution in 6.00 s. The moment of inertia of the turntable about this axis is 1200 \(\mathrm{kg} \cdot \mathrm{m}^{2} .\) A child of mass \(40.0 \mathrm{kg},\) initially standing at the center of the turntable, runs out along a radius. What is the angular speed of the turntable when the child is 2.00 \(\mathrm{m}\) from the center, assuming that you can treat the child as a particle?

\(\cdot\) A cord is wrapped around the rim of a wheel 0.250 \(\mathrm{m}\) in radius, and a steady pull of 40.0 \(\mathrm{N}\) is exerted on the cord. The wheel is mounted on frictionless bearings on a horizontal shaft through its center. The moment of inertia of the wheel about this shaft is 5.00 \(\mathrm{kg} \cdot \mathrm{m}^{2} .\) Compute the angular acceleration of the wheel.

\(\cdot\) What is the power output in horsepower of an electric motor turning at 4800 rev/min and developing a torque of 4.30 \(\mathrm{N} \cdot \mathrm{m}\) ?

\bullet Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star. The density of a neutron star is roughly \(10^{14}\) times as great as that of ordinary solid matter. Suppose we represent the star as a uniform, solid, rigid spiere, both before and after the collapse. The star's initial radius was \(7.0 \times 10^{5} \mathrm{km}\) (comparable to our sun); its final radius is 16 \(\mathrm{km}\) . If the original star rotated once in 30 days, find the angular speed of the neutron star.

Two people are carrying a uniform wooden board that is 3.00 \(\mathrm{m}\) long and weighs 160 \(\mathrm{N}\) . If one person applies an upward force equal to 60 \(\mathrm{N}\) at one end, at what point and with what force does the other person lift? Start with a free-body diagram of the board.

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