/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Two children are sitting on oppo... [FREE SOLUTION] | 91Ó°ÊÓ

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Two children are sitting on opposite ends of a uniform seesaw of negligible mass. (a) Can the seesaw be balanced if the masses of the children are different? How? (b) If a \(35-\mathrm{kg}\) child is \(2.0 \mathrm{~m}\) from the pivot point (or fulcrum), how far from the pivot point will her \(30-\mathrm{kg}\) playmate have to sit on the other side for the seesaw to be in equilibrium?

Short Answer

Expert verified
(a) Yes, by adjusting distances. (b) The playmate should sit approximately 2.33 m from the pivot.

Step by step solution

01

Determine Balance Condition

For the seesaw to be balanced, the torques on both sides of the pivot must be equal. Torque is calculated as the product of force (due to weight, which is mass times gravity) and distance from the pivot. This can be represented by the equation: \( m_1 \times d_1 = m_2 \times d_2 \).
02

Apply Balance Condition for Different Masses (Part a)

Yes, the seesaw can be balanced even if the children's masses are different. By adjusting their distances from the pivot (so one child is farther from the pivot if they are lighter), the torques can be made equal, thus balancing the seesaw.
03

Calculate Distance for Equilibrium (Part b)

Given: \( m_1 = 35 \, \text{kg}, \) \( d_1 = 2.0 \, \text{m}, \) and \( m_2 = 30 \, \text{kg} \). Use the torque balance equation: \( m_1 \times d_1 = m_2 \times d_2 \). Substitute the known values: \( 35 \, \text{kg} \times 2.0 \, \text{m} = 30 \, \text{kg} \times d_2 \). Solve for \( d_2 \) by dividing both sides by \( 30 \, \text{kg} \), giving \( d_2 = \frac{70}{30} \approx 2.33 \, \text{m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque
Torque is a fundamental concept in physics that refers to the rotational force applied around a pivot point or fulcrum. It can be thought of as a measure of how much a force acting on an object causes that object to rotate. The amount of torque depends on two factors: the magnitude of the force applied and the distance from the pivot point at which it is applied. This distance is often called the lever arm. The formula for torque can be expressed as: \ \( \tau = F \times d \) \ where \( \tau \) is the torque, \( F \) is the force applied, and \( d \) is the distance from the pivot.
  • Torque acts in a direction: clockwise or counterclockwise.
  • In equilibrium, the sum of clockwise torque must equal the sum of counterclockwise torque.
Understanding this helps us solve problems involving seesaws and other scenarios where rotation about a pivot is significant.
Equilibrium
Equilibrium in physics is the state where all forces and torques are balanced. This means that an object in equilibrium is either at rest or moving at a constant velocity without accelerating. For a seesaw to be in equilibrium, the clockwise torque needs to match exactly the counterclockwise torque. This balance ensures the seesaw remains level and stable, without tipping to one side. There are two types of equilibrium:
  • Static Equilibrium: When an object is at rest, and there is no net force or torque acting on it, like a balanced seesaw.
  • Dynamic Equilibrium: When an object moves with constant speed, maintaining a consistent state.
In the seesaw exercise, achieving equilibrium required calculations to find the correct distances each child needed to sit from the pivot, ensuring both sides exert equal torques.
Seesaw Balance
A seesaw is a practical example of the torque and equilibrium concepts. Balancing a seesaw involves ensuring that the weight and distance from the pivot on one side equals that on the other side. While it might seem tricky when participants have different weights, balance can still be achieved by compensating with distance. If one child is heavier, they will be closer to the pivot, and the lighter child will sit further away. This configuration ensures that the torques and thus the forces on both sides are similar. By adjusting these parameters, the seesaw can achieve stability and balance.
Using the balance equation \( m_1 \times d_1 = m_2 \times d_2 \), we can calculate where each child needs to sit so that the seesaw does not tip over.
Lever Principle
The lever principle is key to understanding balance scenarios, like on a seesaw. This principle states that a lever amplifies an input force to provide a greater output force, allowing heavier objects or a load to be lifted or balanced. The seesaw acts as a lever, with each child representing an input force and the pivot acting as the fulcrum. The lever principle can be summarized as follows:
  • Effort force multiplied by its distance from the fulcrum is equal to the load force multiplied by its distance from the fulcrum.
  • This means balance can still be struck even if the weights (forces) differ, by varying their distances from the fulcrum.
This concept is a building block in physics, illustrating how small force changes at greater distances can create equilibrium. Using calculations, a balance on the seesaw can be achieved by applying the lever principle effectively.

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Most popular questions from this chapter

A \(10.0-\mathrm{kg}\) solid uniform cube with 0.500 -m sides rests on a level surface. What is the minimum amount of work necessary to put the cube into an unstable equilibrium position?

A ball with a radius of \(15 \mathrm{~cm}\) rolls on a level surface, and the translational speed of the center of mass is \(0.25 \mathrm{~m} / \mathrm{s}\). What is the angular speed about the center of mass if the ball rolls without slipping?

A steel ball rolls down an incline into a loop-theloop of radius \(R\) (v Fig. 8.52a). (a) What minimum speed must the ball have at the top of the loop in order to stay on the track? (b) At what vertical height \((h)\) on the incline, in terms of the radius of the loop, must the ball be released in order for it to have the required minimum speed at the top of the loop? (Neglect frictional losses.) (c) Figure \(8.52 \mathrm{~b}\) shows the loop-the-loop of a roller coaster. What are the sensations of the riders if the roller coaster has the minimum speed or a greater speed at the top of the loop? [Hint: In case the speed is below the minimum, seat and shoulder straps hold the riders in.

A 2.5 -kg pulley of radius \(0.15 \mathrm{~m}\) is pivoted about an axis through its center. What constant torque is required for the pulley to reach an angular speed of \(25 \mathrm{rad} / \mathrm{s}\) after rotating 3.0 revolutions, starting from rest?

A hoop starts from rest at a height \(1.2 \mathrm{~m}\) above the base of an inclined plane and rolls down under the influence of gravity. What is the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface? (Neglect friction.)

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