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An Indy car with a speed of \(120 \mathrm{~km} / \mathrm{h}\) goes around a level, circular track with a radius of \(1.00 \mathrm{~km} .\) What is the centripetal acceleration of the car?

Short Answer

Expert verified
The centripetal acceleration of the car is approximately \(1.11 \text{ m/s}^2\).

Step by step solution

01

Understand the Problem

We are given a circular track with a radius \( r = 1.00 \text{ km} = 1000 \text{ m} \), and a car moving with a speed \( v = 120 \text{ km/h} = 33.33 \text{ m/s} \). We need to calculate the centripetal acceleration of the car.
02

Recall the Centripetal Acceleration Formula

The formula for centripetal acceleration \( a_c \) is given by \( a_c = \frac{v^2}{r} \), where \( v \) is the velocity and \( r \) is the radius of the circular path.
03

Substitute Values into the Formula

Substitute \( v = 33.33 \text{ m/s} \) and \( r = 1000 \text{ m} \) into the formula: \[ a_c = \frac{(33.33)^2}{1000} \].
04

Perform the Calculation

Calculate the value:\[ a_c = \frac{1111.0889}{1000} \approx 1.11 \text{ m/s}^2 \].
05

Interpret the Result

The centripetal acceleration is \(1.11 \text{ m/s}^2\), meaning this is the acceleration necessary to keep the car moving in a circle at the given speed without changing its speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
When a car moves around a circular track, it is said to be in circular motion. This is a type of motion where an object follows a circular path due to an inward center-directed force. For an Indy car racing around a circular track, this force results from the friction between the car's tires and the track surface. Without this centripetal force, the car would move off in a straight line due to inertia. In this scenario, circular motion keeps the car traveling along the curve by continually changing its direction, though its speed stays constant. The concept of circular motion is essential to understanding scenarios where an object is constrained to spin around a central point, like satellites orbiting a planet or the motion of a Ferris wheel.
Physics Problem-Solving
Solving physics problems, like determining centripetal acceleration, involves a methodical approach to break down the problem. The first step is understanding what is given and what is being asked. In our example, we know the speed of the car and the radius of the track. Next, recalling relevant physics formulas is key. Here, the formula for centripetal acceleration helps us establish a clear path to the solution. Substitution involves replacing symbols with numbers from the problem. This step translates abstract relationships into specific calculations. Finally, calculating and interpreting the result helps verify the answer's reasonability and transforms numbers into meaningful insights. Successful physics problem-solving is like piecing together a logical puzzle.
Kinematics
Kinematics is the study of motion without considering forces. It helps us describe how objects move through space over time. We often analyze motion using parameters like velocity, displacement, and acceleration. In circular motion, understanding the linear velocity (the speed of the car) is crucial. This velocity informs how quickly the car travels along its path. The centripetal acceleration is the inward acceleration required for circular motion, computed from the velocity squared over the radius. These components of kinematics allow us to model and predict the motion of objects moving in a constant path. It provides insights into how changes in these parameters affect the overall movement trajectory.
Velocity Conversion
In physics, converting units is essential for accurate calculations. Velocity conversion is the process of changing a speed measurement from one unit to another. In our example, the car's speed was initially given in kilometers per hour. To solve the problem, it was converted into meters per second, the standard SI unit for speed. This involves using the conversion factor where 1 kilometer equals 1000 meters and 1 hour equals 3600 seconds. By dividing the speed by 3.6, we switch from km/h to m/s: \[ v = \frac{120 \ ext{km/h}}{3.6} = 33.33 \ ext{m/s} \] This practice ensures consistency in physics equations, avoiding unit-related errors. Whether for speed, distance, or time, converting units helps maintain clarity and precision in problem-solving.

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