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A 0.150 -kg baseball traveling with a horizontal speed of \(4.50 \mathrm{~m} / \mathrm{s}\) is hit by a bat and then moves with a speed of \(34.7 \mathrm{~m} / \mathrm{s}\) in the opposite direction. What is the change in the ball's momentum?

Short Answer

Expert verified
The change in the baseball's momentum is \(-5.880\, \mathrm{kg \, m/s}\).

Step by step solution

01

Understand the Momentum Formula

The momentum of an object is given by the formula \( p = mv \), where \( p \) is the momentum, \( m \) is the mass, and \( v \) is the velocity.
02

Calculate Initial Momentum

The initial momentum of the baseball is calculated using its initial velocity and mass. The initial velocity is \( 4.50 \mathrm{~m/s} \), and the mass is \( 0.150 \mathrm{~kg} \). Thus, the initial momentum \( p_i = (0.150) \times (4.50) \).
03

Calculate Initial Momentum Value

Calculate the initial momentum. \( p_i = 0.150 \times 4.50 = 0.675 \mathrm{~kg \, m/s} \).
04

Calculate Final Momentum

The baseball's final velocity is \(-34.7 \mathrm{~m/s}\), as it travels in the opposite direction. The final momentum \( p_f = (0.150) \times (-34.7) \).
05

Calculate Final Momentum Value

Calculate the final momentum. \( p_f = 0.150 \times (-34.7) = -5.205 \mathrm{~kg \, m/s} \).
06

Calculate Change in Momentum

To find the change in momentum, subtract the initial momentum from the final momentum. \( \Delta p = p_f - p_i = -5.205 - 0.675 \).
07

Calculate Change in Momentum Value

Perform the subtraction to find the change in momentum. \( \Delta p = -5.205 - 0.675 = -5.880 \mathrm{~kg \, m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision Physics
Collisions are fascinating events in physics where two or more objects come into contact with each other, exchanging energy and momentum. They are particularly interesting because they can be elastic or inelastic.
In an elastic collision, both momentum and kinetic energy are conserved. Objects bounce off each other without losing speed or energy. Picture a perfectly bouncy ball that doesn't slow down when it hits the ground.
In contrast, in an inelastic collision, momentum is conserved, but kinetic energy is not. Some of the kinetic energy is converted into other forms of energy, like heat or sound, or it may be used to deform the objects. Think of a car crash where vehicles crumple and produce sound.
  • Collisions can occur in one dimension (straight line) or in two or three dimensions, depending on the nature of the interacting bodies.
  • They significantly impact the velocity and motion direction of involved objects, as seen in the baseball and bat example.
  • Understanding collision types helps in determining how energy and speed change.
As collisions are so common in the physical world, grasping the underlying principles can help us predict outcomes in real-life situations, such as sports and transportation safety.
Conservation of Momentum
The conservation of momentum is a principle that states the total momentum of a closed system remains the same if no external forces act on it. Momentum, a product of an object's mass and velocity, is a vital quantity demonstrating this principle.
In the exercise, after the baseball collides with the bat, calculating the change in momentum involves considering the direction of the velocities. Knowing the velocity changes direction, we can still apply the conservation of momentum rationale.
  • Before and after the collision, total momentum remains equal, although individual momentums of objects can change.
  • In our baseball example, the initial and final momentum calculations consider the same mass and different velocities, one positive and one negative due to direction.
  • The calculation highlights how the velocity switch significantly impacts momentum's value, reinforcing the need to include direction when addressing momentum issues.
The conservation of momentum provides a mathematical approach for analyzing and solving collision-related physics problems by confidently predicting outcomes based on initial conditions.
Physics Problem Solving
Solving physics problems requires a systematic approach and an understanding of key principles. Mastering this skill is crucial for success in physics and engineering.
The baseball question highlights essential steps:
  • Familiarize yourself with relevant formulas. For momentum, use: \( p = mv \).
  • Organize known quantities. Here, we know the baseball's mass and its initial and final velocities.
  • Calculate step by step. First find initial momentum, then final, and finally the change: \( \Delta p = p_f - p_i \).
  • Pay attention to vectors; velocity is a vector quantity, which means direction matters. This is clearly seen as the velocity changes direction when the baseball is hit.
Adopting structured methods allows for consistent solutions. They offer clarity and verify results are accurate and logical. By following these steps, students can effectively navigate complex scenarios and solve diverse physics problems across multiple contexts.

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Most popular questions from this chapter

In football practice, two wide receivers run different pass receiving patterns. One with a mass of \(80.0 \mathrm{~kg}\) runs at \(45^{\circ}\) northeast at a speed of \(5.00 \mathrm{~m} / \mathrm{s}\). The second receiver (mass of \(90.0 \mathrm{~kg}\) ) runs straight down the field (due east) at \(6.00 \mathrm{~m} / \mathrm{s}\). (a) What is the direction of their total momentum: (1) exactly northeast, (2) to the north of northeast, (3) exactly east, or (4) to the east of northeast? (b) Justify your answer in part (a) by actually computing their total momentum.

A 90-\mathrm{kg}\( astronaut is stranded in space at a point \)6.0 \mathrm{~m}\( from his spaceship, and he needs to get back in 4.0 min to control the spaceship. To get back, he throws a \)0.50-\mathrm{kg}\( piece of equipment so that it moves at a speed of \)4.0 \mathrm{~m} / \mathrm{s}$ directly away from the spaceship. (a) Does he get back in time? (b) How fast must he throw the piece of equipment so he gets back in time?

A \(4.0-\mathrm{kg}\) ball with a velocity of \(4.0 \mathrm{~m} / \mathrm{s}\) in the \(+x\) -direction collides head-on elastically with a stationary \(2.0-\mathrm{kg}\) ball. What are the velocities of the balls after the collision?

A ball of mass \(200 \mathrm{~g}\) is released from rest at a height of \(2.00 \mathrm{~m}\) above the floor and it rebounds straight up to a height of \(0.900 \mathrm{~m}\). (a) Determine the ball's change in momentum due to its contact with the floor. (b) If the contact time with the floor was \(0.0950 \mathrm{~s}\), what was the average force the floor exerted on the ball, and in what direction?

Shows a bird catching a fish. Assume that initially the fish jumps up and that the bird coasts horizontally and does not touch the water with its feet or flap its wings. (a) Is this kind of collision (1) elastic, (2) inelastic, or (3) completely inelastic? Why? (b) If the mass of the bird is \(5.0 \mathrm{~kg}\), the mass of the fish is \(0.80 \mathrm{~kg}\), and the bird coasts with a speed of \(6.5 \mathrm{~m} / \mathrm{s}\) before grabbing, what is the speed of the bird after grabbing the fish?

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