Chapter 5: Problem 20
If a \(10-\mathrm{N}\) force is used to compress a spring with a spring constant of \(4.0 \times 10^{2} \mathrm{~N} / \mathrm{m},\) what is the resulting spring compression?
Short Answer
Expert verified
The spring is compressed by 0.025 meters.
Step by step solution
01
Understand the Problem
We have a spring with a spring constant (k) of \(4.0 \times 10^{2} \text{ N/m}\) and a force (F) of \(10 \text{ N}\) applied to compress it. We need to find the spring compression (x).
02
Recall Hooke's Law
Hooke's Law states that the force needed to compress or extend a spring by some distance (x) is proportional to that distance. It is expressed as \(F = kx\), where \(F\) is the force applied, \(k\) is the spring constant, and \(x\) is the displacement/compression of the spring.
03
Rearrange Hooke's Law to Solve for x
We want to find the compression \(x\). Rearrange the formula \(F = kx\) to solve for \(x\). This gives us \(x = \frac{F}{k}\).
04
Substitute the Values into the Formula
Plug in the given values into the equation \(x = \frac{F}{k}\). Here, \(F = 10 \text{ N}\) and \(k = 4.0 \times 10^{2} \text{ N/m}\). The equation becomes:\[x = \frac{10}{4.0 \times 10^{2}}\]
05
Calculate the Compression x
Perform the division to calculate the spring compression:\[x = \frac{10}{400} = 0.025 \, \text{m}\]This means the spring is compressed by 0.025 meters.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Spring Constant
The spring constant, denoted as "k", is a crucial factor in understanding how springs work. It measures a spring's stiffness—the higher the spring constant, the stiffer the spring. In scientific terms, the spring constant tells us the force needed to stretch or compress a spring by a unit length. For example, if a spring has a constant of 400 N/m, this means you would need 400 Newtons of force to compress or stretch it by 1 meter.
Here's what you should remember about the spring constant:
Here's what you should remember about the spring constant:
- Measured in Newtons per meter (N/m).
- A higher value implies a stiffer spring, while a lower value indicates a more flexible spring.
- Helps determine how much a spring will compress or stretch under a given force.
Force and Displacement
Hooke's Law forms the basis of the relationship between force and displacement in springs. It states that the force exerted by a spring is directly proportional to the amount it is stretched or compressed. This is expressed through the equation: \( F = kx \).
In this formula:
In this formula:
- \( F \) represents the force applied to the spring.
- \( k \) is the spring constant, measuring the spring's stiffness.
- \( x \) is the displacement, which is the change in length of the spring.
- A positive displacement signifies stretching.
- A negative displacement indicates compression.
Spring Compression Calculation
Calculating the compression of a spring involves rearranging Hooke's Law to solve for the displacement or compression distance (\( x \)). This can be done using the formula: \( x = \frac{F}{k} \), where \( F \) is the applied force, and \( k \) is the spring constant.
To understand the calculation:
This means the spring is compressed by 0.025 meters, showing that even a small amount of force can result in a noticeable change in spring length. This understanding is key to solving problems involving springs.
To understand the calculation:
- Identify the force \( F \) being applied to compress the spring.
- Identify the spring constant \( k \).
- Use the formula to find the compression \( x \).
This means the spring is compressed by 0.025 meters, showing that even a small amount of force can result in a noticeable change in spring length. This understanding is key to solving problems involving springs.