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(a) A horizontal force acts on an object on a frictionless horizontal surface. If the force is halved and the mass of the object is doubled, the acceleration will be (1) four times, (2) two times, (3) one-half, (4) one-fourth as great. (b) If the acceleration of the object is \(1.0 \mathrm{~m} / \mathrm{s}^{2},\) and the force on it is doubled and its mass is halved, what is the new acceleration?

Short Answer

Expert verified
(a) One-fourth; (b) 4.0 m/s².

Step by step solution

01

Understand the Relationship

According to Newton's Second Law, the acceleration \(a\) of an object is given by \(a = \frac{F}{m}\), where \(F\) is the force and \(m\) is the mass of the object.
02

Analyze Changes in Force and Mass for Part (a)

If the force \(F\) is halved and the mass \(m\) is doubled, the new acceleration \(a'\) can be expressed as \(a' = \frac{\frac{1}{2}F}{2m} = \frac{F}{4m}\).
03

Determine the Effect on Acceleration for Part (a)

The new expression for acceleration \(a' = \frac{F}{4m}\) indicates that the acceleration is reduced by a factor of 4. Hence, the acceleration is one-fourth as great.
04

Given Acceleration and Analyze Changes for Part (b)

Initially, \(a = 1.0 \ \mathrm{m/s^2}\). For the second scenario, the force is doubled, and the mass is halved, causing the new acceleration \(a' = \frac{2F}{\frac{1}{2}m} = \frac{4F}{m}\).
05

Calculate New Acceleration for Part (b)

The new acceleration is calculated as \(a' = 4 \cdot 1.0 \ \mathrm{m/s^2} = 4.0 \ \mathrm{m/s^2}\), given the force has doubled and the mass halved.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration
Acceleration is a crucial concept in understanding how objects move when acted upon by force. It is defined as the rate at which an object's velocity changes with time. To grasp this concept, you should know that acceleration depends directly on the force applied and inversely on the mass of the object.

This relationship is mathematically expressed by Newton's Second Law of Motion as \( a = \frac{F}{m} \), where \( a \) is acceleration, \( F \) is the force applied to the object, and \( m \) is the object's mass. If you increase the force applied to the object while keeping its mass constant, the acceleration increases. Conversely, increasing the mass while keeping the force constant will decrease the acceleration.

In problems where the force or mass changes, such as the ones you're working on, understanding this relationship helps you determine how acceleration is affected. For example, when the force is halved and the mass doubled, the acceleration becomes one-fourth as seen in the exercise provided.
Force and Mass Relationship
Force and mass have a clear and straightforward relationship described by Newton's Second Law. This law states that force is directly proportional to both mass and acceleration, which is represented as \( F = ma \).

In practical terms, if you double the mass of an object but keep the force constant, the acceleration will be halved, assuming a frictionless environment. Similarly, if you double the force while keeping the mass constant, the acceleration will double. These adjustments help us solve physics problems accurately by predicting the motion of objects.

When changes occur, like the halving of the force or doubling of mass, the calculations must adjust accordingly. It's important to always check both factors - force and mass - as they play a pivotal role in determining how fast an object speeds up or slows down. This understanding is central to solving the problems in your exercise.
Frictionless Surface Dynamics
In a frictionless environment, such as a smooth icy surface, objects move without any resistance slowing them down. This concept is crucial for understanding physics problems, as it simplifies calculations by focusing only on force and mass.

When dealing with frictionless surface dynamics, the only forces to consider are those applied directly to the object (i.e., pushing or pulling forces). The lack of friction means the object won't naturally slow down over time by itself. Thus, any change in motion is due to changes in force and mass alone.

This means exercises working with frictionless surfaces are often more straightforward and focus on ideal conditions. For example, in the problems you have, the calculations assume this ideal condition. When you see words like "frictionless," know that it signals a simpler setup where acceleration calculations directly follow changes in force and mass as per Newton's laws.

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Most popular questions from this chapter

In an Olympic figure-skating event, a 65-kg male skater pushes a \(45-\mathrm{kg}\) female skater, causing her to accelerate at a rate of \(2.0 \mathrm{~m} / \mathrm{s}^{2}\). At what rate will the male skater accelerate? What is the direction of his acceleration?

To haul a boat out of the water for the winter, a worker at the storage facility uses a wide strap with cables operating at the same angle (measured from the horizontal) on either side of the boat (vFig. 4.48 ). (a) As the boat comes up vertically and \(\theta\) decreases, the tension in the cables (1) increases, (2) decreases, (3) stays the same. (b) Determine the tension in each cable if the boat has a mass of \(500 \mathrm{~kg}\) and the angle of each cable is \(45^{\circ}\)

IE .?? Three horizontal forces (the only horizontal ones) act on a box sitting on a floor. One (call it \(F_{1}\) ) acts due east and has a magnitude of \(150 \mathrm{lb}\). A second force (call it \(F_{2}\) ) has an easterly component of \(30.0 \mathrm{lb}\) and a southerly component of \(40.0 \mathrm{lb}\). The box remains at rest. (Neglect friction.) (a) Sketch the two known forces on the box. In which quadrant is the unknown third force: (1) the first quadrant; (2) the second quadrant; (3) the third quadrant; or (4) the fourth quadrant? (b) Find the unknown third force in newtons and compare your answer to the sketched estimate.

One mass, \(m_{1}=0.215 \mathrm{~kg},\) of an ideal Atwood machine (see Fig. 4.42) rests on the floor \(1.10 \mathrm{~m}\) below the other mass, \(m_{2}=0.255 \mathrm{~kg},\) (a) If the masses are released from rest, how long does it take \(m_{2}\) to reach the floor? (b) How high will mass \(m_{1}\) ascend from the floor? (Hint: When \(m_{2}\) hits the floor, \(m_{1}\) continues to move upward.)

An object (mass \(3.0 \mathrm{~kg}\) ) slides upward on a vertical wall at constant velocity when a force \(F\) of \(60 \mathrm{~N}\) acts on it at an angle of \(60^{\circ}\) to the horizontal. (a) Draw the freebody diagram of the object. (b) Using Newton's laws find the normal force on the object. (c) Determine the force of kinetic friction on the object.

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