/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 The work function of a surface i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The work function of a surface is \(5.0 \times 10^{-19} \mathrm{~J}\). If light of wavelength of \(300 \mathrm{nm}\) is incident on the surface, what is the maximum kinetic energy of the photoelectrons ejected from the surface?

Short Answer

Expert verified
The maximum kinetic energy is \(1.63 \times 10^{-19} \mathrm{~J}\).

Step by step solution

01

Understanding the Problem

The exercise is about finding the maximum kinetic energy of photoelectrons ejected due to incident light on a surface. We need to utilize the photoelectric effect principle, which highlights the relationship between the energy of incident light, work function of the material, and the kinetic energy of ejected electrons.
02

Calculate the Energy of the Incident Photons

Use the equation for the energy of a photon: \[ E = \frac{hc}{\lambda} \]where \( h = 6.63 \times 10^{-34} \text{ J}\cdot\text{s} \) is Planck's constant, \( c = 3 \times 10^8 \text{ m/s} \) is the speed of light, and \( \lambda = 300 \times 10^{-9} \text{ m} \) is the wavelength. Substituting these into the equation:\[ E = \frac{(6.63 \times 10^{-34})(3 \times 10^8)}{300 \times 10^{-9}} \text{ J} \]Calculate this energy.
03

Compute the Maximum Kinetic Energy

According to the photoelectric effect, the maximum kinetic energy \( E_k \) is given by:\[ E_k = E - \phi \]where \( E \) is the photon energy calculated in Step 2 and \( \phi = 5.0 \times 10^{-19} \text{ J} \) is the work function of the material. Substitute the values to find \( E_k \).
04

Final Calculation

Continuing from Step 2, after calculating the energy of the photon:\[ E = 6.63 \times 10^{-19} \text{ J} \]Now substitute \( E \) and \( \phi \) into the equation for maximum kinetic energy:\[ E_k = 6.63 \times 10^{-19} - 5.0 \times 10^{-19} \]Calculate to find \( E_k = 1.63 \times 10^{-19} \text{ J} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work Function
The work function, often denoted as \( \phi \), is a crucial concept in understanding the photoelectric effect. It refers to the minimum energy required to remove an electron from the surface of a material. This property varies depending on the material. When light shines on a material, only photons with energy greater than the work function can successfully eject electrons. For the photoelectric effect to occur, the photon's energy must exceed this threshold.
  • The specific value indicates the energy needed for electron liberation.
  • It acts as a barrier or threshold for the ejection of electrons.
  • In our example, the work function is given as \(5.0 \times 10^{-19} \text{ J}\).
Understanding the work function helps us determine the energy balance required for exciting the photoelectron. Only when photon energy surpasses this work function will any leftover energy be converted into the kinetic energy of the electron.
Photon Energy
Photon energy is the energy carried by a single photon and is directly related to its wavelength or frequency. It's calculated using the formula \( E = \frac{hc}{\lambda} \), where \( h \) is Planck's constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength of the photon. This equation highlights two key points:
  • Shorter wavelengths (higher frequency) will result in higher photon energies.
  • The more energetic a photon is, the more potential energy it has to release electrons from a surface.
For instance, with a wavelength of \(300 \text{ nm}\), the energy of the photon calculated is approximately \(6.63 \times 10^{-19} \text{ J}\). By understanding photon energy, you can predict how different sources of light will interact with various materials, influencing their photoelectric response.
Kinetic Energy of Electrons
The kinetic energy of electrons is the energy they possess due to their motion after being ejected by photon impact. In the context of the photoelectric effect, this is the energy leftover after accounting for the energy used to overcome the work function. It can be determined by the equation \( E_k = E - \phi \), where \( E_k \) is the kinetic energy, \( E \) is the photon energy, and \( \phi \) is the work function.
  • Maximum kinetic energy is calculated when the photon's energy exceeds the work function.
  • Gives insights into how energetic the electrons will be once they are free from the material.
In our practical example, after substituting the known values, the maximum kinetic energy of the photoelectrons is found to be \(1.63 \times 10^{-19} \text{ J}\). This demonstrates how the excess energy from the photon, after overcoming the work function, translates into the electron's motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A hydrogen atom has an ionization energy of \(13.6 \mathrm{eV}\). When it absorbs a photon with an energy greater than this energy, the electron will be emitted with some kinetic energy. (a) If the energy of such a photon is doubled, the kinetic energy of the emitted electron will (1) more than double, (2) remain the same, (3) exactly double, (4) increase, but less than double. Why? (b) Photons associated with light of a frequency of \(7.00 \times 10^{15} \mathrm{~Hz}\) and \(1.40 \times 10^{16} \mathrm{~Hz}\) are absorbed by a hydrogen atom. What is the kinetic energy of the emitted electron?

If you have a fever, is the wavelength of the radiation component of maximum intensity emitted by your body (1) greater, (2) the same, or (3) smaller as compared with its value when your temperature is normal? Why? (b) Assume that human skin has a temperature of \(34^{\circ} \mathrm{C}\). What is the wavelength of the radiation component of maximum intensity emitted by our bodies? In what region of the EM spectrum is this wavelength?

When light of wavelength of \(250 \mathrm{nm}\) is incident on a metal surface, the maximum speed of the photoelectrons is \(4.0 \times 10^{5} \mathrm{~m} / \mathrm{s}\). What is the work function of the metal in eV?

For which of the following transitions in a hydrogen atom is the photon of longest wavelength emitted: (1) \(n=5\) to \(n=3,\) (2) \(n=6\) to \(n=2,\) or \((\) 3) \(n=2\) to \(n=1 ?(\mathrm{~b})\) Justify your answer mathematically.

Light of wavelength \(340 \mathrm{nm}\) is incident on a metal surface and ejects electrons that have a maximum speed of \(3.5 \times 10^{5} \mathrm{~m} / \mathrm{s}\). (a) What is the work function of the metal? (b) What is its stopping voltage? (c) What is its threshold wavelength?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.