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A person is prescribed with contact lenses that have powers of \(-3.0 \mathrm{D}\). What type of lenses are these? What is the lenses' focal length?

Short Answer

Expert verified
The lenses are diverging, with a focal length of -0.333 meters.

Step by step solution

01

Understanding Lens Power and Type

The power of a lens is given in diopters ( ext{D}), which can be either positive or negative. Positive diopter values indicate converging lenses, while negative values indicate diverging lenses. Since the power of the lenses is \(-3.0 \text{ D}\), these are diverging lenses.
02

Calculating the Focal Length

The formula to find the focal length \(f\) of a lens, given its power \(P\), is: \[ f = \frac{1}{P} \] Substituting the given power: \[ f = \frac{1}{-3.0} = -0.3333 \text{ meters} \] Hence, the focal length of these lenses is approximately \(-0.3333\text{m}\), or \(-33.33\text{cm}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length
Focal length is an essential property of lenses, allowing us to determine how strongly the lens converges or diverges light. It represents the distance from the lens where parallel rays of light either converge (in the case of converging lenses) or appear to diverge from (for diverging lenses). Understanding the focal length helps in defining the behavior and application of a lens.

To calculate the focal length, you can use the formula:
  • \[f = \frac{1}{P}\]
Here, \( f \) is the focal length in meters, and \( P \) is the lens power in diopters. For a lens with a negative power, the focal length will also be negative, indicating a diverging function.

In our example, the lens power is \(-3.0 \text{ D}\), leading to a focal length of approximately \(-0.3333 \text{ m}\) or \(-33.33 \text{ cm}\). This signifies that the lens is a diverging lens that influences light rays to spread out as if they are coming from a focal point 33.33 cm behind the lens.
Diopter
Diopter is the unit of measurement for the optical power of a lens. It signifies how much the lens bends light. The diopter value, abbreviated D, is the reciprocal of the focal length measured in meters.

The relationship between diopter and focal length is crucial for understanding lens specifications:
  • A lens with a positive diopter (+D) is classified as a converging lens, which brings light rays together.
  • A lens with a negative diopter (-D) is identified as a diverging lens, which spreads light rays apart.
The formula to relate these is simply:
  • \[D = \frac{1}{f}\]
Where \( D \) is the power in diopters and \( f \) is the focal length in meters. This unit is widely used in optics to describe prescriptions for corrective lenses. In our specific situation, the lenses have a power of \(-3.0 \text{ D}\), indicating strong divergence capacity.
Diverging Lenses
Diverging lenses, also known as concave lenses, are characterized by their ability to spread light rays outwards. These lenses are thinner at the center than at the edges.

They take parallel incoming light rays and make them diverge as if they originate from a principal focal point behind the lens. Here are some key characteristics of diverging lenses:
  • They have a negative focal length, which is indicative of their divergence.
  • They are used to correct nearsightedness (myopia), allowing a person to see distant objects more clearly by spreading rays more outwardly.
  • In practical applications, they are often utilized in devices like cameras and binoculars to manage image dimensions, aiding in the correction of vision.
In our case, the lens in question is diverging, as evidenced by its negative power of \(-3.0 \text{ D}\) and negative focal length. This ensures that light rays diverge, increasing the visual field of view for the wearer.

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Most popular questions from this chapter

Two astronomical telescopes have the characteristics shown in the following table: $$ \begin{array}{cccc} \text { Telescope } & \begin{array}{c} \text { Objective } \\ \text { Focal Length (cm) } \end{array} & \begin{array}{c} \text { Eyepiece Focal } \\ \text { Length (cm) } \end{array} & \begin{array}{c} \text { Objective } \\ \text { Diameter (cm) } \end{array} \\ \hline \text { A } & 90.0 & 0.840 & 75.0 \\ \text { B } & 85.0 & 0.770 & 60.0 \end{array} $$ (a) Which telescope would you choose (1) for best magnification? (2) for best resolution? Explain. (b) Calculate the maximum magnification and the minimum resolving angle for a wavelength of \(550 \mathrm{nm}\).

You are given two objectives and two eyepieces and are instructed to make a telescope with them. The focal lengths of the objectives are \(60.0 \mathrm{~cm}\) and \(40.0 \mathrm{~cm}\) and the focal lengths of the eyepieces are \(0.90 \mathrm{~cm}\) and \(0.80 \mathrm{~cm} .\) (a) Which lens combination would you pick if you want to have maximum magnification? How about minimum magnification? Explain. (b) Calculate the maximum and minimum magnifications.

A compound microscope has an objective with a focal length of \(4.00 \mathrm{~mm}\) and an eyepiece with a magnification of \(10.0 \times\). If the objective and eyepiece are \(15.0 \mathrm{~cm}\) apart, what is the total magnification of the microscope?

If a magnifying glass gives an angular magnification of \(1.5 \times\) when viewed with relaxed eyes, what is the power of the lens?

A person can just see the print in a book clearly when she holds the book no closer than at arm's length ( \(0.45 \mathrm{~m}\) from the eyes). (a) Does she have (1) nearsightedness, (2) farsightedness, or (3) astigmatism? Explain. (b) Which type of lens will allow her to read the text at the normal near point \((0.25 \mathrm{~m}),\) and what is that lens's power?

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