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In the development of Young's double-slit experiment, a small-angle approximation \((\tan \theta \approx \sin \theta)\) was used to find the lateral displacements of the maxima (bright) and minima (dark) positions. How good is this approximation? For example, what is the percentage error for \(\theta=10^{\circ} ?\)

Short Answer

Expert verified
The percentage error for \( \theta = 10^{\circ} \) is approximately 1.55\%.

Step by step solution

01

Understand the small-angle approximation

The small-angle approximation states that for small angles, typically measured in radians, the values of \( \tan(\theta) \) and \( \sin(\theta) \) are approximately equal. This is often used when \( \theta \) is small (usually below 15°) to simplify calculations in trigonometry.
02

Convert degrees to radians

Angles in trigonometric calculations like this should be in radians. Convert \( \theta = 10^{\circ} \) to radians using the conversion \( 1^{\circ} = \frac{\pi}{180} \, \text{radians} \). Thus, \( 10^{\circ} = \frac{10 \pi}{180} = \frac{\pi}{18} \approx 0.1745 \, \text{radians} \).
03

Calculate \( \tan(\theta) \) and \( \sin(\theta) \)

Evaluate \( \tan(0.1745) \) and \( \sin(0.1745) \) using a calculator. For \( \theta = 0.1745 \): \( \tan(0.1745) \approx 0.1763 \), \( \sin(0.1745) \approx 0.1736 \).
04

Determine the difference

Find the difference between \( \tan(\theta) \) and \( \sin(\theta) \) by subtracting the two: \( \tan(0.1745) - \sin(0.1745) = 0.1763 - 0.1736 = 0.0027 \).
05

Percentage error calculation

To find the percentage error, use the formula: \( \text{Percentage Error} = \left( \frac{|\tan(\theta) - \sin(\theta)|}{\sin(\theta)} \right) \times 100 \). So, \( \text{Percentage Error} = \left( \frac{0.0027}{0.1736} \right) \times 100 \approx 1.55\%. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Small-Angle Approximation
In physics, the small-angle approximation is a powerful simplification, especially in scenarios where the angle \(\theta\) is small enough that \(\tan \theta\) and \(\sin \theta\) can be treated as nearly equal. This approximation often applies when \(\theta\) is less than about 15 degrees. The simplification allows physicists and engineers to make complex calculations more manageable.
  • The basic principle centers around measuring angles in radians. In radians, small angles appear very close in value when comparing \(\tan \theta\), \(\sin \theta\), and even \(\theta\) itself.

  • For instance, in Young's double-slit experiment, this approximation helps in predicting points of constructive and destructive interference without complicating trigonometric calculations.

Understanding how these functions behave for small angles is essential. For instance, if \(\theta = 10^{\circ}\), translating this into radians involves using the conversion \(1^{\circ} = \frac{\pi}{180}\) radians, yielding \(0.1745\) radians. At this value, the difference between \(\tan(0.1745)\) and \(\sin(0.1745)\) is minimal, making this approximation useful.
Trigonometry in Physics
Trigonometry is a cornerstone of physics, enabling the study of angles and their relationships in different scenarios, such as in Young's double-slit experiment. There, trigonometry helps analyze the path differences and interference patterns arising when two waves meet. It plays a crucial role in understanding various physical phenomena.
  • Trigonometric functions like sine and tangent describe the ratios of sides in a right triangle relative to an angle.

  • In practical physics applications, these functions assist in outlining the angles and dimensions of physical scenarios involving waves, projectiles, and optics.

By using the small-angle approximation, the trigonometric complexity reduces, allowing for simpler computations with nearly the same accuracy. For \(\theta = 10^{\circ}\) (or \(0.1745\) radians), the calculations for \(\tan(\theta)\) and \(\sin(\theta)\) produce similar values. This makes the approximation very useful in simplifying studies of light behavior and mechanics of motion.
Percentage Error Calculation
Calculating the percentage error is a fundamental skill in mathematics and physics, providing a measure of an approximation's accuracy. In the context of the small-angle approximation, it quantifies how close \(\tan(\theta)\) is to \(\sin(\theta)\), stipulating the precision of using one in the place of the other.
  • The formula for percentage error is \(\text{Percentage Error} = \left( \frac{|\tan(\theta) - \sin(\theta)|}{\sin(\theta)} \right) \times 100\).

  • It expresses the error as a percentage of the actual value, helping to assess the reliability of approximations in calculations.

For example, when \(\theta = 10^{\circ}\), the small difference \(0.0027\) between these trigonometric values results in a percentage error of approximately \(1.55\%\). This low error demonstrates the effectiveness of the small-angle approximation within its limitations, providing confidence in its usage for simplifying trigonometric problems in physics.

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Most popular questions from this chapter

At what angle will the second-order maximum be seen from a diffraction grating of spacing \(1.25 \mu \mathrm{m}\) when illuminated by light of wavelength \(550 \mathrm{nm} ?\)

A thin air wedge between two flat glass plates forms bright and dark interference bands when illuminated with normally incident monochromatic light. (See Fig. 24.9.) (a) Show that the thickness of the air wedge changes by \(\lambda / 2\) from one bright band to the next, where \(\lambda\) is the wavelength of the light. (b) What would be the change in the thickness of the wedge between bright bands if the space were filled with a liquid with an index of refraction \(n ?\)

(a) If the wavelength used in a single-slit diffraction experiment increases, will the width of the central maximum (1) increase, (2) remain the same, or (3) decrease? Why? (b) If the width of the slit is \(0.45 \mathrm{~mm}\) the wavelength is \(400 \mathrm{nm},\) and the screen is \(2.0 \mathrm{~m}\) from the slit, what would be the width of the central maximum? (c) What if the wavelength is \(700 \mathrm{nm} ?\)

A teacher standing in a doorway \(1.0 \mathrm{~m}\) wide blows a whistle with a frequency of \(1000 \mathrm{~Hz}\) to summon children from the playground (v Fig. 24.31 ). Two boys are playing on the swings \(20 \mathrm{~m}\) away from the school building. One boy is at an angle of \(0^{\circ}\) and another one at \(19.6^{\circ}\) from a line normal to the doorway. Taking the speed of sound in air to be \(335 \mathrm{~m} / \mathrm{s}\), which boy may not hear the whisle? Prove your answer.

A plate of crown glass \((n=1.52)\) is covered with a layer of water. A beam of light traveling in air is incident on the water and partially transmitted. Is there any angle of incidence for which the light reflected from the water- glass interface will have maximum linear polarization? Justify your answer mathematically.

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