/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A series RLC circuit has compone... [FREE SOLUTION] | 91Ó°ÊÓ

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A series RLC circuit has components with \(R=50 \Omega\), \(L=0.15 \mathrm{H},\) and \(C=20 \mu \mathrm{F}\). The circuit is driven by a \(120-\mathrm{V}, 60-\mathrm{Hz}\) source. (a) What is the current in the circuit, expressed as a percentage of the maximum possible current? (b) What is the power delivered to the circuit, expressed as a percentage of the power delivered when the circuit is in resonance?

Short Answer

Expert verified
(a) 22.6%, (b) 5.12%

Step by step solution

01

Calculate the Angular Frequency

First, we need to calculate the angular frequency \( \omega \) using the formula: \( \omega = 2 \pi f \), where \( f = 60 \) Hz. This gives: \( \omega = 2 \pi \times 60 = 120 \pi \ \text{rad/s} \).
02

Compute Inductive and Capacitive Reactance

Calculate the inductive reactance \( X_L = \omega L = 120\pi \times 0.15 = 18\pi \ \Omega \). Next, calculate the capacitive reactance \( X_C = \frac{1}{\omega C} = \frac{1}{120\pi \times 20 \times 10^{-6}} \approx 265.26 \ \Omega \).
03

Determine Total Impedance

The total impedance \( Z \) for the RLC series circuit is given by: \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \]. Substitute the given values: \[ Z = \sqrt{50^2 + (18\pi - 265.26)^2} \approx 221.14 \ \Omega \].
04

Calculate Maximum Current

The maximum current when the circuit is driven by a 120-V source is given by \( I_{\text{max}} = \frac{V_{\text{source}}}{R} = \frac{120}{50} = 2.4 \ \text{A} \).
05

Calculate Actual Current

The actual current \( I \) in the circuit is \( I = \frac{V_{\text{source}}}{Z} \approx \frac{120}{221.14} \approx 0.543 \ \text{A} \).
06

Calculate Percentage of Maximum Current

The percentage of the actual current relative to the maximum current is: \( \frac{I}{I_{\text{max}}} \times 100\% = \frac{0.543}{2.4} \times 100\% \approx 22.6\% \).
07

Calculate Power at Resonance

Power at resonance can be calculated using \( P_{\text{resonant}} = \frac{{V_{\text{source}}}^2}{R} = \frac{120^2}{50} = 288 \ \text{W} \).
08

Calculate Actual Power Delivered

The power delivered to the circuit can be calculated using \( P = I^2 R = (0.543)^2 \times 50 \approx 14.74 \ \text{W} \).
09

Calculate Percentage of Resonant Power

Calculate the percentage of actual power relative to the resonant power: \( \frac{P}{P_{\text{resonant}}} \times 100\% = \frac{14.74}{288} \times 100\% \approx 5.12\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Frequency
Angular frequency is a key concept in analyzing RLC circuits, as it helps characterize the oscillation rate of circuit signals. Represented by the symbol \( \omega \), angular frequency relates to the standard frequency \( f \) by the equation \( \omega = 2 \pi f \). Here, \( f \) is the frequency of the AC source in hertz. In RLC circuits, angular frequency aids in calculating reactances and determining how quickly the system's current and voltage vary over time.
In our problem, with a frequency \( f = 60 \text{ Hz} \), the angular frequency is calculated as \( \omega = 120\pi \text{ rad/s} \). Understanding \( \omega \) is crucial for proceeding with further circuit analysis, influencing factors like reactance and impedance.
Inductive Reactance
Inductive reactance, denoted as \( X_L \), measures an inductor's opposition to changes in current within an AC circuit. This reactance depends on the angular frequency and the inductance \( L \) of the circuit component. It's given by the formula \( X_L = \omega L \).
Whereas a pure resistor simply resists current, an inductor resists changes in current, leading to a delay between the applied voltage and resulting current. Thus, this reactance plays a pivotal part in any AC circuit.
In our example, the inductive reactance is calculated at \( X_L = 18\pi \ \, \Omega \) using the known values of \( \omega = 120\pi \ \, \text{rad/s} \) and \( L = 0.15 \text{ H} \).
Capacitive Reactance
Capacitive reactance, represented as \( X_C \), evaluates how a capacitor resists the inflow of current in an AC circuit. Unlike resistors or inductors, capacitors store and release energy, delaying voltage changes more than resisting current. Capacitive reactance is inversely proportional to the angular frequency and capacitance \( C \), expressed as \( X_C = \frac{1}{\omega C} \).
For capacitors, reactance decreases as frequency increases, because at high frequencies, capacitors allow easier current flow. This feature makes them invaluable in AC circuits.
In the given circuit, using \( \omega = 120\pi \ \, \text{rad/s} \) and \( C = 20 \mu \text{F} \), the capacitive reactance becomes \( X_C \approx 265.26 \ \, \Omega \).
Impedance
Impedance \( Z \) quantifies combined opposition of resistive and reactive components to AC current. Think of it as the circuit's effective resistance when affected by alternating current. It's a complex quantity comprised of resistance \( R \), inductive reactance \( X_L \), and capacitive reactance \( X_C \). The formula for total impedance in an RLC series circuit is: \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \].
This makes it vital in determining the current flowing through the circuit.
For the problem circuit, resistance \( R = 50 \Omega \), leading to an impedance calculation of \( Z \approx 221.14 \ \Omega \).
The circuit's actual current can then be found using Ohm's Law \( I = \frac{V}{Z} \).
Resonance in Circuits
Resonance in RLC circuits signifies a special frequency where inductive and capacitive reactances cancel out. This results in the circuit appearing purely resistive with impedance at minimum, boosting maximum current flow. This resonance condition is crucial, especially in applications like radio transmitters and signal processing.
The resonant frequency \( f_0 \) in a circuit is given by:\[ f_0 = \frac{1}{2\pi \sqrt{LC}} \].
At resonance, current peaks leading to maximum energy transfer and efficiency in the circuit.
For students tackling RLC circuits, grasping resonance assists in identifying the conditions for optimized circuit performance and understanding power implications. In the exercise, power at resonance is significantly higher compared to the actual power due to this phenomenon.

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Most popular questions from this chapter

In a series RLC circuit, \(R=X_{C}=X_{L}=40 \Omega\) for a particular driving frequency. (a) This circuit is (1) inductive, (2) capacitive, (3) in resonance. Explain your reasoning. (b) If the driving frequency is doubled, what will be the impedance of the circuit?

An ideal transformer is plugged into a \(12-\mathrm{V}, 60-\mathrm{Hz}\) ac outlet in a motor home, thus enabling the owners to use a \(1500-\mathrm{W}\), 120 - \(\mathrm{V}\) hair dryer. (Ignore any inductance or capacitance associated with the hair dryer.) (a) What type of transformer should be used and what should its turn ratio be? When the hair dryer is in operation, (b) what is its resistance? (c) What are its frequency, \(\mathrm{rms}\) voltage, and rms current? (d) What are its peak current and peak voltage and peak power output? (e) What are the peak power, current, and voltage values on the input side of the transformer?

A circuit with a single capacitor is connected to a \(120-\) \(\mathrm{V}, 60\) -Hz source. (a) What is its capacitance if there is a current of \(0.20 \mathrm{~A}\) in the circuit? (b) What would be the current if the source frequency were halved?

A circuit connected to a \(110-\mathrm{V}, 60\) -Hz source contains a \(50-\Omega\) resistor and a coil with an inductance of \(100 \mathrm{mH}\). Find (a) the reactance of the coil, (b) the impedance of the circuit, (c) the current in the circuit, and (d) the power dissipated by the coil, and (e) calculate the phase angle between the current and the applied voltage.

A series \(\mathrm{RC}\) circuit has a resistance of \(200 \Omega\) and a capacitance of \(25 \mu \mathrm{F}\) and is driven by a \(120-\mathrm{V}, 60\) -Hz source. (a) Find the capacitive reactance and impedance of the circuit. (b) How much current is drawn from the source?

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