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A sports car can accelerate from 0 to \(60 \mathrm{mi} / \mathrm{h}\) in \(3.9 \mathrm{~s}\). What is the magnitude of the average acceleration of the car in meters per second squared?

Short Answer

Expert verified
The car's average acceleration is approximately 6.88 m/s².

Step by step solution

01

Convert Speed from Miles per Hour to Meters per Second

First, we need to convert the car's speed from miles per hour to meters per second. We know there are 1609.34 meters in a mile and 3600 seconds in an hour, so:\[60 \text{ mi/h} = 60 \times \frac{1609.34}{3600} \text{ m/s} \approx 26.82 \text{ m/s}\]
02

Calculate Average Acceleration

Now we need to calculate the average acceleration using the formula for acceleration, which is the change in velocity divided by the change in time:\[a = \frac{\Delta v}{\Delta t} = \frac{26.82 \text{ m/s} - 0 \text{ m/s}}{3.9 \text{ s}} \approx 6.88 \text{ m/s}^2\]
03

State the Result Clearly

The magnitude of the average acceleration of the car is approximately \(6.88\) meters per second squared.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Conversion
When dealing with velocity in physics, it's common to encounter measurements in different units, such as miles per hour (mi/h) and meters per second (m/s). Converting between these units is essential for solving problems since the standard in physics is often meters per second.
To convert from miles per hour to meters per second, you can use the conversion factors: 1 mile is 1609.34 meters, and 1 hour is 3600 seconds.
  • First, multiply the speed in miles per hour by 1609.34 to convert miles to meters.
  • Then, divide that result by 3600 to convert hours to seconds.
For example, if a car is traveling at 60 mi/h, you multiply by 1609.34 and divide by 3600. So, the speed in meters per second would be approximately 26.82 m/s. This conversion is important for understanding speed in terms of the metric system, which is widely used in scientific calculations.
Miles per Hour to Meters per Second
Understanding how to convert miles per hour to meters per second can be crucial when tackling physics problems. While miles per hour is a common speed unit in the United States, physics often requires the use of meters per second for consistency in calculations. The process of conversion involves straightforward multiplication and division.
  • Imagine you are given a speed in miles per hour, such as 60 mi/h.
  • To convert, use the fact that 1 mile equals 1609.34 meters.
  • You'll also need to know that 1 hour equates to 3600 seconds.
Thus, the conversion involves multiplying the miles per hour by 1609.34 to change from miles to meters, followed by dividing that product by 3600 to translate from hours to seconds. With practice, this conversion becomes intuitive, allowing for quick and accurate physics calculations.
Physics Problem Solving
When solving physics problems, it's important to follow a structured approach. This breaks down complex concepts into simpler, more manageable steps.
  • Begin by identifying what is being asked; for instance, calculating the average acceleration.
  • Identify all variables involved and convert them into the suitable units for solving the equation.
  • Apply the relevant physics formulas. In this case, acceleration is calculated using the change in velocity divided by the time interval: \( a = \frac{\Delta v}{\Delta t} \).
For the given problem, once you have the speed in meters per second, you can calculate acceleration by determining how much the velocity changes over a given time period. For our car scenario, the car's velocity increases from 0 to 26.82 m/s in 3.9 seconds. Thus, the average acceleration can be found by plugging these values into the formula, resulting in an acceleration of approximately 6.88 m/s². By breaking down problems into these systematic steps, physics problems become more comprehensible and less intimidating.

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Most popular questions from this chapter

A photographer in a helicopter ascending vertically at a constant rate of \(12.5 \mathrm{~m} / \mathrm{s}\) accidentally drops a camera out the window when the helicopter is \(60.0 \mathrm{~m}\) above the ground. (a) How long will the camera take to reach the ground? (b) What will its speed be when it hits?

According to Newton's laws of motion (which will be studied in Chapter 4 ), a frictionless \(30^{\circ}\) incline should provide an acceleration of \(4.90 \mathrm{~m} / \mathrm{s}^{2}\) down the incline. A student with a stopwatch finds that an object, starting from rest, slides down a \(15.00-\mathrm{m}\) very smooth incline in exactly \(3.00 \mathrm{~s}\). Is the incline frictionless?

The speed limit in a school zone is \(40 \mathrm{~km} / \mathrm{h}\) (about \(25 \mathrm{mi} / \mathrm{h}\) ). A driver traveling at this speed sees a child run onto the road \(13 \mathrm{~m}\) ahead of his car. He applies the brakes, and the car decelerates at a uniform rate of \(8.0 \mathrm{~m} / \mathrm{s}^{2} .\) If the driver's reaction time is \(0.25 \mathrm{~s},\) will the car stop before hitting the child?

A train normally travels at a uniform speed of \(72 \mathrm{~km} / \mathrm{h}\) on a long stretch of straight, level track. On a particular day, the train must make a 2.0 -min stop at a station along this track. If the train decelerates at a uniform rate of \(1.0 \mathrm{~m} / \mathrm{s}^{2}\) and, after the stop, accelerates at a rate of \(0.50 \mathrm{~m} / \mathrm{s}^{2},\) how much time is lost because of stopping at the station?

A car and a motorcycle start from rest at the same time on a straight track, but the motorcycle is \(25.0 \mathrm{~m}\) behind the car (v Fig. 2.27). The car accelerates at a uniform rate of \(3.70 \mathrm{~m} / \mathrm{s}^{2}\) and the motorcycle at a uniform rate of \(4.40 \mathrm{~m} / \mathrm{s}^{2}\) (a) How much time elapses before the motorcycle overtakes the car? (b) How far will each have traveled during that time? (c) How far ahead of the car will the motorcycle be \(2.00 \mathrm{~s}\) later? (Both vehicles are still accelerating.)

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