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In a mass spectrometer, a singly charged ion having a particular velocity is selected by using a magnetic field of 0.10 T perpendicular to an electric field of \(1.0 \times 10^{3} \mathrm{~V} / \mathrm{m} .\) A magnetic field of this same magnitude is then used to deflect the ion, which moves in a circular path with a radius of \(1.2 \mathrm{~cm} .\) What is the mass of the ion?

Short Answer

Expert verified
The mass of the ion is approximately \(1.92 \times 10^{-26} \mathrm{~kg}\).

Step by step solution

01

Understanding the Problem

We need to find the mass of a singly charged ion that is subjected to both electric and magnetic fields in a mass spectrometer. The magnetic field strength is 0.10 T and electric field strength is \( 1.0 \times 10^{3} \mathrm{~V/m} \). The ion moves in a circular path with radius 1.2 cm.
02

Calculate the Velocity of the Ion

The velocity of the ion can be determined by setting the electric force equal to the magnetic force in the velocity selector. The equation is \( qE = qvB \), where \( q \) is the charge, \( E \) is the electric field strength, \( v \) is the velocity, and \( B \) is the magnetic field strength. Solving for \( v \), we have \( v = \frac{E}{B} \). Substituting \( E = 1.0 \times 10^{3} \mathrm{~V/m} \) and \( B = 0.10 \mathrm{~T} \), we get \( v = \frac{1.0 \times 10^{3}}{0.10} = 1.0 \times 10^{4} \mathrm{~m/s} \).
03

Relate Mass to Circular Motion

In the magnetic field, the ion undergoes circular motion. The centripetal force required for this motion is provided by the magnetic force, \( qvB = \frac{mv^2}{r} \), where \( r \) is the radius of the path, \( m \) is the mass of the ion. Rearrange to find the mass: \( m = \frac{qBr}{v} \). Substitute \( q = 1.6 \times 10^{-19} \mathrm{~C} \), \( B = 0.10 \mathrm{~T} \), \( r = 0.012 \mathrm{~m} \), and \( v = 1.0 \times 10^{4} \mathrm{~m/s} \).
04

Calculate the Mass of the Ion

Substitute the known values into the mass equation: \( m = \frac{1.6 \times 10^{-19} \times 0.10 \times 0.012}{1.0 \times 10^{4}} \). Calculate \( m = 1.92 \times 10^{-26} \mathrm{~kg} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Force
In the context of a mass spectrometer, the magnetic force plays a crucial role in determining the path of a charged particle, guiding it in a circular motion. This force is exerted on a charged particle when it moves through a magnetic field. The force acting on the ion is given by the expression \( F = qvB \), where:
  • \( q \) is the charge of the particle,
  • \( v \) is its velocity,
  • and \( B \) is the magnetic field strength.
This force acts perpendicular to both the velocity of the particle and the direction of the magnetic field, making the path circular instead of linear. In the exercise, a constant magnetic field ensures the ion follows a predictably circular path due to this perpendicular force.
Electric Force
Electric force is another fundamental concept involved in a mass spectrometer, notably in selecting ions of a specific velocity. This force is exerted on a charged particle in an electric field and helps determine the ion's speed before it enters the magnetic field except the circular path. It is described by the equation \( F = qE \), where:
  • \( q \) is the charge of the ion,
  • \( E \) is the electric field intensity.
In a mass spectrometer, the electric force is used in combination with the magnetic force through a principle known as the velocity selector. This ensures that only ions moving with specific velocities end up in the analysis chamber. Thus, the electric force allows for the precise control necessary to select ions based on their speed, ensuring they travel at the correct rate for proper mass measurement.
Circular Motion
Circular motion is a key aspect in the study of charged particles in magnetic and electric fields, such as within a mass spectrometer. When a charged particle like a singly charged ion is introduced to a uniform magnetic field, it experiences a magnetic force that acts towards the center of its path. This results in circular motion, where the centripetal force required to maintain this path is exactly provided by the magnetic force.To describe this motion mathematically in the context of a mass spectrometer, we use the formula \( qvB = \frac{mv^2}{r} \), where:
  • \( m \) is the mass of the ion,
  • \( r \) is the radius of the circular path,
  • \( v \) is the velocity of the ion.
The radius of the path correlates with the mass of the ion, allowing spectrometers to determine the mass based on its trajectory. As shown in the exercise, using known variables like velocity and radius allows for the calculation of the ion's mass.
Singly Charged Ion
In mass spectrometry, ions are usually singly charged, meaning they have a charge equivalent to that of a single proton or electron, which is approximately \( 1.6 \times 10^{-19} \) coulombs. The simplicity of dealing with singly charged ions rests in the predictability and uniformity they bring to calculations and analyses.For a mass spectrometer, knowing the charge simplifies the equations needed to measure other unknowns, such as the mass of the ion. The singly charged assumption allows practitioners to use the standard charge value \( q \) in force calculations, such as the equilibrium between the magnetic and electric forces and the determination of velocity in a velocity selector.Understanding the concept of a singly charged ion is fundamental in learning how mass spectrometers can separate and identify ions based on mass, as they move through electric and magnetic fields with predictable behaviors due to their uniform charge. This uniform charge provides consistency across the board in conducting these measurements.

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Most popular questions from this chapter

A circular coil of current-carrying wire has the normal to its area pointing upward. A second smaller concentric circular coil carries a current in the opposite direction. (a) Where, in the plane of these coils, could the magnetic field be zero: (1) only inside the smaller one, (2) only between the inner and outer one, (3) only outside the larger one, or (4) inside the smaller one and outside the larger one? (b) The larger one is a 200-turn coil of wire with a radius of \(9.50 \mathrm{~cm}\) and carries a current of \(11.5 \mathrm{~A}\). The second one is a 100 -turn coil with a radius of \(2.50 \mathrm{~cm}\). Determine the current in the inner coil so the magnetic field at their common center is zero. Neglect the Earth's field.

A wire carries a current of 10 A in the \(+x\) -direction in a uniform magnetic field of \(0.40 \mathrm{~T}\). Find the magnitude of the force per unit length and the direction of the force on the wire if the magnetic field is (a) in the \(+x\) -direction, (b) in the \(+y\) -direction, \((\mathrm{c})\) in the \(+z\) -direction, \((\mathrm{d})\) in the \(-y\) -direction, \((\mathrm{e})\) in the \(-z\) -direction, and \((\mathrm{f})\) at an angle of \(45^{\circ}\) above the \(+x\) -axis and in the \(x-y\) plane.

A crude model of the Earth's magnetic field consists of a circular loop of current with a radius of \(500 \mathrm{~km}\) with its center coincident with that of the Earth's. Assuming the plane of the loop to be approximately in the equatorial plane, and using a value of \(0.10 \mathrm{mT}\) for the magnitude of the Earth's field at the poles, (a) estimate the current in the theoretical loop. (b) What would be the magnetic moment (magnitude and direction) of this supposed loop?

A current-carrying solenoid is \(10 \mathrm{~cm}\) long and is wound with 1000 turns of wire. It produces a magnetic field of \(4.0 \times 10^{-4} \mathrm{~T}\) at the solenoid's center. (a) How long would you make the solenoid in order to produce a field of \(6.0 \times 10^{-4} \mathrm{~T}\) at its center? (b) Adjusting only the windings, what number would be needed to produce a field of \(8.0 \times 10^{-4} \mathrm{~T}\) at the center? (c) What current in the solenoid would be needed to produce a field of \(9.0 \times 10^{-4} \mathrm{~T}\) but in the opposite direction?

A cylindrical solenoid \(10 \mathrm{~cm}\) long has 3000 turns of wire and carries a current of 5.0 A. A second solenoid, consisting of 2000 turns of wire and the same length as the first solenoid, surrounds it and is concentric (shares a common central axis) with it. The outer coil carries a current of 10 A in the same direction as the current in inner one. (a) Find the magnetic field near their common center. (b) What current in the second solenoid (magnitude and relative direction) would make the net field strength at the center twice that of the first solenoid alone? (c) What current in the second solenoid (magnitude and relative direction) would result in zero net magnetic field near their common center?

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