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An ionized deuteron (a bound proton-neutron system with a net \(+e\) charge) passes through a velocity selector whose perpendicular magnetic and electric fields have magnitudes of \(40 \mathrm{mT}\) and \(8.0 \mathrm{kV} / \mathrm{m},\) respectively. Find the speed of the ion.

Short Answer

Expert verified
The speed of the ion is 200,000 m/s.

Step by step solution

01

Understand the velocity selector condition

A velocity selector uses perpendicular electric and magnetic fields to filter charged particles based on their speed. The condition for a particle to pass through the selector without deflection is that the electric force equals the magnetic force.
02

Set up the balance of forces equation

The electric force on the ion is given by \( F_E = qE \), where \( q \) is the charge of the ion and \( E \) is the electric field. The magnetic force on a moving ion is \( F_B = qvB \), where \( v \) is the speed of the ion and \( B \) is the magnetic field. For no deflection, these forces must be equal: \( qE = qvB \).
03

Simplify the equation

Divide both sides of the equation by \( q \) (the charge) to simplify. This results in \( E = vB \).
04

Solve for speed \( v \)

Rearrange the equation \( E = vB \) to solve for \( v \). This gives \( v = \frac{E}{B} \).
05

Substitute the given values

Substitute the given values for \( E = 8,000 \mathrm{V/m} \) and \( B = 0.040 \mathrm{T} \) into the equation \( v = \frac{E}{B} \). Calculate \( v = \frac{8,000}{0.040} = 200,000 \) m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Force
The electric force is a fundamental force that acts on charged particles. When a charged particle, like an ion, is placed in an electric field, it experiences a force that can alter its motion. This force is described by the equation \( F_E = qE \), where \( q \) represents the charge of the particle, and \( E \) is the magnitude of the electric field.
In simple terms, the electric force pushes or pulls charged particles along the direction of the electric field lines. This is an important concept in electromagnetism, as it helps to understand how electric fields influence charged particles.
In the context of our exercise, the electric force counterbalances the magnetic force when the deuteron passes through the velocity selector. This balance means the deuteron travels in a straight path without deviation, making the velocity selector useful for filtering particles by speed.
Magnetic Force
Magnetic force is another key force that acts on charged particles, but only when they are moving. This force is always perpendicular to both the magnetic field direction and the particle's velocity. The mathematical expression for magnetic force is given as \( F_B = qvB \). Here, \( v \) is the particle's speed, \( B \) is the magnetic field strength, and \( q \) is the charge.
Magnetic forces play a crucial role in many applications, such as in electric motors and generators. When the speed of the particle and the strength of the field are just right, they can perfectly balance another force, such as in a velocity selector.
In our exercise, the magnetic force counteracts the electric force. This interaction is crucial for allowing charged particles of a specific speed to pass through the velocity selector without deflection.
Charged Particles
Charged particles are particles that have either a positive or negative electric charge. These particles are fundamental components of atoms and molecules. For instance, ions like the deuteron have a net charge because they either gained or lost electrons.
The behavior of charged particles in electric and magnetic fields is vital in many technological and scientific applications. Their interaction with such fields can be manipulated for purposes like separating particles by mass or velocity.
In the problem, a deuteron with a positive charge is under examination. Understanding how its charge interacts means knowing how it will behave in electromagnetic fields, such as in the velocity selector setup, where balanced forces determine the path it travels.
Net Charge
Net charge is the total amount of positive or negative charge in a particle or system. It arises when the number of protons (positive charge carriers) does not equal the number of electrons (negative charge carriers).
This concept becomes especially significant in ionized particles, such as the deuteron, which has lost or gained electrons to acquire a net charge of \(+e\). This net positive charge means the deuteron will respond to electric and magnetic fields, as seen in our velocity selector scenario.
In real-world applications, net charge influences how particles are manipulated in fields. This principle is used in technologies like mass spectrometry, where precise control over charged particles is crucial. Recognizing the role of net charge helps in predicting particle motion in varying field environments.

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Most popular questions from this chapter

A current-carrying solenoid is \(10 \mathrm{~cm}\) long and is wound with 1000 turns of wire. It produces a magnetic field of \(4.0 \times 10^{-4} \mathrm{~T}\) at the solenoid's center. (a) How long would you make the solenoid in order to produce a field of \(6.0 \times 10^{-4} \mathrm{~T}\) at its center? (b) Adjusting only the windings, what number would be needed to produce a field of \(8.0 \times 10^{-4} \mathrm{~T}\) at the center? (c) What current in the solenoid would be needed to produce a field of \(9.0 \times 10^{-4} \mathrm{~T}\) but in the opposite direction?

A beam of protons is accelerated easterly from rest through a potential difference of \(3.0 \mathrm{kV}\). It enters a region where there exists an upward pointing uniform electric field. This field is created by two parallel plates separated by \(10 \mathrm{~cm}\) with a potential difference of \(250 \mathrm{~V}\) across them. (a) What is the speed of the protons as they enter the electric field? (b) Find the magnitude and direction relative to the velocity of the magnetic field (perpendicular to \(\overrightarrow{\mathrm{E}})\) needed so the beam passes undeflected through the plates. (c) What happens to the protons if the magnetic field is greater than the value found in part (b)?

1 lies on the \(x\) -axis and its north end is at \(x=+1.0 \mathrm{~cm},\) while its south end is at… # Two bar very narrow magnets are located in the \(x\) -y \(y\) plane. Magnet #1 lies on the \(x\) -axis and its north end is at \(x=+1.0 \mathrm{~cm},\) while its south end is at \(x=+5.0 \mathrm{~cm}\) Magnet \(\\# 2\) lies on the \(y\) -axis and its north end is at \(y=+1.0 \mathrm{~cm},\) while its south end is at \(y=+5.0 \mathrm{~cm}\) Magnet #2 produces a magnetic field that is only onehalf the magnitude of magnet #1. (a) In what direction would a compass point if it were located at the origin? (b) Repeat part (a) for the situation where magnet #1 is reversed in polarity.

An ionized deuteron (a bound proton-neutron system with a net \(+e\) charge) passes through a velocity selector whose perpendicular magnetic and electric fields have magnitudes of \(40 \mathrm{mT}\) and \(8.0 \mathrm{kV} / \mathrm{m}\), respectively. Find the speed of the ion.

A \(50-\mathrm{cm}\) -long solenoid has 100 turns of wire and carries a current of \(0.95 \mathrm{~A}\). It has a ferromagnetic core completely filling its interior where the field is \(0.71 \mathrm{~T}\). Determine the (a) magnetic permeability and (b) relative magnetic permeability of the material.

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