/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Two identical resistors \((R)\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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Two identical resistors \((R)\) are connected in parallel and then wired in series to a \(40-\Omega\) resistor. If the total equivalent resistance is \(55 \Omega,\) what is the value of \(R ?\)

Short Answer

Expert verified
The value of each resistor \( R \) is \( 30 \ \Omega \).

Step by step solution

01

Define the Resistance Setup

We have two identical resistors, each with resistance \( R \), connected in parallel. This parallel combination is then connected in series with a \( 40 \ \Omega \) resistor.
02

Calculate Equivalent Resistance for Parallel Resistors

The formula for the equivalent resistance \( R_p \) of two resistors in parallel is given by \[ \frac{1}{R_p} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R} \] Solving for \( R_p \), we have: \[ R_p = \frac{R}{2} \]
03

Calculate Total Equivalent Resistance

The parallel combination \( R_p \) is in series with a \( 40 \ \Omega \) resistor. Therefore, the total equivalent resistance \( R_t \) is given by: \[ R_t = R_p + 40 \] Since the given total equivalent resistance is \( 55 \ \Omega \), we can write the equation: \[ 55 = \frac{R}{2} + 40 \]
04

Solve for \( R \)

Rearrange the equation from Step 3 to solve for \( R \): \[ 55 - 40 = \frac{R}{2} \] This simplifies to: \[ 15 = \frac{R}{2} \] Multiply both sides by 2 to solve for \( R \): \[ R = 30 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel and Series Circuits
In the realm of electricity, understanding parallel and series circuits is fundamental. These circuits differ in how components, such as resistors, are connected. In a **series circuit**, components are aligned end-to-end in a single path for the current to flow. This means that if one component fails, the entire circuit is interrupted.
Unlike series circuits, a **parallel circuit** has components connected across the same two points, creating multiple paths for the current. Each component gets the full voltage of the supply. An advantage of parallel circuits is that if one path fails, current can still pass through the remaining paths.
  • **Series Circuit:** Current is the same, voltage is divided.
  • **Parallel Circuit:** Voltage is the same, current is divided.
In our exercise, the resistors first form a parallel setup, reducing the combined resistance, before being joined in a series with another resistor. Understanding the combination of these two types of circuits is key to solving the problem of equivalent resistance.
Equivalent Resistance
**Equivalent resistance** refers to the overall resistance of a circuit that has multiple resistors. Calculating it accurately is important to understand how the circuit as a whole will behave.
In a **series circuit**, the equivalent resistance is simple to find. You just add up all the resistances:
  • For two resistors in series, it is: \( R_t = R_1 + R_2 \).
In a **parallel circuit**, it’s a bit different. The formula is based on the reciprocals of each individual resistance:
  • For two resistors in parallel: \( \frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} \).
Thus, a parallel circuit tends to have a lower equivalent resistance than any of its individual components. This exercise involves calculating the equivalent resistance first for parallel resistors, then adding to a series resistor. This step-by-step calculation shows the total combined impact of a mixed setup.
Ohm's Law
Ohm's Law is a pivotal concept in understanding electrical circuits. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance.
Mathematically, it is expressed as: \( V = I \cdot R \), where:
  • \( V \) is the voltage in volts,
  • \( I \) is the current in amperes,
  • \( R \) is the resistance in ohms.
This relationship helps in determining how much current will flow for a given voltage and resistance. In this exercise, while Ohm's Law isn't directly applied to find the equivalent resistance, understanding this law helps appreciate how voltage, current, and resistance relate in general.
It's this relationship that supports the reason behind the distinct behavior of series and parallel circuits in terms of equivalent resistance. Achieving clarity in these core concepts paves the way for gearing towards more complex circuit analysis.

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Most popular questions from this chapter

Two resistors \(R_{1}\) and \(R_{2}\) are in series with a \(7.0-\mathrm{V}\) battery. If \(R_{1}\) has a resistance of \(2.0 \Omega\) and \(R_{2}\) receives energy at the rate of \(6.0 \mathrm{~W}\), what is (are) the value(s) for the circuit's current(s)? (There may be more than one answer.)

Three resistors with values \(1.0-\Omega, 2.0-\Omega,\) and \(4.0-\Omega\) are connected in parallel in a circuit with a 6.0 -V battery. What are (a) the total equivalent resistance, (b) the voltage across each resistor, and (c) the power delivered to the \(4.0-\Omega\) resistor? \(?\)

A capacitor in a single-loop \(\mathrm{RC}\) circuit is charged to \(63 \%\) of its final voltage in \(1.5 \mathrm{~s}\). Find (a) the time constant for the circuit and (b) the percentage of the circuit's final voltage after \(3.5 \mathrm{~s}\).

During an operation, one of the electrical instruments in use has its metal case shorted to the \(120-\mathrm{V}^{\prime \prime}\) hot" wire that powers it. The attending physician, who is isolated from ground because of rubber-soled shoes, inadvertently touches the case with his elbow, while simultaneously touching the patient's chest with his opposite hand. The patient, lying on a metal table, is well grounded. (a) Draw a schematic circuit diagram of this potentially dangerous complete circuit. (b) If the patient's head-to-ground resistance is \(2200 \Omega\), what is the minimum resistance for the physician so that they both feel, at most, a "mild shock"? [Hint: Use your diagram to determine how the "resistors" are connected.

Two batteries with terminal voltages of \(10 \mathrm{~V}\) and \(4 \mathrm{~V}\) are connected with their positive terminals together. A \(12-\Omega\) resistor is wired between their negative terminals. (a) The current in the resistor is (1) \(0 \mathrm{~A},\) (2) between 0 A and \(1.0 \mathrm{~A},\) (3) greater than \(1.0 \mathrm{~A}\). Explain your choice. (b) Use Kirchhoff's loop theorem to find the current in the circuit and the power delivered to the resistor. (c) Compare this result with the power output of each battery. Do both batteries lose stored energy? Explain.

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