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On a violin, a correctly tuned A string has a frequency of \(440 \mathrm{~Hz}\). If an A string produces sound at \(450 \mathrm{~Hz}\) under a tension of \(500 \mathrm{~N},\) what should the tension be to produce the correct frequency?

Short Answer

Expert verified
The tension should be approximately 478 N.

Step by step solution

01

Understand frequency and tension relationship

The frequency of a vibrating string is related to tension by the formula \( f \propto \sqrt{T} \), where \( f \) is the frequency and \( T \) is the tension. This relationship suggests that frequency is proportional to the square root of the tension.
02

Set up proportion equation using given frequencies and tension

Using the formula from Step 1, we form the equation: \( \frac{f_1}{f_2} = \frac{\sqrt{T_1}}{\sqrt{T_2}} \). Substitute \( f_1 = 440 \text{ Hz} \), \( f_2 = 450 \text{ Hz} \), and \( T_2 = 500 \text{ N} \). We need to find \( T_1 \) that provides the correct frequency.
03

Rearrange and solve for \( T_1 \)

Rearrange the equation from step 2 to solve for \( T_1 \): \( \sqrt{T_1} = \frac{f_1}{f_2} \times \sqrt{T_2} \). Substitute the known values: \( \sqrt{T_1} = \frac{440}{450} \times \sqrt{500} \).
04

Calculate \( T_1 \)

Compute \( \frac{440}{450} = 0.9778 \) and \( \sqrt{500} \approx 22.36 \). Then, \( \sqrt{T_1} = 0.9778 \times 22.36 \approx 21.87 \). Finally, square the result: \( T_1 = (21.87)^2 \approx 478 \text{ N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

String Vibration
When a string, such as a violin string, vibrates, it creates sound waves due to the movement back and forth. This vibration is what gives the string its pitch, which is the foundation of musical sound. The vibration depends on several physical factors:
  • Length of the string: The note played depends on how much of the string is free to vibrate. Shorter lengths create higher pitches because they vibrate faster.
  • Tension in the string:The tighter the string, the higher the pitch as the vibrations are faster.
  • Mass of the string: A heavier string will produce a lower note because it vibrates more slowly.
Recognizing how these factors interact is crucial. In the context of string instruments, fine-tuning the vibration frequency by adjusting these properties helps musicians achieve the desired sound quality.
Proportionality Principle
The principle of proportionality plays a key role in understanding the behavior of vibrating strings. Specifically, the frequency of vibration of a string is directly proportional to the square root of its tension. This relationship can be expressed mathematically as:

\[ f \propto \sqrt{T} \]

Here, \( f \) represents the frequency, and \( T \) is the tension in the string. This formula indicates that if the tension increases, the frequency also increases, but not linearly. This principle helps us understand how changing the tension affects the pitch of the sound produced. Increasing the tension makes the string vibrate more quickly, resulting in a higher frequency (higher pitch), while decreasing tension does the opposite.
Frequency Calculation
Calculating the correct tension for a desired frequency involves a few steps. You start with the known frequency and tension and want to find the tension needed for a different frequency. The equation derived from the proportionality principle is:

\[ \frac{f_1}{f_2} = \frac{\sqrt{T_1}}{\sqrt{T_2}} \]

To solve for the unknown tension, you need to rearrange this equation to:

\[ \sqrt{T_1} = \frac{f_1}{f_2} \times \sqrt{T_2} \]

This means the square root of the desired tension (\( T_1 \)) is the ratio of the desired frequency (\( f_1 \)) to the given frequency (\( f_2 \)) multiplied by the square root of the given tension (\( T_2 \)). Squaring the result gives the tension value needed to achieve the desired frequency. This calculation is important in scenarios such as tuning musical instruments to ensure each note resonates at the correct pitch.

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Most popular questions from this chapter

A violin string is tuned to a certain frequency (first harmonic or the fundamental frequency). (a) If a violinist wants a higher frequency, should the string be (1) lengthened, (2) kept the same length, or (3) shortened? Why? (b) If the string is tuned to 520 Hz and the violinist puts a finger down on the string one-eighth of the string length from the neck end, what is the frequency of the string when the instrument is played this way?

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