/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 In about 1657 , Otto von Guerick... [FREE SOLUTION] | 91Ó°ÊÓ

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In about 1657 , Otto von Guericke, inventor of the air pump, evacuated a sphere made of two brass hemispheres (Fig. P9.89). Two teams of eight horses each could pull the hemispheres apart only on some trials and then "with greatest difficulty," with the resulting sound likened to a cannon firing. Find the force \(F\) required to pull the thin-walled evacuated hemispheres apart in terms of \(R\), the radius of the hemispheres, \(P\) the pressure inside the hemispheres, and atmospheric pressure \(P_{0}\).

Short Answer

Expert verified
The force \(F\) required to pull the thin-walled evacuated hemispheres apart equals \(P0 * 4\pi R^2\).

Step by step solution

01

Define the Problem

Given the radius R of the hemispheres, pressure inside the hemispheres P, and the atmospheric pressure P0, we are to calculate the force F required to pull the hemispheres apart.
02

Understand the Principles at Play

From Physics, force is given by the product of pressure and area, expressed mathematically as F = P * A. Since we are dealing with a spherical object (two hemispheres put together to form a sphere), the total surface area A of our sphere is given by \(4\pi R^2\). Therefore, the force exerted on the sphere due to atmospheric pressure will be \(F0 = P0 * 4\pi R^2\).
03

Calculate the Force Inside the Hemispheres

If the hemispheres are evacuated, there is no force exerted on the sphere from within. Therefore, the only forces at play are the atmospheric pressure from outside and the pressure from inside (equal to zero). The force required to pull the hemispheres apart is equal to the force exerted by the atmospheric pressure. Therefore, \(F = F0 = P0 * 4\pi R^2\).
04

Express Force in Terms of Given Variables

Replace \(P0\) and \(R\) with given symbols to get the expression for the force required to separate the two hemispheres. So, \(F = P0 * 4\pi R^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force Calculation in Physics

When it comes to understanding forces in physics, knowing how to compute them is essential. A force can be thought of as a push or pull upon an object resulting from its interaction with another object. Calculating the magnitude of a force requires the knowledge of the pressure exerted and the area over which the pressure is applied.

In problems involving spheres and hemispheres, like the one presented in the exercise, the force calculation becomes particularly interesting. Here, we want to find the force required to pull apart two hemispheres, which involves considering the pressure difference inside and outside of them. If the hemispheres are forming a perfect vacuum inside, the only pressure exerted is from the outside—this is atmospheric pressure. The force exerted by the atmospheric pressure on the spherical surface is crucial to solve the given problem.

Illustrative Example

Imagine pressing your hands together with a small, inflated balloon between them. It's easy to feel the force you need to apply to keep the balloon from popping out. Now, equate this to the hemispheres and the atmospheric pressure as the force you're applying with your hands. By calculating this force, you can understand how much effort the two teams of horses needed to exert.

To summarize the calculation steps:

  • Identify the variables: radius (\(R\)), internal pressure (\(P\)), and atmospheric pressure (\(P_0\)).
  • Understand that the force exerted by the atmosphere (\(F\)) is equal to atmospheric pressure times the sphere's surface area.
  • Calculate the force using the formula \(F = P_0 \times 4\textbackslash\textbackslash\textpi R^2\).

This method also helps illustrate the significance of pressure in force calculations in a tangible and easy-to-visualize manner.

The Pressure and Area Relationship

Understanding the relationship between pressure and area is vital to solving many physics problems. Pressure is defined as the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Mathematically, pressure (\(P\)) is expressed as force (\(F\)) divided by the area (\(A\) over which the force is spread:

\[P = \frac{F}{A}\]

This relationship shows us that if you apply the same force over a larger area, you will produce a smaller pressure, and vice versa. This principle is key in our exercise, where atmospheric pressure is acting over the entire surface of the hemispheres.

When considering Otto von Guericke's experiment, the evacuated hemispheres have no internal pressure pushing outwards. The net force that must be overcome to separate the hemispheres is the atmospheric pressure acting across their surface area. To calculate this, you use the sphere's surface area, which is \(4\textbackslash\textbackslash\textpi R^2\) for a sphere with radius \(R\). As atmospheric pressure is exerted uniformly across this surface, the relationship provides a clear and straightforward way to find the necessary force.

Remember, a larger area means more of the atmosphere is exerting pressure, and thus, more force is required to overcome it. This concept is critical to all kinds of applications in physics and engineering, from hydraulic presses to the way your shoes distribute your weight across their soles to prevent you from sinking into soft ground.

Otto von Guericke Air Pump Experiment

The historical experiment conducted by Otto von Guericke in the mid-17th century highlights the physical concepts of atmospheric pressure and vacuum. Guericke invented the air pump, which allowed him to remove the air inside the hemispheres, creating a vacuum. This experiment demonstrated the substantial force atmospheric pressure can exert, which was not well understood at the time.

Guericke's experiment used two brass hemispheres that fit together tightly. When the air inside was pumped out, the pressure inside the hemispheres dropped, while the outside pressure (atmospheric pressure) remained the same. As a result, there was a substantial pressure difference between the inside and outside of the hemispheres, and this held them together so strongly that even teams of horses struggled to separate them.

Concept in Action

This demonstration is a practical application of the pressure and area relationship. By understanding that the atmospheric pressure acted over the entire surface area of the hemispheres, Guericke was able to illustrate the invisible forces of our atmosphere. The hemispheres could only be pulled apart when the pressure inside was equalized with the pressure outside, either by letting air back in or by applying a sufficient external force to counteract the atmospheric pressure.

The importance of this experiment cannot be understated as it provided one of the earliest empirical pieces of evidence of the existence and strength of atmospheric pressure, leading to advancements in understanding the Earth's atmosphere, vacuum technology, and air pressure's role in everyday life.

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Most popular questions from this chapter

Suppose a distant world with surface gravity of \(7.44 \mathrm{~m} / \mathrm{s}^{2}\) has an atmospheric pressure of \(8.04 \times 10^{4} \mathrm{~Pa}\) at the surface. (a) What force is exerted by the atmosphere on a disk-shaped region \(2.00 \mathrm{~m}\) in radius at the surface of a methane ocean? (b) What is the weight of a \(10.0-\mathrm{m}\) deep cylindrical column of methane with radius \(2.00 \mathrm{~m}\) ? (c) Calculate the pressure at a depth of \(10.0 \mathrm{~m}\) in the methane ocean. Note: The density of liquid methane is \(415 \mathrm{~kg} / \mathrm{m}^{3}\).

A sample of an unknown material appears to weigh \(300 \mathrm{~N}\) in air and \(200 \mathrm{~N}\) when immersed in alcohol of specific gravity \(0.700\). What are (a) the volume and (b) the density of the material?

Whole blood has a surface tension of \(0.058 \mathrm{~N} / \mathrm{m}\) and a density of \(1050 \mathrm{~kg} / \mathrm{m}^{3}\). To what height can whole blood rise in a capillary blood vessel that has a radius of \(2.0 \times 10^{-6} \mathrm{~m}\) if the contact angle is zero?

Figure P9.85 shows a water tank with a valve. If the valve is opened, what is the maximum height attained by the stream of water coming out of the right side of the tank? Assume \(h=10.0 \mathrm{~m}, L=2.00 \mathrm{~m}\), and \(\theta=30.0^{\circ}\), and that the cross-sectional area at \(A\) is very large compared with that at \(B\).

On October 21, 2001, Ian Ashpole of the United Kingdom achieved a record altitude of \(3.35 \mathrm{~km}\) (11 \(000 \mathrm{ft}\) ) powered by 600 toy balloons filled with helium. Each filled balloon had a radius of about \(0.50 \mathrm{~m}\) and an estimated mass of \(0.30 \mathrm{~kg}\). (a) Estimate the total buoyant force on the 600 balloons. (b) Estimate the net upward force on all 600 balloons. (c) Ashpole parachuted to Earth after the balloons began to burst at the high altitude and the system lost buoyancy. Why did the balloons burst?

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