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(a) One of the moons of Jupiter, named Io, has an orbital radius of \(4.22 \times 10^{8} \mathrm{~m}\) and a period of \(1.77\) days. Assuming the orbit is circular, calculate the mass of Jupiter. (b) The largest moon of Jupiter, named Ganymede, has an orbital radius of \(1.07 \times 10^{9} \mathrm{~m}\) and a period of \(7.16\) days. Calculate the mass of Jupiter from this data. (c) Are your results to parts (a) and (b) consistent? Explain.

Short Answer

Expert verified
The calculated mass of Jupiter based from the data about its moons Io and Ganymede are \(1.898 \times 10^{27} \mathrm{kg}\) and \(1.901 \times 10^{27} \mathrm{kg}\) respectively, which are consistent to each other.

Step by step solution

01

Identify the Given Information

We are given the orbital radius and period for the moons Io and Ganymede, which are \(4.22 \times 10^{8} \mathrm{m}\), 1.77 days, \(1.07 \times 10^{9} \mathrm{m}\), and 7.16 days, respectively.
02

Convert the Period into Seconds

The orbital period for the moons need to be in the same units as the gravitational constant G, which is in cubic meters per kilogram per second squared. So we convert the periods from days into seconds: \n For Io, 1.77 days is equivalent to \(1.77 \times 24 \times 60 \times 60 = 152928 \mathrm{s}\). \n For Ganymede, 7.16 days is equivalent to \(7.16 \times 24 \times 60 \times 60 = 618624 \mathrm{s}\).
03

Apply the Orbital Motion Formula

We use the formula \(G \times M = (4 \pi^2 R) / T^2\) where G is the gravitational constant \(( 6.674 \times 10^{-11} \mathrm{m}^3 \mathrm{kg}^{-1} \mathrm{s}^{-2})\), M is the mass of Jupiter, R is the orbital radius, and T is the period.\n For Io, this gives \(M = (4 \pi^2 R) / (G \times T^2) = (4 \pi^2 \times 4.22 \times 10^{8}) / (6.674 \times 10^{-11} \times (152928)^2) = 1.898 \times 10^{27} \mathrm{kg}\). \n For Ganymede, this gives \(M = (4 \pi^2 R) / (G \times T^2) = (4 \pi^2 \times 1.07 \times 10^{9}) / (6.674 \times 10^{-11} \times (618624)^2) = 1.901 \times 10^{27} \mathrm{kg}\).
04

Identifying Consistency

Comparing the two results, they are very close (1.898 and 1.901) thus, the results are consistent. The small difference could easily be due to small measurement errors in the distances and periods.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Jupiter's Moons
Jupiter, the giant planet of our solar system, is orbited by a plethora of moons. Among these are Io and Ganymede, which are particularly interesting. Io is famous for its volcanically active surface, while Ganymede holds the title of the largest moon, not just of Jupiter, but in our entire solar system. These moons are perfect subjects to study Orbital Mechanics, giving insight into principles like gravitational influence and orbital dynamics.

Studying the orbits of these moons allows astronomers to analyze the mass and gravity dynamics of Jupiter. Io and Ganymede orbit in near-circular paths, influenced significantly by Jupiter's massive gravitational pull. Understanding these moons' movements helps scientists gather data about not just their physical properties, but also the characteristics of Jupiter itself, including its mass and gravitational force.
Orbital Radius
The orbital radius is a key parameter in studying orbital mechanics. It refers to the distance from the center of the planet around which a celestial body orbits, to the center of the object itself.

For example, Io has an orbital radius of \(4.22 \times 10^{8} \mathrm{~m}\), while Ganymede orbits at \(1.07 \times 10^{9} \mathrm{~m}\) from Jupiter. These measurements are crucial when calculating the gravitational effects that Jupiter exerts on them.

Combined with data on their periods, the orbital radius allows scientists to use formulas in physics to estimate the mass of Jupiter. These radii imply a nearly circular path—central to simplifying calculations, as a circular orbit can be described using formulas designed for simpler mathematical descriptions.
Gravitational Constant
In orbital mechanics, the gravitational constant, denoted as \(G\), is a fundamental part of the physics explaining the force of gravity. Its value is \(6.674 \times 10^{-11} \, \mathrm{m^3 \, kg^{-1} \, s^{-2}}\). This constant helps in calculating the gravitational force between two masses, such as a planet and its moon.

The force is critically dependent not just on the distance and mass involved, but also on this constant. Hence, using \(G\) in formulas, we need to have all our other units in compatible standard metrics, typically meters, kilograms, and seconds.

In problems related to Jupiter and its moons, \(G\) appears in Newton's law of universal gravitation, which allows us to deduce the mass of Jupiter based on the moons' distances and orbital periods.
Circular Orbits
When studying the motion of celestial bodies like moons or satellites, identifying the nature of their orbits is essential. A circular orbit is one where the orbiting body's path around the planet has a constant radius, forming a perfect circle. This concept simplifies many calculations and can be described precisely using standard physics equations.

Circular orbits, like those of Io and Ganymede, allow for the usage of equations linking orbital parameters such as the orbital radius and period to the planet's mass. For any celestial body in a circular orbit, you can use the formula \(G \times M = \frac{4 \pi^2 R}{T^2}\) to find the central mass (in this case, Jupiter) if the orbital radius \(R\) and period \(T\) are known.

This assumption of a circular orbit allows for streamlined mathematical derivation and concepts that closely align with real-world astronomical observations.

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Most popular questions from this chapter

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