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A certain light truck can go around a flat curve having a radius of \(150 \mathrm{~m}\) with a maximum speed of \(32.0 \mathrm{~m} / \mathrm{s}\). With what maximum speed can it go around a curve having a radius of \(75.0 \mathrm{~m}\) ?

Short Answer

Expert verified
The maximum speed for the light truck to go around a curve having a radius of 75.0 m is approximately 22.6 m/s.

Step by step solution

01

Identify given values and unknowns

The given values are the radius of the first curve (150 m) and the speed of the truck around that curve (32.0 m/s). The speed of the truck around the second curve (radius = 75.0 m) is unknown.
02

Formulate our proportion

We know that the centripetal force for a curve is given by \( F_c = m v^2 / r \). Since the mass of the truck is the same in both cases, the forces are proportional to each other: \( F_{c1} / F_{c2} = v_{1}^2 / v_{2}^2 = r_1 / r_2 \)
03

Substitute the known values

From the problem, we know that \( r_1 = 150 m\), \( v_1 = 32.0 m/s\), and \( r_2 = 75.0 m\). When we plug these values into our equation from step 2, we have: \( (32.0 m/s)^2 / v_{2}^2 = 150 m / 75.0 m \).
04

Solve for the unknown

To solve for \( v_2\), rearrange the equation as: \( v_{2} = \sqrt{ (32.0 m/s)^2 * 75.0 m / 150 m } \). After performing the calculation, the maximum speed for the truck on the second curve is approximately 22.6 m/s. So, for the curve with a radius of 75 m, the truck should not exceed this speed.

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