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BIO In bicycling for aerobic exercise, a woman wants her heart rate to be between 136 and 166 beats per minute. Assume that her heart rate is directly proportional to her mechanical power output. Ignore all forces on the woman- plus-bicycle system, except for static friction forward on the drive wheel of the bicycle and an air resistance force proportional to the square of the bicycler's speed. When her speed is \(22.0 \mathrm{~km} / \mathrm{h}\), her heart rate is \(90.0\) beats per minute. In what range should her speed be so that her heart rate will be in the range she wants?

Short Answer

Expert verified
The speed range should be around 33.2 km/hr to 40.68 km/hr for her to achieve her target heart rate of 136-166 beats per minute.

Step by step solution

01

Establishing Proportions

Given that her heart rate is (90.0 beats / min) when her speed is (22.0 km / hr), set a proportion that shows the relationship between the heart rate and the speed. Hence, \[\frac{90}{22} = \frac{x}{y}\]where \(x\) is the desired heartbeat and \(y\) is the needed speed.
02

Calculate Lower Limit

First, consider the lower limit of the heart rate range. With a desirable heart rate of 136 beats / min, solve the speed. Hence,\[\frac{90}{22} = \frac{136}{y}\]Cross-multiplication gives \( y = \frac{22 * 136}{90} \). Calculate this to find the minimum speed the woman should bike.
03

Calculate Upper Limit

Then, consider the upper limit of the heart rate range. With a desirable heart rate of 166 beats / min, solve the speed. Hence,\[\frac{90}{22} = \frac{166}{y}\]Cross-multiplication gives \( y = \frac{22 * 166}{90} \). Calculate this to find the maximum speed the woman should bike.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direct Proportion
Direct proportion is a foundational concept in physics and mathematics, describing a relationship between two quantities where their ratio remains constant. This means that as one quantity increases, the other quantity changes at a consistent rate so that the proportion between them is always the same.

For instance, suppose we look at the exercise involving a woman's heart rate during aerobic exercise. The heart rate is said to be directly proportional to her mechanical power output, which means there's a constant ratio between the power she expends and her heart rate. If her heart rate (in beats per minute) is mathematically represented as 'h' and mechanical power output as 'p', the direct proportion can be formulated as:
\[\begin{equation}\frac{h_1}{p_1} = \frac{h_2}{p_2}\end{equation}\]
where subscripts 1 and 2 denote two different conditions of exercise. If she increases her power output, her heart rate will also increase, maintaining a constant ratio.
Mechanical Power Output
Mechanical power refers to the rate at which work is performed or energy is transferred. It is an important measure in various applications, especially in exercise physiology, where it can be an indicator of a person's athletic performance.

In physics, power (P) is calculated as the work (W) done over time (T), formulated as \[\begin{equation}\text{Power} (P) = \frac{\text{Work} (W)}{\text{Time} (T)}\end{equation}\]
In the context of our exercise, mechanical power output is related to how much energy the woman is exerting while pedaling her bicycle. The higher the power output, the more intense the exercise, and consequently, the higher her heart rate will be.
Heart Rate Exercise Correlation
The correlation between heart rate and exercise intensity is a vital aspect of understanding how the cardiovascular system responds to physical activity. As exercise intensity increases, the body demands more oxygen and nutrients to fuel the muscles, resulting in an elevated heart rate.

Exercise physiologists and trainers often use heart rate as a proxy to determine exercise intensity. For a given individual, a direct relationship exists between heart rate and exercise intensity, meaning as one increases, so does the other. This relationship, as mentioned, is utilized to find a safe and effective range for aerobic exercise, where the heart rate should be maintained within a certain range to achieve cardiovascular benefits without overexertion.
Air Resistance in Physics
Air resistance, also known as drag, plays a critical role in many aspects of physics, particularly in aerodynamics and exercise science. It is the force that opposes an object's motion through the air and generally increases with the object's speed.

In our scenario, the air resistance force is said to be proportional not just directly to the bicycler's speed, but to the square of the speed, which is a typical characteristic of fluid resistance at higher velocities. The force of air resistance can be expressed as:
\[\begin{equation}\text{Force}_{\text{air}} = C \cdot v^2\end{equation}\]
where\(C\)is a constant that depends on factors such as the shape and size of the object, and\(v\)is the velocity of the bicycle. As the woman cycles faster, the air resistance increases exponentially, which requires greater energy (mechanical power output) to overcome, thereby increasing her heart rate significantly.

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Most popular questions from this chapter

QIC A \(0.250-\mathrm{kg}\) block along a horizontal track has a speed of \(1.50 \mathrm{~m} / \mathrm{s}\) immediately before colliding with a light spring of force constant \(4.60 \mathrm{~N} / \mathrm{m}\) located at the end of the track. (a) What is the spring's maximum compression if the track is frictionless? (b) If the track is not frictionless, would the spring's maximum compression be greater than, less than, or equal to the value obtained in part (a)?

W A child and a sled with a combined mass of \(50.0 \mathrm{~kg}\) slide down a frictionless slope. If the sled starts from rest and has a speed of \(3.00 \mathrm{~m} / \mathrm{s}\) at the bottom, what is the height of the hill?

Q C Starting from rest, a \(5.00-\mathrm{kg}\) block slides \(2.50 \mathrm{~m}\) down a rough \(30.0^{\circ}\) incline. The coefficient of kinetic friction between the block and the incline is \(\mu_{k}=0.436\). Determine (a) the work done by the force of gravity, (b) the work done by the friction force between block and incline, and (c) the work done by the normal force. (d) Qualitatively, how would the answers change if a shorter ramp at a steeper angle were used to span the same vertical height?

BIO (a) A 75-kg man steps out a window and falls (from rest) \(1.0 \mathrm{~m}\) to a sidewalk. What is his speed just before his feet strike the pavement? (b) If the man falls with his knees and ankles locked, the only cushion for his fall is an approximately \(0.50-\mathrm{cm}\) give in the pads of his feet. Calculate the average force exerted on him by the ground during this \(0.50 \mathrm{~cm}\) of travel. This average force is sufficient to cause damage to cartilage in the joints or to break bones.

Hooke's law describes a certain light spring of unstretched length \(35.0 \mathrm{~cm}\). When one end is attached to the top of a door frame and a \(7.50-\mathrm{kg}\) object is hung from the other end, the length of the spring is \(41.5 \mathrm{~cm}\). (a) Find its spring constant. (b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of \(190 \mathrm{~N}\). Find the length of the spring in this situation.

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