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\(\mathrm{M}\) A loaded ore car has a mass of \(950 \mathrm{~kg}\) and rolls on rails with negligible friction. It starts from rest and is pulled up a mine shaft by a cable connected to a winch. The shaft is inclined at \(30.0^{\circ}\) above the horizontal. The car accelerates uniformly to a speed of \(2.20 \mathrm{~m} / \mathrm{s}\) in \(12.0 \mathrm{~s}\) and then continues at constant speed. (a) What power must the winch motor provide when the car is moving at constant speed? (b) What maximum power must the motor provide? (c) What total energy transfers out of the motor by work by the time the car moves off the end of the track, which is of length \(1250 \mathrm{~m}\) ?

Short Answer

Expert verified
The winch motor must provide a power of approximately 9262 W when the car is moving at constant speed. The maximum power provided by the motor is around 10814 W. The total energy transferred out of the motor by work by the time the car moves off the end of the track is approximately 13517500 J.

Step by step solution

01

Compute the Constant Speed Force

To find the power when the car is moving at constant speed, first identify the force needed to maintain this speed. This is the sum of the gravitational force and resistive force. Since the car moves with no acceleration at this point, the force from the motor is the net force that counteracts the existing forces. Compute this using the equation: \( F = m \cdot g \cdot cos(\Theta) \) where \( m = 950 kg \) is the mass, \( g = 9.8 m/s^2 \) is the acceleration due to gravity, and \( \Theta = 30.0^{\circ} \) is the angle of inclination.
02

Compute the Power at Constant Speed

Now that we have the force, the power when the car is moving at a constant speed can be found by the equation \( P = F \cdot v \) where \( F \) is the force and \( v = 2.20 m/s \) is the constant speed.
03

Compute the Maximum Power

The motor provides a maximum amount of power when it is working against both gravitational force and the force required to accelerate the car initially. The force from gravity remains the same, but we can compute the force for acceleration using \( F = m \cdot a \) where \( m = 950 kg \) is the mass and \( a = v/t = 2.20 m/s / 12.0 s \) is the acceleration. Compute the total force and then the power using \( P = F \cdot v \) as before.
04

Compute the Total Energy

The total energy output from the motor by the time the car moves off the end of the track can be computed as the work done by the motor, which is the force times the total distance, or \( E = F \cdot d \), where \( F \) is the force from Step 3, and \( d = 1250 m \) is the total length of the track.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Speed Force Calculation
Understanding how to calculate the force required to maintain a constant speed is a fundamental concept in physics, particularly in the study of mechanics. To solve problems involving constant speed, such as the one with the ore car moving at a steady pace up a mine shaft, we use Newton's First Law of Motion. This law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

For the ore car to move at a constant speed up an incline, the net force acting on the car must be zero. Therefore, the winch motor must exert a force that precisely balances the gravitational component pulling the car downwards along the incline. This gravitational component can be calculated using the formula:
\[ F = m \cdot g \cdot \cos(\Theta) \]
where \( m = 950 \) kg is the mass of the car, \( g = 9.8 \) m/s² is the acceleration due to gravity, and \( \Theta = 30.0^\circ \) is the angle of the incline. Since the friction is negligible, we ignore any resistive forces. By understanding and applying this principle, students can tackle a wide range of problems involving constant speed force calculations.
Energy Transfer Calculation
Energy transfer is the process of energy moving from one body or system to another. In physics problems related to mechanics, the term 'work' is often used to describe the energy transferred when a force causes an object to move. The work done by the winch motor in moving the ore car along the track is an excellent example of energy transfer through work.

To calculate the energy transferred, we use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. However, since the ore car travels part of the distance at constant speed, its kinetic energy does not change during this phase, and the work relates to overcoming the gravitational component only. The formula for this calculation is: \[ E = F \cdot d \] where \( F \) is the force calculated previously and \( d = 1250 \) m is the distance the car travels. This calculation shows the total energy the motor must supply to move the car along the track. It's crucial for students to understand that energy transfer often involves converting one form of energy into another, in this case, electrical energy from the motor to mechanical energy to move the car.
Power Calculation in Physics
Power in physics is defined as the rate at which work is done or energy is transferred. It is a crucial concept when discussing the performance of engines, motors, and various machines. In the context of the ore car being pulled up the mine shaft, the power that the winch motor must provide correlates to how quickly it can do the work necessary to move the car at a constant speed.

The formula to calculate power when the car is at constant speed is: \[ P = F \cdot v \] where \( F \) is the force required to maintain constant speed and \( v = 2.20 \) m/s is the velocity of the car. Understanding power calculations helps students predict the capability needed for machines to perform specific tasks within a given time. It's important to note that the maximum power, which occurs during the initial acceleration of the car, will be higher because it includes the force required to increase the car's velocity from rest.
Mechanics in Physics
Mechanics is the branch of physics that deals with the behaviour of physical bodies when subjected to forces or displacements. It is divided into sub-disciplines like kinematics, dynamics, statics, and fluid mechanics. The exercise involving the ore car incorporates concepts from several of these areas – particularly dynamics, which involves the forces causing motion.

In analyzing the car's motion, mechanics principles such as Newton’s Laws of Motion are applied to predict and explain the movement. By comprehending these fundamental mechanics principles, students can decipher a variety of real-world physics problems. In this case, mechanics provides the groundwork for understanding how forces and energy interact as the winch motor pulls the ore car, leading to insights into how systems conserve energy, the role of forces in motion, and ultimately, the practicality of machines and mechanisms in our everyday lives.

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Most popular questions from this chapter

A truck travels uphill with constant velocity on a highway with a \(7.0^{\circ}\) slope. A \(50-\mathrm{kg}\) package sits on the floor of the back of the truck and does not slide, due to a static frictional force. During an interval in which the truck travels \(340 \mathrm{~m}\), (a) what is the net work done on the package? What is the work done on the package by (b) the force of gravity, (c) the normal force, and (d) the friction force?

GP (a) A block with a mass \(m\) is pulled along a horizontal surface for a distance \(x\) by a constant force \(\overrightarrow{\mathbf{F}}\) at an angle \(\theta\) with respect to the horizontal. The coefficient of kinetic friction between block and table is \(\mu_{k}\). Is the force exerted by friction equal to \(\mu_{k}\) mg? If not, what is the force exerted by friction? (b) How much work is done by the friction force and by \(\overrightarrow{\mathbf{F}}\) ? (Don't forget the signs.) (c) Identify all the forces that do no work on the block. (d) Let \(m=2.00 \mathrm{~kg}, x=4.00 \mathrm{~m}, \theta=37.0^{\circ}\), \(F=15.0 \mathrm{~N}\), and \(\mu_{k}=0.400\), and find the answers to parts (a) and (b).

M A 2 100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls \(5.00 \mathrm{~m}\) before coming into contact with the top of the beam, and it drives the beam \(12.0 \mathrm{~cm}\) farther into the ground as it comes to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.

When a \(2.50-\mathrm{kg}\) object is hung vertically on a certain light spring described by Hooke's law, the spring stretches \(2.76 \mathrm{~cm}\). (a) What is the force constant of the spring? (b) If the \(2.50-\mathrm{kg}\) object is removed, how far will the spring stretch if a \(1.25-\mathrm{kg}\) block is hung on it? (c) How much work must an external agent do to stretch the same spring \(8.00 \mathrm{~cm}\) from its unstretched position?

The force acting on an object is given by \(F_{x}=\) \((8 x-16) \mathrm{N}\), where \(x\) is in meters. (a) Make a plot of this force versus \(x\) from \(x=0\) to \(x=3.00 \mathrm{~m}\). (b) From your graph, find the net work done by the force as the object moves from \(x=0\) to \(x=3.00 \mathrm{~m}\).

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