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A \(1.50 \times 10^{3}-\mathrm{kg}\) car starts from rest and accelerates uniformly to \(18.0 \mathrm{~m} / \mathrm{s}\) in \(12.0 \mathrm{~s}\). Assume that air resistance remains constant at \(400 \mathrm{~N}\) during this time. Find (a) the average power developed by the engine and (b) the instantaneous power output of the engine at \(t=12.0 \mathrm{~s}\), just before the car stops accelerating.

Short Answer

Expert verified
The average power developed by the engine is 16,650 Watts and the instantaneous power output of the engine at \(t = 12.0 s\) is 33,300 Watts.

Step by step solution

01

Calculation of the acceleration of the car

The acceleration of the car can be calculated using the equation: \(a = \frac{v_f - v_i}{t}\), where \(a\) represents acceleration, \(v_f\) represents final velocity, \(v_i\) represents initial velocity, and \(t\) represents time. Substituting the given values, we have \(a = \frac{18.0 m/s - 0 m/s}{12.0 s} = 1.5 m/s^2\)
02

Calculation of the net force acting on the car

The net force acting on the car can be obtained by using the equation: \(F_{net} = ma - F_{air}\), where \(F_{net}\) is the net force, \(m\) is the mass of the car, \(a\) is the acceleration and \(F_{air}\) is the air resistance. Substituting the known values, we find \(F_{net} = 1.50 × 10^{3} kg * 1.5 m/s^2 - 400 N = 1850 N\)
03

Calculation of the work done by the car

To find the work done by the net force over the given distance, we use the equation: \(W = F_{net} * d\), where \(W\) is the work done, \(F_{net}\) is the net force and \(d\) is the distance covered. Since it's not given, we find the distance traveled during the time period using the equation \(d = v_i*t + 0.5*a*t^2\), where \(d\) is the distance, \(v_i\) is the initial velocity, \(t\) is time and \(a\) is acceleration. Substituting values, \(d = 0 m/s * 12.0 s + 0.5 * 1.5 m/s^2 * (12.0 s)^2 = 108 m\), then \(W = 1850 N * 108 m = 199800 J\)
04

Calculation of the average power developed by the engine

The average power can be calculated using the formula: \(P_{avg} = \frac{W}{t}\), where \(P_{avg}\) is the average power, \(W\) is the work done and \(t\) is the time period. Substituting the values, we get \(P_{avg} = \frac{199800 J}{12.0 s} = 16650 W\)
05

Calculation of the instantaneous power

The instantaneous power at a given point of time can be calculated using the formula: \(P_{inst} = F_{net} * v\), where \(P_{inst}\) is the instantaneous power, \(F_{net}\) is the net force and \(v\) is the speed at that time. Substituting the values, we have \(P_{inst} = 1850 N * 18.0 m/s = 33300 W\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniformly Accelerated Motion
Uniformly accelerated motion refers to a scenario where an object's velocity changes at a constant rate. Here, the acceleration is unchanging over time. In our car example, the vehicle starts from rest and reaches a velocity of 18.0 m/s over a 12.0 s period.

To calculate the acceleration, the formula used is:
\(a = \frac{v_f - v_i}{t}\)
where \(a\) is the acceleration, \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time. For the car, as it starts from rest (\(v_i = 0\)), the calculation simplifies to: \(a = \frac{18.0\ m/s}{12.0\ s} = 1.5\ m/s^2\). This acceleration is uniform, meaning the car's velocity increases by 1.5 m/s every second.
Net Force Calculation
The net force is the sum of all forces acting upon an object. It's vital for determining an object's acceleration according to Newton's second law, which states \(F_{net} = ma\), where \(F_{net}\) is the net force, \(m\) is the mass, and \(a\) is the acceleration.

For the car in our problem, air resistance, which works in the opposite direction of the car's motion, acts as a counteracting force and must be subtracted from the total force provided by the car's engine. The net force calculation can therefore be updated to include this resistant force: \(F_{net} = ma - F_{air}\).

Substituting in the mass of the car, its calculated acceleration, and the constant air resistance, we obtained the net force acting on the car to propel it forward.
Work-Energy Principle
The work-energy principle is a foundational concept in physics, expressing the relationship between the work done on an object and its energy. Work is defined as a force applied over a distance and is given by the formula \(W = F_{net} * d\), where \(W\) is the work, \(F_{net}\) is the net force, and \(d\) is the distance moved in the direction of the force.

In the car example, we needed to first find how far the car traveled during the acceleration period. Using the motion equation \(d = v_i*t + 0.5*a*t^2\), and then multiplying the net force by this distance to find the total work done. This concept links the forces acting on the car and the car's displacement to describe how much energy was transferred to accelerate the car.
Power in Mechanics
Power in mechanics is a measure of how quickly work is done or energy is transmitted. The standard SI unit for power is the watt (W). Average power and instantaneous power are two key concepts here.

Average power \(P_{avg}\) is the total work divided by the time over which the work was performed: \(P_{avg} = \frac{W}{t}\). For our car, we calculated this by dividing the total work by the 12.0 s period. In contrast, instantaneous power \(P_{inst}\) is measured at a specific moment in time and can be found by multiplying the net force by the instantaneous velocity at that time: \(P_{inst} = F_{net} * v\).

In the final step of our exercise, we found the instantaneous power of the car at 12.0 s by using the net force at that moment and the car's velocity, providing us with the power output just as the car finished accelerating.

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