/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 BIO A flea is able to jump about... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

BIO A flea is able to jump about \(0.5 \mathrm{~m}\). It has been said that if a flea were as big as a human, it would be able to jump over a 100 -story building! When an animal jumps, it converts work done in contracting muscles into gravitational potential energy (with some steps in between). The maximum force exerted by a muscle is proportional to its cross-sectional area, and the work done by the muscle is this force times the length of contraction. If we magnified a flea by a factor of 1000 , the cross section of its muscle would increase by \(1000^{2}\) and the length of contraction would increase by 1000 . How high would this "superflea" be able to jump? (Don't forget that the mass of the "superflea" increases as well.)

Short Answer

Expert verified
The 'superflea' would still be able to jump about 0.5 m.

Step by step solution

01

Understand force exerted

The total force that can be exerted by a muscle is proportional to its cross-sectional area. If we magnify the flea by a factor of 1000, the cross section of its muscle would increase by \(1000^2\). Therefore, the force magnifier would be \(1000^2 = 10^6\).
02

Understand work done

The work done by a muscle is force times distance. Given that the length of contraction increases 1000 times for the 'superflea', this would increase the work done by a factor of 1000. Combining with the increase in force from step 1, the total work magnifier would be \(10^6 * 1000 = 10^9\).
03

Understand the mass change

The magnification would also increase the mass of the flea, as the volume (and therefore mass) increases with the cube of the length magnifier. This means the mass of the 'superflea' would be \(1000^3 = 10^9\) times the mass of the normal flea.
04

Apply the energy conservation law

The work done in contracting muscles becomes gravitational potential energy which is calculated by the formula \(PE = mgh\), where \(m\) is mass, \(g\) is the acceleration due to gravity, and \(h\) is height. For the 'superflea', the work transformed to potential energy would be \(10^9\) times more, so the height it could reach would be \(10^9\) times higher, provided the mass is maintained.
05

Adjust for increased mass

However, the mass of the 'superflea' is also \(10^9\) times more than the mass of the normal flea. The increased mass would make it more difficult to jump high (as more energy is required to lift a larger mass). Therefore, the effect of the increased mass of the 'superflea' would cancel out the ability to jump higher due to increased work done.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Muscle Dynamics
Muscle dynamics is a fascinating topic that revolves around how muscles generate force and movement. When animals move, they convert energy from their muscles into motion.
One key principle in understanding muscles is the relationship between force and the muscle's cross-sectional area.
  • The force exerted by a muscle increases proportionally with the cross-sectional area of the muscle. This means larger muscles can exert more force.
  • Muscles work by contracting, and the force they generate is a direct outcome of these contractions.
  • In the case of our flea example, magnifying the flea by a factor of 1000 increases the muscle's cross-section by a factor of 1,000,000 (since the area scales by the square of the magnification factor).
This massive increase in cross-section allows the flea's muscles to generate prodigious amounts of force. However, understanding muscle dynamics also means recognizing the limits and energy costs associated with these forces.
Gravitational Potential Energy
Gravitational potential energy is the energy an object has due to its position in a gravitational field, like Earth’s. When an animal jumps, its muscles do work to elevate its body against gravity, forming potential energy.
  • The fundamental formula is \(PE = mgh\), where \(m\) is mass, \(g\) is the acceleration due to gravity, and \(h\) is the height.
  • For the flea, the work done in muscle contraction is converted into gravitational potential energy, allowing it to jump.
  • Even if the work done by muscles is vastly increased, as in the superflea scenario, the jump height will not change since its mass also increases proportionally.
The formula and the problem’s context highlight that more energy is required to lift heavier objects. So, even though a superflea could potentially generate greater force, its increased weight negates the benefits concerning how high it can jump.
Scaling Laws in Biology
Scaling laws in biology help us understand how physical characteristics of living organisms change with size. These principles are crucial when exploring how larger creatures handle movement and force differently than smaller ones.

Key aspects of scaling include:
  • The cube-square law states that if an organism’s size doubles, its surface area increases by the square, and its volume (and mass) increases by the cube.
  • This principle is evident in the flea scenario. When magnifying the flea by 1000 times, its muscle cross-sectional area, linked to force, grows by \(10^6\), while its volume and mass grow by \(10^9\).
  • These scaling laws explain why a human-sized flea would not have super jumping abilities, as its mass increase would balance any potential force benefits.
Understanding these scaling laws reinforces why biologists need to consider evolutionary adaptations and biomechanical constraints when assessing animal abilities, especially in exaggerated hypothetical scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

QIC The masses of the javelin, discus, and shot are \(0.80 \mathrm{~kg}, 2.0 \mathrm{~kg}\), and \(7.2 \mathrm{~kg}\), respectively, and record throws in the corresponding track events are about \(98 \mathrm{~m}, 74 \mathrm{~m}\), and \(23 \mathrm{~m}\), respectively. Neglecting air resistance, (a) calculate the minimum initial kinetic energies that would produce these throws, and (b) estimate the average force exerted on each object during the throw, assuming the force acts over a distance of \(2.0 \mathrm{~m}\). (c) Do your results suggest that air resistance is an important factor?

The force acting on an object is given by \(F_{x}=\) \((8 x-16) \mathrm{N}\), where \(x\) is in meters. (a) Make a plot of this force versus \(x\) from \(x=0\) to \(x=3.00 \mathrm{~m}\). (b) From your graph, find the net work done by the force as the object moves from \(x=0\) to \(x=3.00 \mathrm{~m}\).

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of \(4.0 \mathrm{~m} / \mathrm{s}\) up a \(20^{\circ}\) inclined track. The combined mass of monkey and sled is \(20 \mathrm{~kg}\), and the coefficient of kinetic friction between sled and incline is \(0.20\). How far up the incline do the monkey and sled move?

A \(2.1 \times 10^{3}-\mathrm{kg}\) car starts from rest at the top of a \(5.0\)-m-long driveway that is inclined at \(20^{\circ}\) with the horizontal. If an average friction force of \(4.0 \times 10^{5} \mathrm{~N}\) impedes the motion, find the speed of the car at the bottom of the driveway.

Tarzan swings on a \(30.0\)-m-long vine initially inclined at an angle of \(37.0^{\circ}\) with the vertical. What is his speed at the bottom of the swing (a) if he starts from rest? (b) If he pushes off with a speed of \(4.00 \mathrm{~m} / \mathrm{s}\) ?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.