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In 1990 Walter Arfeuille of Belgium lifted a \(281.5-\mathrm{kg}\) object through a distance of \(17.1 \mathrm{~cm}\) using only his teeth. (a) How much work did Arfeuille do on the object? (b) What magnitude force did he exert on the object during the lift, assuming the force was constant?

Short Answer

Expert verified
The work done by Walter Arfeuille on the object is approximately 472 Joules and the force he exerted during the lift, assuming the force was constant, was approximately 2758.7 N.

Step by step solution

01

Calculate Work

The work done (W) can be calculated using the formula: \( W = F \cdot d \), where F is the force and d is the distance. Given that the distance (d) is 17.1 cm, which is 0.171 m (since we need to convert cm to meters to match with SI unit of force), we need to first find the force (F). However, given that the object is lifted vertically, the force is equal to the weight of the object. The weight (force due to gravity) of an object is calculated using the formula: \( F = m \cdot g \), where m is the mass of the object and g is the acceleration due to gravity (9.8 m/s²). The mass m is given as 281.5 kg. So, the force F is \( F = 281.5 \mathrm{kg} \cdot 9.8 \mathrm{m/s^{2}} = 2758.7 \mathrm{N} \). Now we can calculate the work done: \( W = 2758.7 \mathrm{N} \cdot 0.171 \mathrm{m} = 471.83 \mathrm{J} \). Thus, Walter Arfeuille did approximately 472 Joules of work on the object.
02

Calculate Force

The force exerted is determined by rearranging the formula for work: \( F = W / d \), where W is work and d is distance. However, since we've determined in Step 1 that the force equals to weight which was already calculated as 2758.7N, it has been found that the force he exerted during the lift, assuming it was constant, was approximately 2758.7N. So there's nothing to calculate in this step, but it's included for completeness.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work-Energy Principle
The concept of work in physics is closely linked to energy. When we talk about the work-energy principle, we're referring to the idea that work done on an object results in a change in its energy. In simple terms, it's the work done against a force to cause a displacement.

In the context of the exercise, Walter Arfeuille performing the act of lifting an object with his teeth is a clear demonstration of this principle. To lift the object, he must do work against the gravitational force pulling the object towards Earth. This work is converted into potential energy of the object at its new height.

Here's a key point: the amount of work done is directly proportional to the force applied and the distance over which that force is applied. There's a helpful equation that captures this relationship: \( W = F \times d \), where \( W \) is the work done, \( F \) is the force, and \( d \) is the distance moved by the object in the direction of the force.
Force Calculation
Understanding how to calculate force is essential in physics. For the force calculation, we often use Newton’s second law of motion, which states that the force applied on an object is equal to the mass of the object multiplied by its acceleration (\( F = m \times a \)).

In Arfeuille's case, the acceleration due to gravity (\( g = 9.8 \text{ m/s}^2 \)), plays a critical role because it determines the force with which Earth attracts the object - in this case, through Arfeuille's teeth! The formula we use here, taking gravity into account, is \( F = m \times g \), where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity.
SI Units Conversion
Another fundamental aspect of physics is using consistent units, which enables scientists and engineers to communicate with precision. The International System of Units (SI) is widely adopted around the world for this purpose.

In the exercise, the conversion of units is a crucial step before we can calculate work. The distance measurement initially provided in centimeters must be converted to meters, the SI unit for distance. This is because work, in Joules, is calculated using Newtons for force (the SI unit for force) and meters for distance.

To convert from centimeters to meters, we divide by 100 (since 100 cm equals 1 m). Hence, a distance of \( 17.1 \text{ cm} \) becomes \( 0.171 \text{ m} \). Paying attention to this conversion detail is vital for accurate physics calculations.
Acceleration Due to Gravity
The acceleration due to gravity is a constant that measures how quickly objects increase their speed as they fall towards Earth. It's denoted as \( g \) and is approximately \( 9.8 \text{ m/s}^2 \) near Earth’s surface.

This acceleration is a crucial component when computing forces that involve gravity, such as the weight of an object. Every mass experiences this force which is particularly evident in the exercise scenario. Arfeuille's lifting force had to match the downward gravitational force to lift the object.

Remembering that gravity exerts the same acceleration on all objects regardless of their mass allows us to calculate the force with which any object is attracted towards Earth. The understanding of this constant is not only a key to solving many physics problems but also to comprehending how objects interact on a global scale.

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Most popular questions from this chapter

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