/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A block of mass \(m=\) \(5.8 \ma... [FREE SOLUTION] | 91Ó°ÊÓ

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A block of mass \(m=\) \(5.8 \mathrm{~kg}\) is pulled up a \(\theta=\) \(25^{\circ}\) incline as in Figure P4.30 with a force of magnitude \(F=32 \mathrm{~N}\). (a) Find the acceleration of the block if the incline is frictionless. (b) Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is \(0.10\).

Short Answer

Expert verified
The acceleration of the block without friction is calculated by plugging the known values into \(a = (F - mg\sin\theta)/m\). In the presence of friction, the acceleration is found by first calculating the frictional force and then using \(a = (F - f_k - mg\sin\theta) / m\) to find the final answer.

Step by step solution

01

Find the parallel and perpendicular forces in the scenario without friction

First identify the forces acting on the block. These will be the gravitational force \(mg\), the normal force \(N\), and the pulling force \(F\). The angle of the incline \(\theta\) affects how these forces act on the block. The force due to gravity will have a component parallel to the incline (\(mg\sin\theta\)) and a component perpendicular to the incline (\(mg\cos\theta\)). The normal force is equal to the perpendicular component of the gravitational force (\(N=mg\cos\theta\)). The net force parallel to the incline causing the block to move is the force applied minus the parallel component of the gravitational force (\(F-mg\sin\theta\)).
02

Apply Newton's second law to find acceleration without friction

Newton's second law states that the force acting on an object is equal to its mass times its acceleration (\(F = ma\)). We can rearrange this formula to solve for acceleration (\(a = F/m\)). In this case, the net force acting on the block is the difference between the applied force and the parallel component of gravity, thus the acceleration of the block is given by \(a = (F - mg\sin\theta) / m\). Plug the given values into the equation to get the acceleration without friction.
03

Determine the kinetic friction force

In the second part of the question, a frictional force is introduced. The kinetic friction force can be calculated using the formula \(f_k = \mu_k N\), where \(\mu_k\) is the coefficient of kinetic friction, and \(N\) is the normal force which we already calculated. When we have the force due to friction, it needs to be subtracted from the force applied to find the net force acting on the block (\(F - f_k - mg\sin\theta\)).
04

Find the acceleration with friction

Again apply Newton's second law (\(F = ma\)). The acceleration in the presence of friction is given by \(a = (F - f_k - mg\sin\theta) / m\). Plug in the calculated and given values into the formula to find the acceleration of the block with friction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is a force that opposes the motion of an object sliding over a surface. It comes into play when the object is already in motion. This force acts opposite to the direction of motion, reducing the object's acceleration. The magnitude of kinetic friction can be calculated using the formula \( f_k = \mu_k N \), where \( \mu_k \) is the coefficient of kinetic friction, and \( N \) is the normal force acting perpendicular to the surface.
  • The coefficient of kinetic friction is a measure of how "grippy" two surfaces are when sliding past each other.
  • Normal force is typically equal to the perpendicular component of the object's weight on a surface, especially when the surface is inclined.
In the given problem, kinetic friction is significant because it alters the acceleration of the block as it moves up the incline. When you compute the net force, you must deduct the kinetic friction force from the applied force to get an accurate measure of the effective force inducing acceleration.
Inclined Plane
An inclined plane is a flat surface tilted at an angle to the horizontal. When an object is placed on an incline, gravity causes a split in the forces acting on the object. One component of gravity runs parallel to the surface, which affects the object's movement, and one is perpendicular, impacting the normal force.
  • The angle \( \theta \) of the inclined plane affects how much of the gravitational force components are parallel and perpendicular.
  • The steeper the angle, the larger the parallel component of gravity, increasing the likelihood of the object sliding.
Studying inclined planes helps in understanding how forces split and act differently based on orientation. This concept is fundamental when dealing with real-world physics problems, such as sledging down a hill or moving furniture up a ramp.
Gravitational Force
Gravitational force is the force of attraction between two masses, usually considered between Earth and objects on its surface. It is denoted as \( mg \), where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity (\( g \approx 9.8 \text{ m/s}^2 \) on Earth's surface).
  • When on an incline, gravity splits into two components: parallel and perpendicular to the surface.
  • The gravitational force parallel to the incline is \( mg \sin\theta \), which tries to pull the object down along the incline.
  • The perpendicular component, \( mg \cos\theta \), acts against the inclined surface, contributing to the normal force.
Understanding gravitational force is crucial because it is a primary factor that determines the motion of objects in our everyday life. Its effects are clearly observable when dealing with inclined planes, as it dictates how objects accelerate down the slope.

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Most popular questions from this chapter

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