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The force exerted by the wind on the sails of a sailboat is \(390 \mathrm{~N}\) north. The water exerts a force of \(180 \mathrm{~N}\) east. If the boat (including its crew) has a mass of \(270 \mathrm{~kg}\), what are the magnitude and direction of its acceleration?

Short Answer

Expert verified
The magnitude of the acceleration is approximately \(2.19 \, \mathrm{ms}^{-2}\) and the direction is \(24.6^\circ\) east of north.

Step by step solution

01

Determine the Resultant Force

The resultant force acting on the ship can be calculated by considering each force as a vector. The force due to the wind is pointing towards North (\(F_{wind} = 390 N\)), whereas the force due to the water is pointing towards the East (\(F_{water} = 180 N\)). These forces act at right angles to each other thus the magnitude of the resultant force (\(F_{R}\)) can be found by using Pythagoras' theorem: \( F_{R} = \sqrt{F_{wind}^2 + F_{water}^2} = \sqrt{390^2 + 180^2} = \sqrt{210,600}\).
02

Total Acceleration

The acceleration (\(a\)) of the boat can be found by using Newton's second law, which is stated as \( F = ma \). Rearranging for \( a \), we have \( a = \frac{F}{m} \). We plug in the values of \( F_{R} \) and the given mass into this equation to find the acceleration. \( a = \frac{\sqrt{210,600}}{270} \).
03

Direction of Acceleration

The direction of the acceleration can be found by determining the angle east of north. This can be calculated by finding the angle \( \theta \) using the equation \( \theta = \tan^{-1}(\frac{F_{water}}{F_{wind}}) \). Substituting the known values gives \( \theta = \tan^{-1}(\frac{180}{390}) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resultant Force Calculation
Understanding the concept of resultant force is crucial when analyzing the motion of objects influenced by multiple forces. A resultant force is effectively the single force that represents the vector sum of all the forces acting on an object, defining the net force that dictates the object's acceleration. In the provided exercise, the sailboat experiences two perpendicular forces: a wind force of 390 N north and water resistance of 180 N east.

To find the magnitude of the resultant force, we use Pythagoras' theorem, which is applicable here since the forces are at a right angle to each other. The equation for the resultant force (\(F_R\)) becomes: \[ F_{R} = \( \( \( \(F{\_wind}^{2} + F{\_water}^{2} \( \)\)\)\) \) = \( \( \( \( \sqrt{390^{2} + 180^{2}} \( \)\)\)\) \) = \( \( \( \( \sqrt{210,600} \( \)\)\)\) \)\]Making sense of this calculation is key to predicting the boat's movement.
Newton's Second Law of Motion
At the heart of motion analysis is Newton's second law of motion, which provides a relationship between the forces acting on an object, its mass, and the resulting acceleration. It is succinctly expressed in the equation \( F = ma \) where \( F \) represents the net force acting on the object, \( m \) is the mass of the object, and \( a \) is the acceleration.

Applying this law to the exercise, once we have the magnitude of the resultant force, we determine the acceleration of the boat by rearranging the equation to solve for \( a \) — \( a = \frac{F}{m} \). Plugging in the values from the resultant force and the boat's mass, we can find out how fast the boat will accelerate in response to the combined forces of wind and water.
Vector Addition in Physics
Vectors are mathematical representations of quantities that have both a magnitude and a direction. In physics, vector addition is commonly used to combine multiple forces acting on an object to find a single resultant force. Since forces are vector quantities, they follow the rules of vector addition.

For instance, if two forces are perpendicular, as in the case of the sailboat, their vector addition is akin to the sides and hypotenuse of a right triangle. Therefore, to obtain the direction of the resultant force, we use trigonometry—specifically the tangent function—which relates the sides of a right triangle to its angles. The angle \( \theta \) east of north that gives us the direction of the total acceleration can be found using the equation \( \theta = \tan^{-1}(\frac{F_{water}}{F_{wind}}) \). The calculated angle helps us understand not only how fast the boat is accelerating but in what direction it will travel.

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Most popular questions from this chapter

A 72-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of \(1.2 \mathrm{~m} / \mathrm{s}\) in \(0.80 \mathrm{~s}\). The elevator travels with this constant speed for \(5.0 \mathrm{~s}\), undergoes a uniform negative acceleration for \(1.5 \mathrm{~s}\), and then comes to rest. What does the spring scale register (a) before the elevator starts to move? (b) During the first \(0.80 \mathrm{~s}\) of the elevator's ascent? (c) While the elevator is traveling at constant speed? (d) During the elevator's negative acceleration?

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